Category: Class 5

Students can download 5th Maths Term 3 Chapter 5 Money InText Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 3 Chapter 5 Money InText Questions

Try This (Text Book Page No.34)

₹ 1 = 100 Paise
₹ 5 = ______ Paise
775 Paise = ₹ 7.75
425 Paise = ₹ ____
Answer:
₹ 1 = 100 Paise

₹ 5 = ______ Paise
= 500
Hint: ₹ 5 = 5 × 100 paise = 500

775 Paise = ₹ 7.75

425 Paise = ₹ ____
= 4.25
Hint: 425 paise = \(\frac { 425 }{ 100 }\) = ₹ 4.25

Activity (Text Book Page No.37)

Match the big bag with small bag

Answer:

Let’s Think (Text Book Page No.41)

Divide 1000 poise equally for 5 students. How many rupees does each student get?
Answer:
1000 ÷ 5

200 paise = ₹ \(\frac { 200 }{ 100 }\) = ₹ 2
Each student

Activity (Text Book Page No.41)

Find out how many denominations of ₹ 1, ₹ 2, ₹ 5, ₹ 10, ₹ 20, ₹ 50, ₹ 100, ₹ 200, ₹ 500, and ₹ 2,000 are there in ₹ 10,000?

Answer:

Students can download 5th Maths Term 3 Chapter 5 Money Ex 5.2 Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 3 Chapter 5 Money Ex 5.2

Question 1.
Fill in the blanks

(i) ₹ 75 × 5 = ________
Answer:
375

(ii) ₹ 200.25 ÷ 25 = ________
Answer:
₹ 8.01

(iii) ₹ 3500 ÷ 500 = ________
Answer:
₹ 7

(iv) ₹ 15.50 × 100 = ________
Answer:
₹ 1550

Question 2.
Answer the following
(i) ₹ 98725 × 5
Answer:

(ii) ₹ 679.68 × 7
Answer:

(iii) 362.37 × 12
Answer:

(iv) 324.52 ÷ 28
Answer:

(v) 7980 ÷ 8
Answer:

(vi) 397.10 ÷ 11
Answer:

Question 3.
The cost of 1 kg of tomato is ₹ 15. Find the cost of 5 kg of tomatoes?
Answer:
Cost of 1 kg = ₹ 15
Cost of 5 kg = ₹ 15 × 5

Question 4.
The cost of one egg is ₹ 4.50. Find the cost of 20 eggs.
Answer:
Cost of 1 egg = ₹ 4.50
Cost of 20 egg = ₹ 4.50 × 20
= ₹ 90.00

Question 5.
The school management has decided to give a pen for all children participating in the Children’s day celebration. The cost of a pen is
₹ 18. How much money do they need to buy pens for 256 children?
Answer:
Cost of a pen = ₹ 18
Number of children = 256
Money needed = 256 × 18

Question 6.
A fruit seller buys 8 boxes ef grapes for ₹ 2,000. What is the cost of one box?
Answer:
Number of boxes = 8
Cost of 8 boxes = ₹ 2000
Cost of 1 boxes = \(\frac { 2000 }{ 8 }\) = 250

Question 7.
In a sweet stall, the cost of 18 kg of sweets is ₹ 2,520. What is the cost of 1 kg of sweet?
Answer:
Cost of 18 kg of sweets is = ₹ 2,520
Cost of 1 kg = \(\frac { 2520 }{ 18 }\) = ₹ 140

Students can download 5th Maths Term 3 Chapter 6 Fractions 6.1 Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 3 Chapter 6 Fractions 6.1

Question 1.
Write the fraction shown by the shaded parts.
(i)

Answer:
\(\frac { 5 }{ 12 }\)

(ii)

Answer:
\(\frac { 2 }{ 6 }\)

(iii)

Answer:
\(\frac { 3 }{ 9 }\)

Question 2.
Write the fractions for the following and find the numerator and the denominator.
(i) Sheeki got 12 marks out of 20 marks in science.
Answer:
\(\frac { 12 }{ 20 }\); Numerator = 12; Denominator = 20

(ii) Six fruits are rotten out of forty fruits in a basket.
Answer:
\(\frac { 6 }{ 40 }\); Numerator = 6; Denominator = 40

(iii) In a colony of 50 houses. 17 houses are not occupied.
Answer:
\(\frac { 17 }{ 50 }\); Numerator = 17; Denominator = 50

