Tamil Nadu 11th Physics Model Question Paper 3 English Medium

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TN State Board 11th Physics Model Question Paper 3 English Medium

General Instructions:

  1. The question paper comprises of four parts.
  2. You are to attempt all the parts. An internal choice of questions is provided wherever applicable.
  3. All questions of Part I, II, III and IV are to be attempted separately.
  4. Question numbers 1 to 15 in Part I are Multiple Choice Questions of one mark each.
    These are to be answered by choosing the most suitable answer from the given four alternatives and writing the option code and the corresponding answer
  5. Question numbers 16 to 24 in Part II are two-mark questions. These are to be answered in about one or two sentences.
  6. Question numbers 25 to 33 in Part III are three-mark questions. These are to be answered in about three to five short sentences.
  7. Question numbers 34 to 38 in Part IV are five-mark questions. These are to be answered in detail Draw diagrams wherever necessary.

Time: 3 Hours
Maximum Marks: 70

PART – I

Answer all the questions: [15 × 1 = 15]

Question 1.
A new unit of length is chosen such that the speed of light in vacuum is unity. The distance between the Sun and the Earth in terms of the new unit, if light takes 8 minute and 20 sec to cover the distance is …………………..
(a) 100 new unit
(b) 300 new unit
(c) 500 new unit
(d) 700 new unit
Hint:
Speed is unity = 1 unit/sec
Time = 8 min and 20 sec = 500 sec
Distance b/w sun and earth = Speed × Time
= 1 × 500 = 500 unit
Answer:
(c) 500 new unit

Tamil Nadu 11th Physics Model Question Paper 3 English Medium

Question 2.
For a satellite moving in an orbit around the Earth, the ratio of kinetic energy to potential energy is ………………….
(a) 2
(b) 1 : 2
(c) 1 : \(\sqrt{2}\)
(d) \(\sqrt{2}\)
Hint:
\(\frac { GMm }{ R^{ 2 } } \) = mω2R
K.E = \(\frac{1}{2}\)Iω2 = \(\frac{1}{2}\)mR2ω2 = \(\frac{GMm}{2R}\)
P.E = – \(\frac{GMm}{R}\) ⇒ So \(\frac{K.E}{|P.E|}\) = \(\frac{1}{2}\)
Answer:
(b) 1 : 2

Question 3.
In the equilibrium position a body has ……………….
(a) Maximum potential energy
(b) Minimum potential energy
(c) Minimum kinetic energy
(d) Neither maximum nor minimum potential energy
Answer:
(c) Minimum kinetic energy

Tamil Nadu 11th Physics Model Question Paper 3 English Medium

Question 4.
The centrifugal force appears to exist ………………….
(a) Only in inertial frames
(b) Only in rotating frames
(c) In any accelerated frame
(d) Both in inertial and non-inertial frames
Answer:
(b) Only in rotating frames

Question 5.
A particle is moving with a constant velocity along a line parallel to positive x-axis. The magnitude of its angular momentum with respect to the origin is …………………..
(a) Zero
(b) Increasing with x
(c) Decreasing with x
(d) Remaining constant
Answer:
(d) Remaining constant

Question 6.
When 8 droplets of water of radius 0.5 mm combine to form a single droplet. The radius of it is …………………
(a) 4 mm
(b) 2 mm
(c) 1 mm
(d) 8 mm
Hint:
Volume of 8 droplets of water = 8 × \(\frac{4}{3}\) π(0.5)3
When each droplet combine to form one volume remains conserved
R3 = 8 × (0.5)3
R3 = (8 × (0.5)3)
R3 = 2 × 0.5 = 1 mm
Answer:
(c) 1 mm

Tamil Nadu 11th Physics Model Question Paper 3 English Medium

Question 7.
Pressure head in Bernoulli’s equation is …………………
(a) \(\frac { P_{ \rho } }{ g } \)
(b) \(\frac { P }{ \rho g } \)
(c) ρg
(d) Pρg
Answer:
(b) \(\frac { P }{ \rho g } \)

Question 8.
The angle between particle velocity and wave velocity in a transverse wave is ……………………
(a) Zero
(b) π/4
(c) π/2
(d) π
Answer:
(c) π/2

