Category: Class 5

Students can download 5th Maths Term 2 Chapter 5 Interconcept InText Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 2 Chapter 5 Interconcept InText Questions

Activity (Text Book Page No.41)

Question 1.
Write distance, bus fares and travel time from your town to the nearest cities:

Distance, Time and money are interrelated in our daily life situations. Can you discuss and complete the table given below?

Answer:

Question 2.
Distances are given below from Chennai to Kanyakumari

City	Distance [KM]
Chennai	0 km
Tambaram	35 km
Tindivanam	128 km
Villupuram	172 km
Trichy	332 km
Madurai	462 km
Virudunagar	520 km
Tirunelveli	624 km
Kanya Kumari	707 km

Complete the following:

1. The distance between Chennai to Tindivanam ______
Answer:
128 km

2. The distance between Chennai to Villupuram ______
Answer:
172 km

3. The distance between Chennai to Trichy ______
Answer:
332 km

4. The distance between Trichy to Madurai ______
Answer:
462 – 332 = 130 km

5. The distance between Madurai to Tirunelveli ______
Answer:
624 – 462 = 162 km

6. The distance between Chennai to Kanyakumari ______
Answer:
707 km

7. The distance between Trichy to Kanyakumari ______
Answer:
707 – 332 = 375 km

8. The distance between Tindivanam to Tirunelveli ______
Answer:
624 – 128 = 496 km

9. The distance between Chennai to Madurai _____
Answer:
462 km

10. Which is the longest distance? Chennai to Trichy/Chennai to Madurai? ______
Answer:
Chennai to Madurai

Activity (Text Book Page No.43)

Question 1.
The distance between planets and sun

Planets	Distance from sun (KM)
Mercury	57909175
Venus	108200000
Earth	149600011
Mars	227940000
Jupiter	778333000
Saturn	1429400000
Uranus	2870990000
Neptune	4504300000

Answer the following from the given table:

1.The distance between Earth and Sun is _________ .
Answer:
149600011

2. _________ Planet is in the longest distance from the sun.
Answer:
Neptune

3. The Nearest Planet to Sun is _________ .
Answer:
Mercury

4. Arrange the planets in ascending order depending upon the Planets distance from the sun.
Answer:

• Mercury
• Venus
• Earth
• Mars
• Jupiter
• Saturn
• Uranus
• Neptune

5. Arrange the planets in descending order depending upon the Planets distance from the sun.
Answer:

• Neptune
• Uranus
• Saturn
• Jupiter
• Mars
• Earth
• Venus
• Mercury

Students can download 5th Maths Term 2 Chapter 5 Interconcept Ex 5.4 Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 2 Chapter 5 Interconcept Ex 5.4

Question 1.
Answer the following
(i) 3 Km 500 m = _______
Answer:
3 Km 500 m = 3 + 500 × \(\frac { 1 }{ 1000 }\)
= 3 + \(\frac { 1 }{ 2 }\) = 3\(\frac { 1 }{ 2 }\) km

(ii) 25 Km 250 m = _______
Answer:
25 Km 250 m = 25 + 250 × \(\frac { 1 }{ 1000 }\)
= 25 + \(\frac { 1 }{ 4 }\) = 25\(\frac { 1 }{ 4 }\) km

(iii) 17 Km 750 m = _______
Answer:
17 Km 750 m = 17 + 750 × \(\frac { 1 }{ 1000 }\)
= 17 + \(\frac { 3 }{ 4 }\) = 17\(\frac { 3 }{ 4 }\) km

(iv) 35 Km 250 m = _______
Answer:
35 Km 250 m = 35 + 250 × \(\frac { 1 }{ 1000 }\)
= 35 + \(\frac { 1 }{ 4 }\) = 35\(\frac { 1 }{ 4 }\) km

(v) 45 Km 750 m = _______
Answer:
45 Km 750 m = 45 + 750 × \(\frac { 1 }{ 1000 }\)
= 45 + \(\frac { 3 }{ 4 }\) = 45\(\frac { 3 }{ 4 }\) km

Question 2.
Convert into Hours: [In fraction]
(i) 10 minutes
Answer:
10 minutes = 10 × \(\frac { 1 }{ 60 }\)
= \(\frac { 1 }{ 6 }\) hours