Question 3.
Find out which is greater in the following fractions.
(i) \(\frac { 5 }{ 12 }\) and \(\frac { 7 }{ 12 }\)
(ii) \(\frac { 22 }{ 48 }\) and \(\frac { 17 }{ 48 }\)
(iii) \(\frac { 11 }{ 56 }\) and \(\frac { 27 }{ 56 }\)
Answer:
(i) \(\frac { 5 }{ 12 }\) and \(\frac { 7 }{ 12 }\)
5 < 7
∴ \(\frac { 5 }{ 12 }\) < \(\frac { 7 }{ 12 }\)
\(\frac { 7 }{ 12 }\) is greater

(ii) \(\frac { 22 }{ 48 }\) and \(\frac { 17 }{ 48 }\)
22 > 17
∴ \(\frac { 22 }{ 48 }\) > \(\frac { 17 }{ 48 }\)
\(\frac { 22 }{ 48 }\) is greater.

(iii) \(\frac { 11 }{ 56 }\) and \(\frac { 27 }{ 56 }\)
11 < 27
∴ \(\frac { 11 }{ 56 }\) < \(\frac { 27 }{ 56 }\)
\(\frac { 27 }{ 56 }\)
11 < 27 is greater

Question 4.
Which is smaller in the following fraction?
(i) \(\frac { 10 }{ 42 }\) and \(\frac { 21 }{ 42 }\)
(ii) \(\frac { 31 }{ 37 }\) and \(\frac { 15 }{ 37 }\)
Answer:
(i) \(\frac { 10 }{ 42 }\) and \(\frac { 21 }{ 42 }\)
10 < 21
\(\frac { 10 }{ 42 }\) < \(\frac { 21 }{ 42 }\)
\(\frac { 10 }{ 42 }\) is smaller

(ii) \(\frac { 31 }{ 37 }\) and \(\frac { 15 }{ 37 }\)
15 < 31
\(\frac { 31 }{ 37 }\) < \(\frac { 15 }{ 37 }\)
\(\frac { 15 }{ 37 }\) is smaller

Students can download 5th Maths Term 3 Chapter 6 Fractions InText Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 3 Chapter 6 Fractions InText Questions

Try This (Text Book Page No. 47)

Question 1.
Represent the crossed out part as a fraction.

Answer:
\(\frac { 2 }{ 5 }\)

Question 2.
Represent the figures that are outside the circle as a fraction.

Answer:
\(\frac { 2 }{ 5 }\)

Try This (Text Book Page No. 48)

(i) In \(\frac { 3 }{ 7 }\), ____ is the numerator and ___ is the denominator.
Answer:
3, 7

(ii) In \(\frac { 6 }{ 10 }\), ____ is the numerator and ___ is the denominator.
Answer:
6, 10

Students can download 5th Maths Term 3 Chapter 6 Fractions 6.7 Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 3 Chapter 6 Fractions 6.7

Question 1.
Multiply the following
(i) \(\frac{1}{7}\) × 4
Answer:
\(\frac{1 \times 4}{7}=\frac{4}{7}\)

(ii) \(\frac{3}{8}\) × 5
Answer:
\(\frac{3 \times 5}{8}=\frac{15}{8}\)

(iii) \(\frac{7}{11}\) × 6
Answer:
\(\frac{7 \times 6}{11}=\frac{42}{11}\)

(iv) \(\frac{21}{50}\) × 2
Answer:
\(\frac{21 \times 2}{50}=\frac{42}{50}\)

(v) \(\frac{15}{32}\) × 3
Answer:
\(\frac{15 \times 3}{32}=\frac{45}{32}\)

Question 2.
John has 300 ml of water in a glass and he drinks \(\frac{2}{3}\)ml of water. How many ml of water does he drink?
Answer:
Water in glass = 300 ml
\(\frac{2}{3}\)ml of water = \(\frac{2}{3}\) × 300 = \(\frac{2 \times 300}{3}=\frac{600}{3}\)
= 200

Students can download 5th Maths Term 3 Chapter 6 Fractions 6.5 Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 3 Chapter 6 Fractions 6.5

Question 1.
Add the following fractions
(i) \(\frac{1}{5}\) + \(\frac{3}{5}\)
Answer:
\(\frac{1}{5}+\frac{3}{5}=\frac{1+3}{5}=\frac{4}{5}\)

(ii) \(\frac{1}{7}\) + \(\frac{3}{7}\)
Answer:
\(\frac{1}{7}+\frac{3}{7}=\frac{1+3}{7}=\frac{4}{7}\)