Question 9.
If the masses of the Earth and Sun suddenly double, the gravitational force between them will …………………….
(a) Remains the same
(b) Increase two times
(c) Increase four times
(d) Decrease two times
Answer:
(c) Increase four times

Question 10.
A mobile phone tower transmits a wave signal of frequency 900 MHz, the length of the transmitted from the mobile phone tower ……………………
(a) 0.33 m
(b) 300 m
(c) 2700 × 108m
(d) 1200 m
Hint:
f = 900 MHz = 900 × 106 Hz
Speed of wave (c) = 3 × 106 ms-1
λ = \(\frac{v}{f}\) = \(\frac { 3\times 10^{ 8 } }{ 900\times 10^{ 6 } } \) = \(\frac{1}{3}\) = 0.33m
Answer:
(a) 0.33 m

Tamil Nadu 11th Physics Model Question Paper 3 English Medium

Question 11.
The displacement y of a wave travelling in the x direction is given by
y = (2 × 10-3) sin (300 t – 2x + \(\frac { \pi }{ 4 } \)), where x and y are measured in metres and t in second. The speed of the wave is …………………
(a) 150 ms-1
(b) 300 ms-1
(c) 450 ms-1
(d) 600 ms-1
Hint:
From standard equation of wave, Y = a sin (ωt – kx + ϕ)
ω = 300 ; k = 2
Speed of wave, V = \(\frac{ω}{k}\) = \(\frac{300}{2}\) = 150ms-1
Answer:
(a) 150 ms-1

Question 12.
The increase in internal energy of a system is equal to the workdone on the system. The process does the system undergoes is ……………………
(a) Isochoric
(b) Adiabatic
(c) Isobaric
(d) Isothermal
Answer:
(d) Isothermal

Question 13.
The minimum velocity with which a body of mass m must enter a vertical loop of radius R so that it can complete the loop is ……………………..
(a) \(\sqrt{2gR}\)
(b) \(\sqrt{3gR}\)
(c) \(\sqrt{5gR}\)
(d) \(\sqrt{gR}\)
Answer:
(c) \(\sqrt{5gR}\)

Tamil Nadu 11th Physics Model Question Paper 3 English Medium

Question 14.
If the rms velocity of the molecules of a gas in a container be doubled then the pressure of the gas will.
(a) Becomes 4 times of the previous value
(b) Becomes 2 times of its previous value
(c) Remains same
(d) Becomes \(\frac{1}{4}\) of its previous value
Hint:

Tamil Nadu 11th Physics Model Question Paper 3 English Medium img 1

Answer:
(a) Becomes 4 times of the previous value

Question 15.
Gravitational mass is proportional to gravitational ………………….
(a) Intensity
(b) Force
(c) Field
(d) All of these
Answer:
(b) Force

PART – II

Answer any six questions in which Q. No 23 is compulsory. [6 × 2 = 12]

Question 16.
Write any four postulates of Kinetic theory of gases?
Answer:

  1. A gas consists of a very large number of molecules. Each one is a perfectly identical elastic sphere.
  2. The molecules of a gas are in a state of continuous and random motion. They move in all directions with all possible velocities.
  3. The size of each molecule is very small as compared to the distance between them. Hence, the volume occupied by the molecule is negligible in comparison to the volume of the gas:
  4. There is no force of attraction or repulsion between the molecules and the walls of the container.

Tamil Nadu 11th Physics Model Question Paper 3 English Medium

Question 17.
Draw the free body diagram of the book at rest on the table?
Answer:

Tamil Nadu 11th Physics Model Question Paper 3 English Medium img 2

Question 18.
Three block are connected as shown in fig on a horizontal frictionless table. If m1 = 1 kg, m2 = 8 kg, m3 = 27 kg and T3 = 36 N then calculate tension T2?
Answer:

Tamil Nadu 11th Physics Model Question Paper 3 English Medium img 3

Acceleration acquired by all blocks a = \(\frac { T_{ 3 } }{ m_{ 1 }+m_{ 2 }+m_{ 3 } } \) = \(\frac{36}{36}\) = 1ms-2
∴ Tension T2 = (m1 + m2) a
= (1 + 8) × 1 = 9N

Tamil Nadu 11th Physics Model Question Paper 3 English Medium

Question 19.
What is power? Give its dimensional formula?
Answer:
The rate of work done is called power. Dimensional formula of power is ML2 T-3

Question 20.
What are geostationary and polar satellites?
Answer:
Geostationary Satellite: It is the satellite which appears at a fixed position and at a definite height to an observer on Earth.
Polar Satellite: It is the satellite which revolves in polar orbit around the Earth.