(ii) 25 minutes
Answer:
25 minutes = 25 × \(\frac { 1 }{ 60 }\)
= \(\frac { 5 }{ 12 }\) hours

(iii) 36 minutes
Answer:
36 minutes = 36 × \(\frac { 1 }{ 60 }\)
= \(\frac { 3 }{ 5 }\) hours

(iv) 48 minutes
Answer:
48 minutes = 48 × \(\frac { 1 }{ 60 }\)
= \(\frac { 4 }{ 5 }\) hours

(v) 50 minutes
Answer:
50 minutes = 50 × \(\frac { 1 }{ 60 }\)
= \(\frac { 5 }{ 6 }\) hours

Question 3.
Convert into minutes:
(i) \(\frac { 5 }{ 6 }\) Hour
Answer:
\(\frac { 5 }{ 6 }\) Hour = \(\frac { 5 }{ 6 }\) × 60
= 50 minutes

(ii) \(\frac { 8 }{ 10 }\) Hour
Answer:
\(\frac { 8 }{ 10 }\) Hour = \(\frac { 8 }{ 10 }\) × 60
= 48 minutes

(iii) \(\frac { 4 }{ 6 }\) Hour
Answer:
\(\frac { 4 }{ 6 }\) Hour = \(\frac { 4 }{ 6 }\) × 60
= 40 minutes

(iv) \(\frac { 5 }{ 10 }\) Hour
Answer:
\(\frac { 5 }{ 10 }\) Hour = \(\frac { 5 }{ 10 }\) × 60
= 30 minutes

(v) \(\frac { 6 }{ 10 }\) Hour
Answer:
\(\frac { 6 }{ 10 }\) Hour = \(\frac { 6 }{ 10 }\) × 60
= 36 minutes

Question 4.
Match the following:

Answer:

Question 5.
Write the \(\frac { 1 }{ 4 }\), \(\frac { 1 }{ 2 }\) and \(\frac { 3 }{ 4 }\) parts of the following
(i) ₹ 200
Answer:
\(\frac { 1 }{ 4 }\) part of ₹ 200 = \(\frac { 1 }{ 4 }\) × 200 = \(\frac { 200 }{ 4 }\) = ₹ 50
\(\frac { 1 }{ 2 }\) part of ₹ 200 = \(\frac { 1 }{ 2 }\) × 200 = \(\frac { 200 }{ 2 }\) = ₹ 100
\(\frac { 3 }{ 4 }\) part of ₹ 200 = \(\frac { 3 }{ 4 }\) × 200 = \(\frac { 600 }{ 4 }\) = ₹ 150

(ii) ₹ 10,000
Answer:
\(\frac { 1 }{ 4 }\) part of ₹ 10,000 = \(\frac { 1 }{ 4 }\) × 10,000 = \(\frac { 10000 }{ 4 }\) = ₹ 2500
\(\frac { 1 }{ 2 }\) part of ₹ 10,000 = \(\frac { 1 }{ 2 }\) × 10,000 = \(\frac { 10000 }{ 2 }\) = ₹ 5000
\(\frac { 3 }{ 4 }\) part of ₹ 10,000 = \(\frac { 3 }{ 4 }\) × 10,000 = \(\frac { 30000 }{ 4 }\) = ₹ 7500

(iii) ₹ 8,000
Answer:
\(\frac { 1 }{ 4 }\) part of ₹ 8,000 = \(\frac { 1 }{ 4 }\) × 8,000 = \(\frac { 8000 }{ 4 }\) = ₹ 2000
\(\frac { 1 }{ 2 }\) part of ₹ 8,000 = \(\frac { 1 }{ 2 }\) × 8,000 = \(\frac { 8000 }{ 2 }\) = ₹ 4000
\(\frac { 3 }{ 4 }\) part of ₹ 8,000 = \(\frac { 3 }{ 4 }\) × 8,000 = \(\frac { 24000 }{ 4 }\) = ₹ 6000