(iii) \(\frac{5}{12}\) + \(\frac{2}{12}\)
Answer:
\(\frac{5}{12}+\frac{2}{12}=\frac{5+2}{12}=\frac{7}{12}\)

(iv) \(\frac{3}{9}\) + \(\frac{7}{9}\)
Answer:
\(\frac{3}{9}+\frac{7}{9}=\frac{3+7}{9}=\frac{10}{9}\)

(v) \(\frac{2}{15}\) + \(\frac{3}{15}\)
Answer:
\(\frac{2}{15}+\frac{3}{15}=\frac{2+3}{15}=\frac{5}{15}\)

(vi) \(\frac{2}{7}\) + \(\frac{1}{7}\) + \(\frac{3}{7}\)
Answer:
\(\frac{2}{7}+\frac{1}{7}+\frac{3}{7}=\frac{2+1+3}{7}=\frac{6}{7}\)

(vii) \(\frac{3}{10}\) + \(\frac{5}{10}\) + \(\frac{2}{10}\)
Answer:
\(\frac{3}{10}+\frac{5}{10}+\frac{2}{10}=\frac{3+5+2}{10}=\frac{10}{10}=1\)

(viii) \(\frac{2}{9}\) + \(\frac{1}{9}\)
Answer:
\(\frac{2}{9}+\frac{1}{9}=\frac{2+1}{9}=\frac{3}{9}\)

(ix) \(\frac{3}{8}\) + \(\frac{2}{8}\)
Answer:
\(\frac{3}{8}+\frac{2}{8}=\frac{3+2}{8}=\frac{5}{8}\)

Question 2.
Mother gave \(\frac{2}{8}\) of guava to Meena and \(\frac{3}{8}\) of guava to Geetha. How many parts of the guava did she give them altogether?
Answer:
Meena get = \(\frac{2}{8}\)
Geeta get = \(\frac{3}{8}\)
Sum = \(\frac{2}{8}\) + \(\frac{3}{8}\) = \(\frac{5}{8}\)

Question 3.
The girls of Std V cleaned \(\frac{3}{5}\) of a field, while the boys cleaned \(\frac{1}{5}\) part of the field. What part of the field was cleaned altogether?
Answer:
Girls cleaned = \(\frac{3}{5}\)
Boys cleaned = \(\frac{1}{5}\)
Sum = \(\frac{3}{5}+\frac{1}{5}=\frac{4}{5}\)

Students can download 5th Maths Term 3 Chapter 6 Fractions 6.4 Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 3 Chapter 6 Fractions 6.4

Question 1.
Write the proper symbol from <, >, or = in the box
(i) \(\frac{3}{5}\) ___ \(\frac{2}{5}\)
Answer:
\(\frac{3}{5}\)   >    \(\frac{2}{5}\)

(ii) \(\frac{2}{8}\) ___ \(\frac{1}{8}\)
Answer:
\(\frac{2}{8}\)    >     \(\frac{1}{8}\)

(iii) \(\frac{2}{11}\) ___ \(\frac{10}{11}\)
Answer:
\(\frac{2}{11}\)    <     \(\frac{10}{11}\)

(iv) \(\frac{3}{15}\) ___ \(\frac{10}{30}\)
Answer:
\(\frac{3}{15}=\frac{3 \times 2}{15 \times 2}=\frac{6}{30}\)
\(\frac{6}{30}\)   <    \(\frac{10}{30}\)
\(\frac{3}{15}\)   <    \(\frac{10}{30}\)

(v) \(\frac{3}{8}\) ___ \(\frac{3}{7}\)
Answer:
\(\frac{3}{8}=\frac{3 \times 7}{8 \times 7}=\frac{21}{56}\)
\(\frac{3}{7}=\frac{3 \times 8}{7 \times 8}=\frac{24}{56}\)
\(\frac{21}{56}\)   <    \(\frac{24}{56}\)
\(\frac{3}{8}\)   <    \(\frac{3}{7}\)

(vi) \(\frac{4}{7}\) ___ \(\frac{4}{11}\)
Answer:
\(\frac{4}{7}=\frac{4 \times 11}{7 \times 11}=\frac{44}{77}\)
\(\frac{4}{11}=\frac{4 \times 7}{11 \times 7}=\frac{28}{77}\)
\(\frac{44}{77}\)    >    \(\frac{28}{77}\)
\(\frac{4}{7}\)    >    \(\frac{4}{11}\)