Question 21.
An iceberg of density 900 kg m-3 is floating in water of density 1000 kg m-3. What is the percentage of volume of iceberg outside the water?
Answer:
Fraction of volume inside water = Relative density of the body
\(\frac { V’ }{ V } \) = \(\frac { \rho }{ \rho ‘ } \) = \(\frac{900}{1000}\) = 0.9
Fraction of volume outside water = 1 – 0.9 = 0.1
Percentage of volume outside water = 0.1 × 100 = 10%

Tamil Nadu 11th Physics Model Question Paper 3 English Medium

Question 22.
State stoke’s law and define terminal velocity?
Answer:
Stoke’s law:
When a body falls through a highly viscous liquid, it drags the layer of the liquid immediately in contact with it. This results in a relative motion between the different layers of the liquid. As a result of this, the falling body experiences a viscous force F.

Stoke performed many experiments on the motion of small spherical bodies in different fluids and concluded that the viscous force F acting on the spherical body depends on

  1. Coefficient of viscosity q of the liquid
  2. Radius a of the sphere and
  3. Velocity v of the spherical body

Dimensionally it can be proved that ∴ F = k ηav
Experimentally Stoke found that k = 6π
This is Stoke’s law

Terminal velocity:
Terminal velocity of a body is defined as the constant velocity acquired by a body while falling through a viscous liquid.

Tamil Nadu 11th Physics Model Question Paper 3 English Medium

Question 23.
The Earth without its atmosphere would be hospitably cold. Explain why?
Answer:
The lower layers of Earth’s atmosphere reflect infrared radiations from Earth back to the surface of Earth. Thus the heat radiation received by the earth from the Sun during the day are kept trapped by the atmosphere. If atmosphere of Earth were not there, its surface would become too cold to live.

Question 24.
A body A is projected upwards with velocity v1 Another body B of same mass is proj eeted at an angle of 45°. Both reach the same height. Calculate the ratio of their initial kinetic energies?
Answer:
As A and B attain the same height therefore vertical component of initial velocity of B is equal to initial velocity of A
v2 cos 45° = V1 (or) \(\frac { v_{ 2 } }{ \sqrt { 2 } } \) = v1

Tamil Nadu 11th Physics Model Question Paper 3 English Medium img 4

PART – III

Answer any six questions in which Q.No. 29 is compulsory. [6 × 3 = 18]

Question 25.
Explain the rules for counting significant figures with examples?
Rules for counting significant figures:
Answer:

Tamil Nadu 11th Physics Model Question Paper 3 English Medium img 5

Question 26.
Elastic headon collision, consider two particles one is moving and another one is stationary with their respective masses m and \(\frac { M }{ m } \). A moving particle meets collides elastically on stationary particle in the opposite direction. Find the kinetic energy of the stationary particle after a collision?
Answer:
mass of the moving particle m1 = m (say)
mass of the stationary particle m1 = \(\frac { 1 }{ m } \) M
Velocity of the moving particle before collision = v1i (say)
Velocity of the stationary particle before collision = v2i = 0
Velocity of the stationary particle after collision = v2f (say)

Tamil Nadu 11th Physics Model Question Paper 3 English Medium img 6

Kinetic energy of the stationary particle after a collision

Tamil Nadu 11th Physics Model Question Paper 3 English Medium img 7

Question 27.
Calculate the angle for which a cyclist bends when he turns a circular path of length 34.3 m in \(\sqrt{22}\) s?
Answer:
Given Data:
l = 34.3 m, t = \(\sqrt{22}\) , g = 9.8 ms-2, θ = ?
If r is radius of circular path, then length of path = 2πr = 34.3 m
r = \(\frac { 33.4 }{ 2\pi } \) and time taken t = \(\sqrt{22}\)s