(iv) ₹ 24,000
Answer:
\(\frac { 1 }{ 4 }\) part of ₹ 24,000 = \(\frac { 1 }{ 4 }\) × 24,000 = \(\frac { 24000 }{ 4 }\) = ₹ 6000
\(\frac { 1 }{ 2 }\) part of ₹ 24,000 = \(\frac { 1 }{ 2 }\) × 24,000 = \(\frac { 24000 }{ 2 }\) = ₹ 12000
\(\frac { 3 }{ 4 }\) part of ₹ 24,000 = \(\frac { 3 }{ 4 }\) × 24,000 = \(\frac { 72000 }{ 4 }\) = ₹ 18000

(iv) ₹ 50,000
Answer:
\(\frac { 1 }{ 4 }\) part of ₹ 50,000 = \(\frac { 1 }{ 4 }\) × 50,000 = \(\frac { 50000 }{ 4 }\) = ₹ 12500
\(\frac { 1 }{ 2 }\) part of ₹ 50,000 = \(\frac { 1 }{ 2 }\) × 50,000 = \(\frac { 50000 }{ 2 }\) = ₹ 25000
\(\frac { 3 }{ 4 }\) part of ₹ 50,000 = \(\frac { 3 }{ 4 }\) × 50,000 = \(\frac { 150000 }{ 4 }\) = ₹ 37500

Students can download 5th Maths Term 2 Chapter 5 Interconcept Ex 5.3 Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 2 Chapter 5 Interconcept Ex 5.3

Question 1.
Answer the following

Answer:

Question 2.
Sneha spent ₹ 7 per Km for a trip and she travelled 850km. How much is the total cost of the trip?
Answer:
Cost per kilometer is ₹ 7
Cost for 850 km = 850 × ₹ 7
= ₹ 5950

Question 3.
Prabhu spent ₹ 9 per Km for o trip and he travelled 580km. How much is the total cost of the trip?
Answer:
Cost per kilometer is ₹ 9
Cost for 850 km = 580 × ₹ 9
= ₹ 5220

Students can download 5th Maths Term 2 Chapter 5 Interconcept Ex 5.2 Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 2 Chapter 5 Interconcept Ex 5.2

Question 1.
Answer the following

Answer:

Question 2.
Wilson reached 240 Km at the speed of 60 Km/hour. How muc time did he travelled?
Answer:

Question 3.
Anbarasan travelled 350 Km at the speed of 70 Km/hour. Find the time taken for his travel.
Answer:

Question 4.
Nazar travelled 360 Km at the speed of 90 Km/hour. Find the time taken for his travel.
Answer:

Question 5.
Fathima reached 480 Km at the speed of 120 Km/hour. How much time did she travelled?
Answer:

Students can download 5th Maths Term 2 Chapter 5 Interconcept Ex 5.1 Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 2 Chapter 5 Interconcept Ex 5.1

Question 1.
Answer the following

Answer:

Question 2.
i. Distance covered in 2 hours at the speed of 20 miles/hour:
Answer:
20 × 2 = 40 miles

ii. Distance covered in 4 hours at the speed of 65 miles/hour:
Answer:
65 × 4 = 260 miles

iii. Distance covered in 5 hours at the speed of 48 Km/hour:
Answer:
48 × 5 = 240 km

iv. Distance covered in 6 hours at the speed of 80 Km/hour:
Answer:
80 × 6 = 480 km

v. Distance covered in 3 hours at the speed of 42 Km/hour:
Answer:
42 × 3 = 126 km

Question 3.
If Gopi ran 12 Hours at a speed of 14 Km/Hour, then how much distance did he ran?
Answer:
Distance = Speed × time = 14 × 12 = 168 km
Distance = 168 km

Question 4.
If naja rides motorcycle for 4 Hours at a speed of 30 Km/Hour, then how much distance did he go?
Answer:
Distance = Speed × time = 30 × 4 = 120 km
Distance = 120 km

Students can download 5th Maths Term 2 Chapter 4 Measurements InText Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 2 Chapter 4 Measurements InText Questions

Let us recall (Text Book Page No.24)

Question 1.
10 milligram = ______ centigram
Answer:
10 milligram = 1 centigram

Question 2.
10 centigram = ______ decigram
Answer:
10 centigram = 1 decigram

Question 3.
10 decigram = ______ gram
Answer:
10 decigram = 1 gram

Question 4.
gram = ______ decagram
Answer:
gram = 1 decagram

Question 5.
______ decagram = 1 hectagram
Answer:
10 decagram = 1 hectagram

Question 6.
10 hectagram = ______ kilogram
Answer:
10 hectagram = 1 kilogram

Activity (TextBook Page No. 24 & 25)

