Category: Class 5

Students can download 5th Maths Term 2 Chapter 5 Interconcept Ex 5.4 Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 2 Chapter 5 Interconcept Ex 5.4

Question 1.
Answer the following
(i) 3 Km 500 m = _______
Answer:
3 Km 500 m = 3 + 500 × \(\frac { 1 }{ 1000 }\)
= 3 + \(\frac { 1 }{ 2 }\) = 3\(\frac { 1 }{ 2 }\) km

(ii) 25 Km 250 m = _______
Answer:
25 Km 250 m = 25 + 250 × \(\frac { 1 }{ 1000 }\)
= 25 + \(\frac { 1 }{ 4 }\) = 25\(\frac { 1 }{ 4 }\) km

(iii) 17 Km 750 m = _______
Answer:
17 Km 750 m = 17 + 750 × \(\frac { 1 }{ 1000 }\)
= 17 + \(\frac { 3 }{ 4 }\) = 17\(\frac { 3 }{ 4 }\) km

(iv) 35 Km 250 m = _______
Answer:
35 Km 250 m = 35 + 250 × \(\frac { 1 }{ 1000 }\)
= 35 + \(\frac { 1 }{ 4 }\) = 35\(\frac { 1 }{ 4 }\) km

(v) 45 Km 750 m = _______
Answer:
45 Km 750 m = 45 + 750 × \(\frac { 1 }{ 1000 }\)
= 45 + \(\frac { 3 }{ 4 }\) = 45\(\frac { 3 }{ 4 }\) km

Question 2.
Convert into Hours: [In fraction]
(i) 10 minutes
Answer:
10 minutes = 10 × \(\frac { 1 }{ 60 }\)
= \(\frac { 1 }{ 6 }\) hours

(ii) 25 minutes
Answer:
25 minutes = 25 × \(\frac { 1 }{ 60 }\)
= \(\frac { 5 }{ 12 }\) hours

(iii) 36 minutes
Answer:
36 minutes = 36 × \(\frac { 1 }{ 60 }\)
= \(\frac { 3 }{ 5 }\) hours

(iv) 48 minutes
Answer:
48 minutes = 48 × \(\frac { 1 }{ 60 }\)
= \(\frac { 4 }{ 5 }\) hours

(v) 50 minutes
Answer:
50 minutes = 50 × \(\frac { 1 }{ 60 }\)
= \(\frac { 5 }{ 6 }\) hours

Question 3.
Convert into minutes:
(i) \(\frac { 5 }{ 6 }\) Hour
Answer:
\(\frac { 5 }{ 6 }\) Hour = \(\frac { 5 }{ 6 }\) × 60
= 50 minutes

(ii) \(\frac { 8 }{ 10 }\) Hour
Answer:
\(\frac { 8 }{ 10 }\) Hour = \(\frac { 8 }{ 10 }\) × 60
= 48 minutes

(iii) \(\frac { 4 }{ 6 }\) Hour
Answer:
\(\frac { 4 }{ 6 }\) Hour = \(\frac { 4 }{ 6 }\) × 60
= 40 minutes

(iv) \(\frac { 5 }{ 10 }\) Hour
Answer:
\(\frac { 5 }{ 10 }\) Hour = \(\frac { 5 }{ 10 }\) × 60
= 30 minutes

(v) \(\frac { 6 }{ 10 }\) Hour
Answer:
\(\frac { 6 }{ 10 }\) Hour = \(\frac { 6 }{ 10 }\) × 60
= 36 minutes

Question 4.
Match the following:

Answer:

Question 5.
Write the \(\frac { 1 }{ 4 }\), \(\frac { 1 }{ 2 }\) and \(\frac { 3 }{ 4 }\) parts of the following
(i) ₹ 200
Answer:
\(\frac { 1 }{ 4 }\) part of ₹ 200 = \(\frac { 1 }{ 4 }\) × 200 = \(\frac { 200 }{ 4 }\) = ₹ 50
\(\frac { 1 }{ 2 }\) part of ₹ 200 = \(\frac { 1 }{ 2 }\) × 200 = \(\frac { 200 }{ 2 }\) = ₹ 100
\(\frac { 3 }{ 4 }\) part of ₹ 200 = \(\frac { 3 }{ 4 }\) × 200 = \(\frac { 600 }{ 4 }\) = ₹ 150