As tan θ = \(\frac { v^{ 2 } }{ rg } \)
∴ tan θ = (\(\frac { 34.3 }{ \sqrt { 22 } } \))2 × \(\frac { 2\pi }{ 34.3\times 9.8 } \)
tan θ = \(\frac { 34.3\times 34.3 }{ 22 } \) × \(\frac{2×22}{7×343×9.8}\) = \(\frac{34.3×2}{68.6}\) = 1 [∴θ = 45°]

Tamil Nadu 11th Physics Model Question Paper 3 English Medium

Question 28.
Explain how density, moisture affect the velocity of sound in gases?
Answer:
Effect of density:
Let us consider two gases with different densities having same temperature and pressure. Then the speed of sound in the two gases are

Tamil Nadu 11th Physics Model Question Paper 3 English Medium img 8

Taking ratio of equation (1) and equation (2) we get

Tamil Nadu 11th Physics Model Question Paper 3 English Medium img 9

For gases having same value of γ,
\(\frac { v_{ 1 } }{ v_{ 2 } } \) = \(\sqrt { \frac { \rho _{ 2 } }{ \rho _{ 1 } } } \)
Thus the velocity of sound in a gas is inversely proportional to the square root of the density of the gas.

Effect of moisture (humidity):
We know that density of moist air is 0.625 of that of dry air, which means the presence of moisture in air (increase in humidity) decreases its density. Therefore, speed of sound increases with rise in humidity. From equation:
v = \(\sqrt { \frac { \gamma \rho }{ \rho } } \)

Let ρ1, v1 = and ρ2, v2 be the density and speeds of sound in dry air and moist air, respectively.

Tamil Nadu 11th Physics Model Question Paper 3 English Medium img 10

Since P is the atmospheric pressure, it can be shown that
\(\frac { \rho _{ 2 } }{ \rho _{ 1 } } \) = \(\frac { P }{ p_{ 1 }+0.625p_{ 2 } } \)
where p1 and p2 are the partial pressures of dry air and water vapour respectively. Then

Tamil Nadu 11th Physics Model Question Paper 3 English Medium img 11

Question 29.
Explain
(a) Why there are no lunar eclipse and solar eclipse every month?
(b) Why do we have seasons on earth?
Answer:
(a) If the orbits of the Moon and Earth lie on the same plane, during full Moon of every month, we can observe lunar eclipse. If this is so during new Moon we can observe solar eclipse.

But Moon’s orbit is tilted 5° with respect to Earth’s orbit. Due to this 5° tilt, only during certain periods of the year, the Sun, Earth and Moon align in straight line leading to either lunar eclipse or solar eclipse depending on the alignment.

(b) The common misconception is that ‘Earth revolves around the Sun, so when the Earth is very far away, it is winter and when the Earth is nearer, it is summer’.

Actually, the seasons in the Earth arise due to the rotation of Earth around the Sun with 23.5° tilt. Due to this 23.5° tilt, when the northern part of Earth is farther to the Sun, the southern part is nearer to the Sun. So when it is summer in the northern hemisphere, the southern hemisphere experience winter.

Tamil Nadu 11th Physics Model Question Paper 3 English Medium

Question 30.
When a person breathes, his lungs can hold up to 5.5 1 of air at body temperature 37°C and atmospheric pressure (1 atm = 101 kPa). This air contains 21% oxygen, calculate the number of oxygen molecules in the lungs?
Answer:
We can treat the air inside the lungs as an ideal gas. To find the number of molecules, we can use the ideal gas law.
PV = NkT
Here volume is given in the Litre. 1 Litre is volume occupied by a cube of side 10 cm
1 Litre = 10 cm × 10 cm × 10 cm = 10-3m-3
N = \(\frac{PV}{kT}\) = \(\frac { 1.01\times 10^{ 5 }\times 5.5\times 10^{ -3 } }{ 1.38\times 10^{ -23 }\times 310 } \)
= 1.29 × 1023 × \(\frac{21}{100}\)
Number of oxygen molecules = 2.7 × 1022 molecules

Question 31.
Give any five properties of vector product of two vectors?
Answer:
(I) The vector product of any two vectors is always another vector whose direction is perpendicular to the plane containing these two vectors, i.e., orthogonal to both the vectors \(\vec { A } \) and \(\vec { B } \), even though the vectors AandB may or may not be mutually orthogonal.