Tick the suitable unit to measure the following objects

Answer:

Answer:

Try These (TextBook Page No. 24 & 25)

Convert into grams
Question 1.
2250 mg
Answer:
2250 mg = 2250 ÷ 1000 g
= 2 g 250 mg

Question 2.
5 kg 400 g
Answer:
5 kg 400 g = (5 × 1000) + 400 g
= 5000 + 400 g
= 5400 g

Try These (TextBook Page No. 26)

Convert into kilogram
Question 1.
4000 gram
Answer:
400o g = 4000 ÷ 1000 kg
= 4 kg

Question 2.
7350 gram
Answer:
7350 g = 7350 ÷ 1000 g
= 7 kg 350 g

Question 3.
4750 gram
Answer:
4750 g = 4750 ÷ 1000 g
= 4 kg 750 g

Try These (TextBook Page No. 27)

Find the sum of the following
Question 1.
5 kg 300g + 19 kg 850 g
Answer:

Sum = 25 kg 150 g

Question 2.
15 g 450 mg + 14 g 25 mg + 3 g 700 mg
Answer:

Sum = 33 g 175 mg

Question 3.
18 kg 750 g + 16 kg 400g + 3 kg 500g.
Answer:

Sum = 38 kg 650 g

Try This (TextBook Page No. 28)

Subtract the following
a. 75 kg – 35 kg 4009
Answer:

Difference = 39 kg 600 g

b. 57 kg 750 g – 23 kg 450 g
Answer:

Difference = 34 kg 300 g

c. 975 kg 400 g – 755 kg 550
Answer:

Difference = 219 kg 850 g

Try These (TextBook Page No. 29)

MuItpy the following:
a. 7 kg 350 g × 7
Answer:

7 kg 350 g × 7 = 51 kg 450 g

b. 9 kg 750 g × 3
Answer:

9 kg 750 g × 3 = 29 kg 250 g

c. 45 kg 800 g × 6
Answer:

45 kg 800 g × 6 = 274 kg 800 g

Try This (TextBook Page No. 29)

Divide the following:
a. 7 kg 490 g ÷ 7
Answer:

7 kg 490 g ÷ 7 = 1 kg 70 g

b. 35 kg 650 g ÷ 5
Answer:

35 kg 650 g ÷ 5 = 7 kg 130 g

c. 6 g 240 mg ÷ 4
Answer:

6 g 240 mg ÷ 4 = 1 g 560 mg

d. 150 g 750 mg ÷ 15
Answer:

150 g 750 mg ÷ 15 = 10 g 50 mg

Try This (TextBook Page No. 34)

Convert into millilitre:
a. 5 l 500 ml
Answer:
5 l 500 ml = (5 × 1000) + 500 ml
= 5000 + 500
= 5500 ml

b. 9 l 200 ml
Answer:
9 l 200 ml = (9 × 1000) + 200 ml
= 9000 + 200
= 9200 ml

c. 2 l 300 ml
Answer:
2 l 300 ml = (2 × 1000) + 300 ml
= 2000 + 300
= 2300 ml

Activity (TextBook Page No. 34)

Litre	Millilitre
1. l	1000 ml
2. l	2000 ml
3. l
4. l
5. l 300 ml	5300 ml
6. l
7. l
8. l 400 ml
9. l
10. 1 200 ml

Answer:

Litre	Millilitre
1. l	1000 ml
2. l	2000 ml
3. l	3000 ml
4. l	4000 ml
5. l 300 ml	5300 ml
6. l	6000 ml
7. l	7000 ml
8. l 400 ml	8400 ml
9. l	9000 ml
10. 1 200 ml	10200 ml

Try These (TextBook Page No. 35)

Question 1.
4 l 300 ml + 6 l 700 ml
Answer:

Sum = 11 l

Question 2.
7 l 250 ml + 2 l 300 ml
Answer:

Sum = 9 l 550 ml

Question 3.
5 l 500 ml – 4 l 450 ml
Answer:

Difference = 1 l 50 ml

Question 4.
46 l 300 ml – 12 l 550 ml
Answer:

Difference = 33 l 750 ml

Try These (TextBook Page No. 37)