(vii) \(\frac{5}{12}\) ___ \(\frac{1}{6}\)
Answer:
\(\frac{1}{6}=\frac{1 \times 2}{6 \times 2}=\frac{2}{12}\)
\(\frac{5}{12}\)    >    \(\frac{2}{12}\)
\(\frac{5}{12}\)    >    \(\frac{1}{6}\)
\(\frac{3}{7}\)   <    \(\frac{5}{9}\)

(viii) \(\frac{4}{9}\) ___ \(\frac{4}{9}\)
Answer:
\(\frac{4}{9}\) = \(\frac{4}{9}\)

(ix) \(\frac{3}{7}\) ___ \(\frac{5}{9}\)
Answer:
\(\frac{3}{7}=\frac{3 \times 9}{7 \times 9}=\frac{27}{63}\)
\(\frac{5}{9}=\frac{5 \times 7}{9 \times 7}=\frac{35}{63}\)
\(\frac{27}{63}\)   <    \(\frac{35}{63}\)

(x) \(\frac{4}{11}\) ___ \(\frac{1}{5}\)
Answer:
\(\frac{4}{11}=\frac{4 \times 5}{11 \times 5}=\frac{20}{55}\)
\(\frac{1}{5}=\frac{1 \times 11}{5 \times 11}=\frac{11}{55}\)
\(\frac{20}{55}\)    >    \(\frac{11}{55}\)
\(\frac{4}{11}\)    >    \(\frac{1}{5}\)

Students can download 5th Maths Term 3 Chapter 6 Fractions 6.2 Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 3 Chapter 6 Fractions 6.2

Question 1.
Write the suitable number in the box.
(i)

Answer:

(ii)

Answer:

(iii)

Answer:

(iv)

Answer:

(v)

Answer:

(vi)

Answer:

(vii)

Answer:

(viii)

Answer:

Question 2.
Find an equivalent fraction with denominator 18 for each of the following fractions \(\frac{1}{2}, \frac{2}{3}, \frac{4}{6}, \frac{2}{9}, \frac{7}{9}, \frac{5}{3}\)
Answer:
\(\frac{1}{2}=\frac{1 \times 9}{2 \times 9}=\frac{9}{18}\)
\(\frac{2}{3}=\frac{2 \times 6}{3 \times 6}=\frac{12}{18}\)
\(\frac{4}{6}=\frac{3 \times 4}{3 \times 6}=\frac{12}{18}\)
\(\frac{2}{9}=\frac{2 \times 2}{9 \times 2}=\frac{4}{18}\)
\(\frac{7}{9}=\frac{7 \times 2}{9 \times 2}=\frac{14}{18}\)
\(\frac{5}{3}=\frac{5 \times 6}{3 \times 6}=\frac{30}{18}\)

Question 3.
Find an equivalent fraction with denominator 5 for each of the following fractions \(\frac{6}{15}, \frac{10}{25}, \frac{12}{30}, \frac{6}{10}, \frac{21}{35}\)
Answeer:
\(\frac{6}{15}=\frac{6 \div 3}{15 \div 3}=\frac{2}{5}\)
\(\frac{10}{25}=\frac{10 \div 5}{25 \div 5}=\frac{2}{5}\)
\(\frac{12}{30}=\frac{12 \div 6}{30 \div 6}=\frac{2}{5}\)
\(\frac{6}{10}=\frac{6 \div 2}{10 \div 2}=\frac{3}{5}\)
\(\frac{21}{35}=\frac{21 \div 7}{35 \div 7}=\frac{3}{5}\)

Students can download 5th Maths Term 3 Chapter 5 Money Ex 5.1 Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 3 Chapter 5 Money Ex 5.1

Question 1.
Fill in the blanks
(i) ₹ 35,50 + ₹ 4.50 = ______

Answer:
₹ 40.00

(ii) ₹ 7500 + ₹ 3000 = ______

Answer:
₹ 10500

(iii) ₹ 1000 – ₹ 230 = ______

Answer:
₹ 770.00

(iv) ₹ 75.50 – ₹ 30.25 = ______

Answer:
₹ 45.25

Question 2.
Match the following

(i) ₹ 950.50 + ₹ 350	(a) ₹ 399.50
(ii) ₹ 8000 – ₹ 3500	(b) ₹ 91.25
(iii) ₹ 50.70 + ₹ 40.00	(c) ₹ 1300.50
(iv) ₹ 750 – ₹ 350.00	(d) ₹ 4500

Answer:

(i) ₹ 950.50 + ₹ 350	(c) ₹ 1300.50
(ii) ₹ 8000 – ₹ 3500	(d) ₹ 4500
(iii) ₹ 50.70 + ₹ 40.00	(b) ₹ 91.25
(iv) ₹ 750 – ₹ 350.00	(a) ₹ 399.50