(II) The vector product of two vectors is not commutative, i.e., \(\vec { A } \) × \(\vec { B } \) ≠ \(\vec { B } \) × \(\vec { A } \) . But, \(\vec { A } \) × \(\vec { B } \) = –\(\vec { B } \) × \(\vec { A } \).

Here it is worthwhile to note that |\(\vec { A } \) × \(\vec { B } \)| = |\(\vec { B } \) × \(\vec { A } \)| = AB sin θ i.e., in the case of the product vectors \(\vec { A } \) × \(\vec { B } \) and \(\vec { B } \) × \(\vec { A } \), the magnitudes are equal but directions are opposite to each other.

(III) The vector product of two vectors will have maximum magnitude when sin 0 = 1, i.e., θ = 90° i.e., when the vectors \(\vec { A } \) and \(\vec { B } \) are orthogonal to each other.
(\(\vec { A } \) × \(\vec { B } \))max = AB\(\hat { n } \)

(IV) The vector product of two non-zero vectors will be minimum when sin 0 = 0, i.e., 0 = 0° or 180°
(\(\vec { A } \) × \(\vec { B } \))max = 0
i.e., the vector product of two non-zero vectors vanishes, if the vectors are either parallel or antiparallel.

(V) The self-cross product, i.e., product of a vector with itself is the null vector
\(\vec { A } \) × \(\vec { A } \) = AA sin 0°\(\hat { n } \) = \(\vec { 0 } \)
In physics the null vector \(\vec { 0 } \) is simply denoted as zero.

Tamil Nadu 11th Physics Model Question Paper 3 English Medium

Question 32.
Why does a porter bend forward w hile carrying a sack of rice on his back?
Answer:
When a porter carries a sack of rice, the line of action of his centre of gravity will go away from the body. It affects the balance, to avoid this he bends. By which centre of gravity will realign within the body again. So balance is maintained.

Question 33.
A piece of wood of mass m is floating erect in a liquid whose density is p. If it is slightly pressed down and released, then executes simple harmonic motion. Show that its time period of oscillation is T = 2π\(\sqrt{m/Agρ}\)
Answer:
Spring factor of liquid(k) = Aρg
Inertia factor of wood = m
Time period T = 2π = image 12
T = 2π\(\sqrt{m/Aρg}\)

PART – IV

Answer all the questions. [5 × 5 = 25]

Question 34 (a).
Describe the vertical oscillations of a spring?
Answer:
Vertical oscillations of a spring: Let us consider a massless spring with stiffness constant or force constant k attached to a ceiling as shown in figure. Let the length of the spring before loading mass m be L.

If the block of mass m is attached to the other end of spring, then the spring elongates by a length. Let F, be the restoring force due to stretching of spring. Due to mass m, the gravitational force acts vertically downward. We can draw free-body diagram for this system as shown in figure. When the system is under equilibrium,

Tamil Nadu 11th Physics Model Question Paper 3 English Medium img 12

F1 + mg = 0 ……………… (1)
But the spring elongates by small displacement 1, therefore,
F1 ∝ l ⇒ F1 = -kl ……………….. (2)
Substituting equation (2) in equation (1) we get
-kl + mg = 0
mg = kl or
\(\frac{m}{k}\) = \(\frac{l}{g}\) ………………….. (3)

Suppose we apply a very small external force on the mass such that the mass further displaces downward by a displacement y, then it will oscillate up and down. Now, the restoring force due to this stretching of spring (total extension of spring is y + 1) is
F2 ∝ (y + l)
F2 = -k(y + l) = -ky – kl …………………… (4)

Since, the mass moves up and down with acceleration \(\frac{d^{2} y}{d t^{2}}\), by drawing the free body diagram for this case we get
-ky – kl + mg = m \(\frac{d^{2} y}{d t^{2}}\) ……………………. (5)
The net force acting on the mass due to this stretching is
F = F2 + mg
F = -ky – kl + mg …………………… (6)
The gravitational force opposes the restoring force. Substituting equation (3) in equation (6), we get
F = – ky- kl + kl = -ky
Applying Newton’s law we get
m \(\frac{d^{2} y}{d t^{2}}\) = -ky
\(\frac{d^{2} y}{d t^{2}}\) = –\(\frac{k}{m}\)y ………………… (7)
The above equation is in the form of simple harmonic differential equation. Therefore, we get the time period as
T = 2π\(\sqrt{m/k}\) second ……………………. (8)
The time period can be rewritten using equation (3)
T = 2π\(\sqrt{m/k}\) = 2πl\(\frac{1}{g}\) second ……………………. (9)
The accleration due to gravity g can be computed by the formula
g = 4π2\((\frac { 1 }{ T } )^{ 2 }\)ms-2 …………………….. (10)