Question 1.
2 l 250 ml × 2
Answer:

2 l 250 ml × 2 = 4 l 500 ml

Question 2.
18 l 240 ml ÷ 6
Answer:

18 l 240 ml ÷ 6 = 3 l 40 ml

Students can download 5th Maths Term 2 Chapter 4 Measurements Ex 4.2 Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 2 Chapter 4 Measurements Ex 4.2

Question 1.
Fill in the blanks
(i) ________ is the smallest metric measure of capacity.
Answer:
Milliliter

(ii) _______ is the largest unit of volume and equals ________ litres
Answer:
Kilometer, 1000

(iii) 7 kI 301 = _____l.
Answer:
7030

(iv) 5 l 400 ml = ____ ml.
Answer:
5400

(v) 1300ml = ____ l ____ ml
Answer:
1, 300

Question 2.
Match the following

1. 4500 ml	6 l 500 ml
2. 3250 ml	8 l 200 ml
3. 6500 ml	7 l 50 ml
4. 8200 ml	4 l 500 ml
5. 7050 ml	3 l 250 ml

Answer:

1. 4500 ml	4 l 500 ml
2. 3250 ml	3 l 250 ml
3. 6500 ml	6 l 500 ml
4. 8200 ml	8 l 200 ml
5. 7050 ml	7 l 50 ml

Question 3.
Add and write in litres
(i) 400 l; 50 l; 500 ml
Answer:

sum = 450 l 500 ml

(ii) 3 kl; 400 I; 3 ml
Answer:

sum = 3400 l 3 ml

(iii) 1400 ml; 5680 ml; 280 l
Answer:

sum = 287 l 080 ml

Question 4.
Subtract:
(i) 3 kl from 15485 l
Answer:

Difference = 12485 l

(ii) 15 kl from 20 kl
Answer:

Difference = 15 kl

(iii) 345 ml from 5 l
Answer:

Difference = 5 l 655 ml

Question 5.
Multiply the following:
(i) 31200 ml × 8
Answer:

Product = 25 l 600 ml

(ii) 4 I 450 ml × 4
Answer:

Product = 17 l 800 ml

(iii) 51300 ml × 5
Answer:

Product = 26 l 500 ml

(iv) 61700 ml × 6
Answer:

Product = 40 l 200 ml

Question 6.
Divide the following:
(i) 18 l 240 ml ÷ 6
Answer:

18 l 240 ml ÷ 6 = 3 l 40 ml

(ii) 20 l 600 ml ÷ 2
Answer:

20 l 600 ml ÷ 2 = 10 l 300 ml

(iii) 21 l 490 ml ÷ 7
Answer:

21 l 490 ml ÷ 7 = 3 l 70 ml

(iv) 25 l 350 ml ÷ 5
Answer:

25 l 350 ml ÷ 5 = 5 l 70 ml

Question 7.
Kalaiyarasi bought 5 l 500 ml groundnut oil and 750 ml sesame oil. How much oil did she bought in all?
Answer:
Ground nut oil = 5 I 500 ml
Sesame oil = 750 ml
Total = 5 I 500 ml + 750 ml
= 6 l 250 ml

Question 8.
In a fuel station there was 70 l 500 ml of fuel. How much amount of fuel will be left after selling 35 l 700 ml of fuel?
Answer:

Fuel left = 34 l 800 ml

Question 9.
A pot contains 9 l 500 ml of water, how much amount of water will 7 such pots contain?
Answer:
One pot contain = 9 l 500 ml

Total = 66 l 500 ml

Question 10.
25 l 500 ml of milk is filled in 5 milk cans, how much milk is filled in one can?
Answer:
In 5 cans = 25 l 500 ml
1 can = 25 l 500 ml + 5

= 5l 100 ml

Students can download 5th Maths Term 2 Chapter 4 Measurements Ex 4.1 Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 2 Chapter 4 Measurements Ex 4.1

Question 1.
Fill in the blanks.