(ii) ₹ 10,000
Answer:
\(\frac { 1 }{ 4 }\) part of ₹ 10,000 = \(\frac { 1 }{ 4 }\) × 10,000 = \(\frac { 10000 }{ 4 }\) = ₹ 2500
\(\frac { 1 }{ 2 }\) part of ₹ 10,000 = \(\frac { 1 }{ 2 }\) × 10,000 = \(\frac { 10000 }{ 2 }\) = ₹ 5000
\(\frac { 3 }{ 4 }\) part of ₹ 10,000 = \(\frac { 3 }{ 4 }\) × 10,000 = \(\frac { 30000 }{ 4 }\) = ₹ 7500

(iii) ₹ 8,000
Answer:
\(\frac { 1 }{ 4 }\) part of ₹ 8,000 = \(\frac { 1 }{ 4 }\) × 8,000 = \(\frac { 8000 }{ 4 }\) = ₹ 2000
\(\frac { 1 }{ 2 }\) part of ₹ 8,000 = \(\frac { 1 }{ 2 }\) × 8,000 = \(\frac { 8000 }{ 2 }\) = ₹ 4000
\(\frac { 3 }{ 4 }\) part of ₹ 8,000 = \(\frac { 3 }{ 4 }\) × 8,000 = \(\frac { 24000 }{ 4 }\) = ₹ 6000

(iv) ₹ 24,000
Answer:
\(\frac { 1 }{ 4 }\) part of ₹ 24,000 = \(\frac { 1 }{ 4 }\) × 24,000 = \(\frac { 24000 }{ 4 }\) = ₹ 6000
\(\frac { 1 }{ 2 }\) part of ₹ 24,000 = \(\frac { 1 }{ 2 }\) × 24,000 = \(\frac { 24000 }{ 2 }\) = ₹ 12000
\(\frac { 3 }{ 4 }\) part of ₹ 24,000 = \(\frac { 3 }{ 4 }\) × 24,000 = \(\frac { 72000 }{ 4 }\) = ₹ 18000

(iv) ₹ 50,000
Answer:
\(\frac { 1 }{ 4 }\) part of ₹ 50,000 = \(\frac { 1 }{ 4 }\) × 50,000 = \(\frac { 50000 }{ 4 }\) = ₹ 12500
\(\frac { 1 }{ 2 }\) part of ₹ 50,000 = \(\frac { 1 }{ 2 }\) × 50,000 = \(\frac { 50000 }{ 2 }\) = ₹ 25000
\(\frac { 3 }{ 4 }\) part of ₹ 50,000 = \(\frac { 3 }{ 4 }\) × 50,000 = \(\frac { 150000 }{ 4 }\) = ₹ 37500

Students can download 5th Maths Term 2 Chapter 5 Interconcept Ex 5.3 Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 2 Chapter 5 Interconcept Ex 5.3

Question 1.
Answer the following

Answer:

Question 2.
Sneha spent ₹ 7 per Km for a trip and she travelled 850km. How much is the total cost of the trip?
Answer:
Cost per kilometer is ₹ 7
Cost for 850 km = 850 × ₹ 7
= ₹ 5950

Question 3.
Prabhu spent ₹ 9 per Km for o trip and he travelled 580km. How much is the total cost of the trip?
Answer:
Cost per kilometer is ₹ 9
Cost for 850 km = 580 × ₹ 9
= ₹ 5220

Students can download 5th Maths Term 2 Chapter 5 Interconcept Ex 5.2 Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 2 Chapter 5 Interconcept Ex 5.2

Question 1.
Answer the following

Answer:

Question 2.
Wilson reached 240 Km at the speed of 60 Km/hour. How muc time did he travelled?
Answer:

Question 3.
Anbarasan travelled 350 Km at the speed of 70 Km/hour. Find the time taken for his travel.
Answer:

Question 4.
Nazar travelled 360 Km at the speed of 90 Km/hour. Find the time taken for his travel.
Answer:

Question 5.
Fathima reached 480 Km at the speed of 120 Km/hour. How much time did she travelled?
Answer:

Students can download 5th Maths Term 2 Chapter 5 Interconcept Ex 5.1 Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 2 Chapter 5 Interconcept Ex 5.1

Question 1.
Answer the following

Answer:

Question 2.
i. Distance covered in 2 hours at the speed of 20 miles/hour:
Answer:
20 × 2 = 40 miles

ii. Distance covered in 4 hours at the speed of 65 miles/hour:
Answer:
65 × 4 = 260 miles

iii. Distance covered in 5 hours at the speed of 48 Km/hour:
Answer:
48 × 5 = 240 km

iv. Distance covered in 6 hours at the speed of 80 Km/hour:
Answer:
80 × 6 = 480 km

v. Distance covered in 3 hours at the speed of 42 Km/hour:
Answer:
42 × 3 = 126 km

Question 3.
If Gopi ran 12 Hours at a speed of 14 Km/Hour, then how much distance did he ran?
Answer:
Distance = Speed × time = 14 × 12 = 168 km
Distance = 168 km

Question 4.
If naja rides motorcycle for 4 Hours at a speed of 30 Km/Hour, then how much distance did he go?
Answer:
Distance = Speed × time = 30 × 4 = 120 km
Distance = 120 km

Students can download 5th Maths Term 2 Chapter 4 Measurements InText Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 2 Chapter 4 Measurements InText Questions

Let us recall (Text Book Page No.24)

Question 1.
10 milligram = ______ centigram
Answer:
10 milligram = 1 centigram

Question 2.
10 centigram = ______ decigram
Answer:
10 centigram = 1 decigram

Question 3.
10 decigram = ______ gram
Answer:
10 decigram = 1 gram

Question 4.
gram = ______ decagram
Answer:
gram = 1 decagram

Question 5.
______ decagram = 1 hectagram
Answer:
10 decagram = 1 hectagram

Question 6.
10 hectagram = ______ kilogram
Answer:
10 hectagram = 1 kilogram

Activity (TextBook Page No. 24 & 25)

Tick the suitable unit to measure the following objects

Answer:

Answer:

Try These (TextBook Page No. 24 & 25)

Convert into grams
Question 1.
2250 mg
Answer:
2250 mg = 2250 ÷ 1000 g
= 2 g 250 mg

Question 2.
5 kg 400 g
Answer:
5 kg 400 g = (5 × 1000) + 400 g
= 5000 + 400 g
= 5400 g

Try These (TextBook Page No. 26)

Convert into kilogram
Question 1.
4000 gram
Answer:
400o g = 4000 ÷ 1000 kg
= 4 kg

Question 2.
7350 gram
Answer:
7350 g = 7350 ÷ 1000 g
= 7 kg 350 g

Question 3.
4750 gram
Answer:
4750 g = 4750 ÷ 1000 g
= 4 kg 750 g

Try These (TextBook Page No. 27)

Find the sum of the following
Question 1.
5 kg 300g + 19 kg 850 g
Answer:

Sum = 25 kg 150 g

Question 2.
15 g 450 mg + 14 g 25 mg + 3 g 700 mg
Answer:

Sum = 33 g 175 mg

Question 3.
18 kg 750 g + 16 kg 400g + 3 kg 500g.
Answer:

Sum = 38 kg 650 g

Try This (TextBook Page No. 28)

Subtract the following
a. 75 kg – 35 kg 4009
Answer:

Difference = 39 kg 600 g

b. 57 kg 750 g – 23 kg 450 g
Answer:

Difference = 34 kg 300 g

c. 975 kg 400 g – 755 kg 550
Answer:

Difference = 219 kg 850 g

Try These (TextBook Page No. 29)

MuItpy the following:
a. 7 kg 350 g × 7
Answer:

7 kg 350 g × 7 = 51 kg 450 g

b. 9 kg 750 g × 3
Answer:

9 kg 750 g × 3 = 29 kg 250 g

c. 45 kg 800 g × 6
Answer:

45 kg 800 g × 6 = 274 kg 800 g

Try This (TextBook Page No. 29)

Divide the following:
a. 7 kg 490 g ÷ 7
Answer:

7 kg 490 g ÷ 7 = 1 kg 70 g

b. 35 kg 650 g ÷ 5
Answer:

35 kg 650 g ÷ 5 = 7 kg 130 g

c. 6 g 240 mg ÷ 4
Answer:

6 g 240 mg ÷ 4 = 1 g 560 mg

d. 150 g 750 mg ÷ 15
Answer:

150 g 750 mg ÷ 15 = 10 g 50 mg

Try This (TextBook Page No. 34)

Convert into millilitre:
a. 5 l 500 ml
Answer:
5 l 500 ml = (5 × 1000) + 500 ml
= 5000 + 500
= 5500 ml

b. 9 l 200 ml
Answer:
9 l 200 ml = (9 × 1000) + 200 ml
= 9000 + 200
= 9200 ml

c. 2 l 300 ml
Answer:
2 l 300 ml = (2 × 1000) + 300 ml
= 2000 + 300
= 2300 ml

Activity (TextBook Page No. 34)

Answer:

Try These (TextBook Page No. 35)

Question 1.
4 l 300 ml + 6 l 700 ml
Answer:

Sum = 11 l

Question 2.
7 l 250 ml + 2 l 300 ml
Answer:

Sum = 9 l 550 ml

Question 3.
5 l 500 ml – 4 l 450 ml
Answer:

Difference = 1 l 50 ml

Question 4.
46 l 300 ml – 12 l 550 ml
Answer:

Difference = 33 l 750 ml

Try These (TextBook Page No. 37)

Question 1.
2 l 250 ml × 2
Answer:

2 l 250 ml × 2 = 4 l 500 ml

Question 2.
18 l 240 ml ÷ 6
Answer:

18 l 240 ml ÷ 6 = 3 l 40 ml

Students can download 5th Maths Term 2 Chapter 4 Measurements Ex 4.2 Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 2 Chapter 4 Measurements Ex 4.2

Question 1.
Fill in the blanks
(i) ________ is the smallest metric measure of capacity.
Answer:
Milliliter

(ii) _______ is the largest unit of volume and equals ________ litres
Answer:
Kilometer, 1000

(iii) 7 kI 301 = _____l.
Answer:
7030

(iv) 5 l 400 ml = ____ ml.
Answer:
5400

(v) 1300ml = ____ l ____ ml
Answer:
1, 300

Question 2.
Match the following

Answer:

Question 3.
Add and write in litres
(i) 400 l; 50 l; 500 ml
Answer:

sum = 450 l 500 ml

(ii) 3 kl; 400 I; 3 ml
Answer:

sum = 3400 l 3 ml

(iii) 1400 ml; 5680 ml; 280 l
Answer:

sum = 287 l 080 ml

Question 4.
Subtract:
(i) 3 kl from 15485 l
Answer:

Difference = 12485 l

(ii) 15 kl from 20 kl
Answer:

Difference = 15 kl

(iii) 345 ml from 5 l
Answer:

Difference = 5 l 655 ml

Question 5.
Multiply the following:
(i) 31200 ml × 8
Answer:

Product = 25 l 600 ml

(ii) 4 I 450 ml × 4
Answer:

Product = 17 l 800 ml

(iii) 51300 ml × 5
Answer:

Product = 26 l 500 ml

(iv) 61700 ml × 6
Answer:

Product = 40 l 200 ml

Question 6.
Divide the following:
(i) 18 l 240 ml ÷ 6
Answer:

18 l 240 ml ÷ 6 = 3 l 40 ml

(ii) 20 l 600 ml ÷ 2
Answer:

20 l 600 ml ÷ 2 = 10 l 300 ml

(iii) 21 l 490 ml ÷ 7
Answer:

21 l 490 ml ÷ 7 = 3 l 70 ml

(iv) 25 l 350 ml ÷ 5
Answer:

25 l 350 ml ÷ 5 = 5 l 70 ml

Question 7.
Kalaiyarasi bought 5 l 500 ml groundnut oil and 750 ml sesame oil. How much oil did she bought in all?
Answer:
Ground nut oil = 5 I 500 ml
Sesame oil = 750 ml
Total = 5 I 500 ml + 750 ml
= 6 l 250 ml

Question 8.
In a fuel station there was 70 l 500 ml of fuel. How much amount of fuel will be left after selling 35 l 700 ml of fuel?
Answer:

Fuel left = 34 l 800 ml

Question 9.
A pot contains 9 l 500 ml of water, how much amount of water will 7 such pots contain?
Answer:
One pot contain = 9 l 500 ml

Total = 66 l 500 ml

Question 10.
25 l 500 ml of milk is filled in 5 milk cans, how much milk is filled in one can?
Answer:
In 5 cans = 25 l 500 ml
1 can = 25 l 500 ml + 5

= 5l 100 ml

Students can download 5th Maths Term 2 Chapter 4 Measurements Ex 4.1 Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 2 Chapter 4 Measurements Ex 4.1

Question 1.
Fill in the blanks.

(i) 7 kg 400 g = ______ g
Answer:
7400

(ii) 5 g 50 mg = ______ mg
Answer:
5050

(iii) 9500 mg = ______ g ______ mg
Answer:
9,500

(iv) 15 kg 350 g = ______ g
Answer:
15350

(v) 6250 g = ______ kg ______ g
Answer:
6,250

Question 2.
Add the following:

(i) 4 kg 250 g + 3 kg 450 g
Answer:

4 kg 250 g + 3 kg 450 g = 7 kg 700 g

(ii) 75g 430 mg + 750 g
Answer:

75g 430 mg + 750 g = 825 g 430 mg

(iii) 97 kg 45 g + 77 kg 450g + 33 kg 250 g
Answer:

97 kg 45 g + 77 kg 450g + 33 kg 250 g = 207 kg 745 g

(iv) 75 kg 400 g + 30 kg 250 g
Answer:

75 kg 400 g + 30 kg 250 g = 105 kg 650 g

Question 3.
Subtract the following:

(i) 40 kg 350 g – 25 kg 200 g
Answer:

40 kg 350 g – 25 kg 200 g = 15 kg 150 g

(ii) 35 kg 850 g – 18 kg 500 g
Answer:

35 kg 850 g – 18 kg 500 g = 17 kg 350 g

(iii) 985 kg 475 g – 275 kg 325 g
Answer:

985 kg 475 g – 275 kg 325 g = 710 kg 150 g

(iv) 700 kg – 300 kg 500 g
Answer:

700 kg – 300 kg 500 g = 399 kg 500 g

Question 4.
Multiply the following:

(i) 4 kg 300 g × 7
Answer:

4 kg 300 g × 7 = 30 kg 100 g

(ii) 17kg 750 g × 8
Answer:

17kg 750 g × 8 = 142 kg

(iii) 25 kg 550 g × 4
Answer:

25 kg 550 g × 4 = 102 kg 200 g

(iv) 72g 350 mg × 5
Answer:

72g 350 mg × 5 = 361 g 750 mg

Question 5.
Divide the following:

(i) 99 kg 99 0g ÷ 3
Answer:

99 kg 99 0g ÷ 3 = 33 kg 330 g

(ii) 147 g 630 mg ÷ 7
Answer:

147 g 630 mg ÷ 7 = 21 g 90 mg

(iii) 550 kg 220 g ÷ 11
Answer:

550 kg 220 g ÷ 11 = 50 kg 20 g

(iv) 484 g 384 mg ÷ 4
Answer:

484 g 384 mg ÷ 4 = 121 g 96 g

Question 6.
What is the total weight of 7 kg 500 g of cashew nut and 3 kg 350 g of pista?
Answer:
cashew nut = 7 kg 500 g
pista = 3 kg 350 g
Total weight = 7 kg 500 g + 3 kg 350 g
= 10 kg 850 g