Question 3.
Add the following
(i) ₹ 8987.75 + ₹ 9565.50 + ₹ 7693.50
(ii) ₹ 29763.50 + ₹ 95675.50 + ₹ 4973.50
(iii) ₹ 9978.75 + ₹ 7695.50 + ₹ 635.00
Answer:
(i) ₹ 8987.75 + ₹ 9565.50 + ₹ 7693.50

(ii) ₹ 29763.50 + ₹ 95675.50 + ₹ 4973.50

(iii) ₹ 9978.75 + ₹ 7695.50 + ₹ 635.00

Question 4.
Subtract the following
(i) ₹1985 – ₹ 798.25
(ii) ₹ 688 – ₹ 215
(iii) ₹ 49689 – ₹ 33462.50
Answer:
(i) ₹1985 – ₹ 798.25

(ii) ₹ 688 – ₹ 215

(iii) ₹ 49689 – ₹ 33462.50

Question 5.
Arun purchased gold coins in different weights in a Jewellery shop. The price of the gold coins were ₹ 18965.75, ₹ 26998.00 and ₹ 3589.50 respectively. Find the total price of the gold coins.
Answer:

Question 6.
In a textiles shop, father, mother, son and daughter were purchasing clothes. The price of each of their clothes were ₹ 8950, ₹ 14875, ₹ 7895 and ₹ 9780 respectively. Find the total cost of their clothes.
Answer:

Question 7.
A farmer wanted to buy a tractor. The price of the tractor was ₹ 6,72,598, but he had only ₹ 2,86,760. How much more amount was required to buy the tractor?
Answer:

Question 8.
A man had ₹ 17,246 in his savings account. If he had taken ₹ 8,891 to pay for house rent, then how much amount was left in his savings account?
Answer:

Students can download 5th Maths Term 3 Chapter 4 Algebra Ex 4.2 Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 3 Chapter 4 Algebra Ex 4.2

Question 1.
Say whether true or false

(i) (23 + 4) = (4 + 23)
Hint: 27 = 27
Answer:
True

(ii) (9 + 4) > 12
Hint: 13 > 12
Answer:
True

(iii) (9 + 4) < 12
Hint: 13 < 12
Answer:
False

(iv) 11 > 121
Answer:
False

(v) 142 < 142
Answer:
False

(vi) 112 = 112
Answer:
True

(vii) (6 × 5) (32 – 2)
Hint: 30 = 30
Answer:
True

(viii) \(\frac { 49 }{ 7 }\) > 7
Hint: \(\frac { 49 }{ 7 }\) = 7
Answer:
False

(ix) (4 × 3) = (3 × 4)
Hint: 4 × 3 = 12 ;
3 × 4 = 12
Answer:
True

(x) (21 + 0) = 21
Answer:
True

Question 2.
Fill in the blanks with the right symbol (<, > or =).
(i) (54 ÷ 9) ___ (8 – 3)
Answer:
54 ÷ 9 = 6
8 – 3 = 5
6 > 5
(54 ÷ 9) > 8 – 3

(ii)(6 + 2) ___ (4 × 2)
Answer:
6 + 2 = 8
4 × 2 = 8
8 = 8
(6 + 2) = (4 × 2)

(iii) (10 × 2) ____ (15 + 20)
Answer:
10 × 2 = 20
15 + 20 = 35
20 < 35
10 × 2 < 15 + 20

Question 3.
Fill in the blanks in the expressions with the suitable number.
(i) (1 × 9) = (___ × 1)
Answer:
(1 × 9) = (9 × 1)

(ii) (6 × 3) > (8 × ___)
Answer:
6 × 3 = 18
8 × 2 = 16
18 > 16
6 × 3 > (8 × 2)

(iii) (36 ÷ 6) < (___ × 7)
Answer:
36 ÷ 6 = 6
1 × 7 = 7
6 < 7
(36 ÷ 6) < 1 × 7

(iv) (0 + 2) > (7 × ____)
Answer:
(0 + 2) = 2
7 × 0 = 0
2 > 0
(0 + 2) > (7 × 0)

(v) (42 ÷ 7) = (4 + ____)
Answer:
(42 ÷ 7) = 6
4 + 2 = 6
(42 ÷ 7) = (4 + 2)

(vi) (6 – ___) < (1 + 2)
Answer:
6 – 4 = 2
1 + 2 = 3
2 < 3
(6 – 3) < (1 + 2)