(i) 7 kg 400 g = ______ g
Answer:
7400

(ii) 5 g 50 mg = ______ mg
Answer:
5050

(iii) 9500 mg = ______ g ______ mg
Answer:
9,500

(iv) 15 kg 350 g = ______ g
Answer:
15350

(v) 6250 g = ______ kg ______ g
Answer:
6,250

Question 2.
Add the following:

(i) 4 kg 250 g + 3 kg 450 g
Answer:

4 kg 250 g + 3 kg 450 g = 7 kg 700 g

(ii) 75g 430 mg + 750 g
Answer:

75g 430 mg + 750 g = 825 g 430 mg

(iii) 97 kg 45 g + 77 kg 450g + 33 kg 250 g
Answer:

97 kg 45 g + 77 kg 450g + 33 kg 250 g = 207 kg 745 g

(iv) 75 kg 400 g + 30 kg 250 g
Answer:

75 kg 400 g + 30 kg 250 g = 105 kg 650 g

Question 3.
Subtract the following:

(i) 40 kg 350 g – 25 kg 200 g
Answer:

40 kg 350 g – 25 kg 200 g = 15 kg 150 g

(ii) 35 kg 850 g – 18 kg 500 g
Answer:

35 kg 850 g – 18 kg 500 g = 17 kg 350 g

(iii) 985 kg 475 g – 275 kg 325 g
Answer:

985 kg 475 g – 275 kg 325 g = 710 kg 150 g

(iv) 700 kg – 300 kg 500 g
Answer:

700 kg – 300 kg 500 g = 399 kg 500 g

Question 4.
Multiply the following:

(i) 4 kg 300 g × 7
Answer:

4 kg 300 g × 7 = 30 kg 100 g

(ii) 17kg 750 g × 8
Answer:

17kg 750 g × 8 = 142 kg

(iii) 25 kg 550 g × 4
Answer:

25 kg 550 g × 4 = 102 kg 200 g

(iv) 72g 350 mg × 5
Answer:

72g 350 mg × 5 = 361 g 750 mg

Question 5.
Divide the following:

(i) 99 kg 99 0g ÷ 3
Answer:

99 kg 99 0g ÷ 3 = 33 kg 330 g

(ii) 147 g 630 mg ÷ 7
Answer:

147 g 630 mg ÷ 7 = 21 g 90 mg

(iii) 550 kg 220 g ÷ 11
Answer:

550 kg 220 g ÷ 11 = 50 kg 20 g

(iv) 484 g 384 mg ÷ 4
Answer:

484 g 384 mg ÷ 4 = 121 g 96 g

Question 6.
What is the total weight of 7 kg 500 g of cashew nut and 3 kg 350 g of pista?
Answer:
cashew nut = 7 kg 500 g
pista = 3 kg 350 g
Total weight = 7 kg 500 g + 3 kg 350 g
= 10 kg 850 g

Question 7.
Vimal had a sack of cotton seeds weighing 50 kg 350 g. He used 7 kg 300 g cotton seeds to feed his cow. How much cotton seed will be remaining after feeding his cow?
Answer:

Remaining cotton seeds = 43 kg 50 g

Question 8.
A glass bottle can contain 25 g 125 mg of medicine, how much medicine can 7 such bottles contain?
Answer:

7 bottles contain = 175 g 875 mg

Question 9.
75 kg 750 g of groundnut seed is filled in five bags, how much groundnut seed can a bag contain?
Answer:
Total = 75 kg 750 g
One bag = 75 kg 750 g ÷ 5

one bag = 15 kg 150 g

Students can download 5th Maths Term 2 Chapter 3 Patterns Additional Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 2 Chapter 3 Patterns Additional Questions

Question 1.
Mention the time in the clock when the angle is

(i) 30°
Answer:

(ii) 120°
Answer:

(iii) 150°
Answer:

Students can download 5th Maths Term 2 Chapter 3 Patterns InText Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 2 Chapter 3 Patterns InText Questions

Activity:1 (Text Book Page No.16)

Continue the pattern as done in first to complete the tile.

Answer:

Answer:

Activity:2 (Text Book Page No.16)

Continue the border stripe.

Answer:

Activity:3 (Text Book Page No.16)

Answer:

Activity:4 (Text Book Page No.22)

Arrange the given words to form a pattern
Depth, called, walked, mice, played, pulled, breadth, rice, length, width, price, voice
_______, _______, _______, _______,
_______, _______, _______, _______,
_______, _______, _______, _______,
Answer:
Depth, breadth, length, width
called, walked, played, pulled
nice, rice, price, voice