Question 7.
Vimal had a sack of cotton seeds weighing 50 kg 350 g. He used 7 kg 300 g cotton seeds to feed his cow. How much cotton seed will be remaining after feeding his cow?
Answer:

Remaining cotton seeds = 43 kg 50 g

Question 8.
A glass bottle can contain 25 g 125 mg of medicine, how much medicine can 7 such bottles contain?
Answer:

7 bottles contain = 175 g 875 mg

Question 9.
75 kg 750 g of groundnut seed is filled in five bags, how much groundnut seed can a bag contain?
Answer:
Total = 75 kg 750 g
One bag = 75 kg 750 g ÷ 5

one bag = 15 kg 150 g

Students can download 5th Maths Term 1 Chapter 6 Information Processing Intext Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 1 Chapter 6 Information Processing Intext Questions

Activity (Text Book Page No.86)

The Fifth standard students were given a task of collecting mathematical shapes in a competition. Team named shakuntaladevi won the competition.

Let us count the shapes collected by the winning team.

Answer:

Activity (Text Book Page No.87)

Total stock of household articles at the end of the month in a mart is given below. Answer the following questions.

Questions and Answers
Question 1.
How many chairs are there in the stock list?
Answer:
9

Question 2.
Name the articles that are lesser in count than the count of cots.
Answer:
Tri footed stools

Question 3.
What is the total number of things in the stock?
Answer:
27

Question 4.
How many tri footed stools were there?
Answer:
3

Question 5.
Mention the articles which is 3 greater than tri footed stool?
Answer:
Table mat

Activity (Text Book Page No.89)

The following information shows the number ofliterates ¡n a village of 200 people. braw a pictograph for that data.

Answer:

Activity (Text Book Page No.91)

The number of Two Wheeler sold in a week ¡n a showroom is given below. Represent the data using tally marks.

Answer:

Activity (Text Book Page No.92)

In a mathematics test, the following marks were obtained by 30 students. Arrange these marks in a table using tally marks.

(a) Find how many students obtained marks equal to or more than 8 ?
(b) How many students obtained marks below 4 ?
Answer:

(a) Find how many students obtained marks equal to or more than 8 ?
Answer:
6 Students

(b) How many students obtained marks below 4 ?
Answer:
9 students

Activity (Text Book Page No.94)

The following information iS collected from 50 students of class V about their grades in exams. Complete the following table from the bar graph.

Answer:

Students can download 5th Maths Term 1 Chapter 6 Information Processing Ex 6.3 Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 1 Chapter 6 Information Processing Ex 6.3

Question 1.
The bar chart represents the number of students using different modes of transport. Observe and answer the following questions.

Questions and Answers
a. Which mode of transport is mostly used by the students?
Answer:
Bicycle.

b. How many students come to school by walking?
Answer:
40 students.

c. Which mode of transport is used the least?
Answer:
car.

d. How many students come to school by Bus?
Answer:
40 students.

Question 2.
The following information shows the grades of science and maths of 30 students of class 5.

Answer the following question.
a. How many students got equal grades in both subjects.
Answer:
Two

b. How many students got a higher grade in science than in maths?
Answer:
Eight

c. Which was the most common grade in science?
Answer:
c.

Question 3.
Mr. binesh collected the information about the rainfall of a particular city in a week from the newspaper and recorded his information in the pictograph.

Answer the following question.
a. On which day, the rain was most?
Answer:
Friday (20 mm).

b. On which day, the rain was least?
Answer:
Sunday & Wednesday (6 mm).

c. How much rain was there on Sunday?
Answer:
6 mm.

d. How much rain was there on Monday?
Answer:
12 mm.

e. Find total rainfall of the city in that week?
Answer:
74 mm.

Question 4.
NeeIa, Mala, Kola and Balo were neighbours. The following dato shows the number of fish in each of their fish tank, brow pictogroph to represent the data and Answer the questions.

Answer the following question.
a. How many fishes did bala have? ________
Answer:
24.

b. Who has 16 fishes? ________
Answer:
Neela.

c. How many fewer fish did Kala have than Mala? ________
Answer:
8.

d. How many fish did Neela and Bala have altogether? ________
Answer:
40 fish.