[OR]

(b) Derive poiseuille’s formula for the volume of a liquid flowing per second through a pipe under streamlined flow?
Answer:
Consider a liquid flowing steadily through a horizontal capillary tube. Let v = (\(\frac{1}{g}\)) be the volume of the liquid flowing out per second through a capillary tube. It depends on (1) coefficient of viscosity (η) of the liquid, (2) radius of the tube (r), and (3) the pressure gradient (\(\frac{P}{l}\)) . Then,
v ∝ηarb(\(\frac{P}{l}\))c
v = kηarb(\(\frac{P}{l}\))c …………………….. (1)

where, k is a dimensionless constant.
Therefore, [v] = \(\frac { Volume }{ Time } \) = [L3T-1]; [ \(\frac{dP}{dX}\) ] = \(\frac { Pressure }{ Distance } \) = [ML-2T-2]
[η] = [Ml-1T-1] and [r] = [L]

Substituting in equation (1)
[L3T-1] = [ML-1T-1]a[L]b [ML-2T-2]c
M0L3T-1 = Ma+bL-a+b-2cT-a-2c = -1

So, equating the powers of M, L and T on both sides, we get
a + c = 0, – a + b – 2c = 3, and – a – 2c = – 1

We have three unknowns a, b and c. We have three equations, on solving, we get
a = – 1, b = 4 and c = 1

Therefore, equation (1) becomes,
v = kη-1r4(\(\frac{P}{l}\))1

Experimentally, the value of k is shown to be , we have \(\frac{π}{8}\), we have
v = \(\frac{\pi r^{4} \mathrm{P}}{8 \eta /}\)

The above equation is known as Poiseuille’s equation for the flow of liquid through a narrow tube or a capillary tube. This relation holds good for the fluids whose velocities are lesser than the critical velocity (vc).

Tamil Nadu 11th Physics Model Question Paper 3 English Medium

Question 35 (a).
Describe briefly simple harmonic oscillation as a projection of uniform circular motion?
Answer:
Consider a particle of mass m moving with unifonn speed v along the circumference of a circle whose radius is r in anti-clockwise direction (as shown in figure). Let us assume that the origin of the coordinate system coincides with the center O of the circle.

If ω is the angular velocity of the particle and θ the angular displacement of the particle at any instant of time t, then θ = ωt. By projecting the uniform circular motion on its diameter gives a simple harmonic motion.

This means that we can associate a map (or a relationship) between uniform circular (or revolution) motion to vibratory motion. Conversely, any vibratory motion or revolution can be mapped to unifonn circular motion. In other words, these two motions are similar in nature.

Let us first project the position of a particle moving on a circle, on to its vertical diameter or on to a line parallel to vertical diameter as shown in figure. Similarly, we can do it for horizontal axis or a line parallel to horizontal axis.

Tamil Nadu 11th Physics Model Question Paper 3 English Medium img 13

The projection of uniform circular motion on a diameter of SHM:
As a specific example, consider a spring mass system (or oscillation of pendulum). When the spring moves up and down (or pendulum moves to and fro), the motion of the mass or bob is mapped to points on the circular motion.

Thus, if a particle undergoes uniform circular motion then the projection of the particle on the diameter of the circle (or on a line parallel to the diameter) traces straight line motion which is simple harmonic in nature. The circle is known as reference circle of the simple harmonic motion. The simple harmonic motion can also be defined as the motion of the projection of a particle on any diameter of a circle of reference.

[OR]

(b) State and prove Bernoulli’s theorem for a flow of incompressible non viscous and stream lined flow of fluid?
Answer:
Bernoulli’s theorem:
According to Bernoulli’s theorem, the sum of pressure energy, kinetic energy, and potential energy per unit mass of an incompressible, non-viscous fluid in a streamlined flow remains a constant. Mathematically,
\(\frac{P}{ρ}\) + \(\frac{1}{2}\)v2 + gh – constant
This is known as Bernoulli’s equation.
Proof:
Let us consider a flow of liquid through a pipe AB. Let V be the volume of the liquid when it enters A in a time t. Which is equal to the volume of the liquid leaving B in the same time. Let aA, vA and PA be the area of cross section of the tube, velocity of the liquid and pressure exerted by the liquid at A respectively.

Let the force exerted by the liquid at A is
FA = PAaA

Distance travelled by the liquid in time t is d = vAt
Therefore, the work done is W = FAd = PAaAvAt
But aAvAt = aAd = V, volume of the liquid entering at A.

Thus, the work done is the pressure energy (at A), W = FAd = PAV

Pressure energy per unit volume at
A = \($\frac{\text { Pressure energy }}{\text { Volume }}$\) = \(\frac { P_{ A }V }{ V } \) = PA

Pressure energy per unit mass at
A = \($\frac{\text { Pressure energy }}{\text { Mass }}$\) = \(\frac { P_{ A }V }{ m } \) = \(\frac { P_{ A } }{ \frac { m }{ V } } \) = \(\frac { P_{ A } }{ \rho } \)

Since m is the mass of the liquid entering at A in a given time, therefore, pressure energy of the liquid at A is
EPA = PAV = PAV × (\(\frac{m}{m}\)) = m\(\frac { P_{ A } }{ \rho } \)

Potential energy of the liquid at A,
PEA = mghA

Due to the flow of liquid, the kinetic energy of the liquid at A,
KEA = \(\frac{1}{2}\)mv2A

Therefore, the total energy due to the flow of liquid at A,
EA = EPA + KEA + PEA
EA = \(m \frac{P_{A}}{\rho}+\frac{1}{2} m v_{A}^{2}+m g h_{A}\)

Similarly, let aB, VB and PB be the area of cross section of the tube, velocity of the liquid and pressure exerted by the liquid at B. Calculating the total energy at FB, we get .
\(\mathrm{E}_{\mathrm{B}}=m \frac{\mathrm{P}_{\mathrm{B}}}{\rho}+\frac{1}{2} m v_{\mathrm{B}}^{2}+m g h_{\mathrm{B}}\)
From the law of conservation of energy.
EA = EB

Tamil Nadu 11th Physics Model Question Paper 3 English Medium img 14

Thus, the above equation can be written as
\(\frac { P }{ \rho g } \) + \(\frac{1}{2}\) \(\frac { v^{ 2 } }{ g } \) + h = Constant

The above equation is the consequence of the conservation of energy which is true until there is no loss of energy due to friction. But in practice, some energy is lost due to friction. This arises due to the fact that in a fluid flow, the layers flowing with different velocities exert frictional forces on each other. This loss of energy is generally converted into heat energy. Therefore, Bernoulli’s relation is strictly valid for fluids with zero viscosity or non-viscous liquids. Notice that when the liquid flows through a horizontal pipe, then
h = 0 ⇒ \(\frac { P }{ \rho g } \) + \(\frac{1}{2}\) \(\frac { v^{ 2 } }{ g } \) = Constant

Tamil Nadu 11th Physics Model Question Paper 3 English Medium

Question 36 (a).
Explain perfect inelastic collision and derive an expression for loss of kinetic energy in perfect inelastic collision?
Answer:
In a perfectly inelastic or completely inelastic collision, the objects stick together permanently after collision such that they move with common velocity. Let the two bodies with masses m1 and m2 move with initial velocities u1 and u2 respectively before collision. Aft er perfect inelastic collision both the objects move together with a common velocity v as shown in figure.
Since, the linear momentum is conserved during collisions,

Tamil Nadu 11th Physics Model Question Paper 3 English Medium img 15

m1u1 + m2u2 = (m1 + m2) v

Tamil Nadu 11th Physics Model Question Paper 3 English Medium img 16

The common velocity can be computed by
v = \(\frac{m_{1} u_{1}+m_{2} u_{2}}{\left(m_{1}+m_{2}\right)}\) ………………….. (1)

Loss of kinetic energy in perfect inelastic collision;
In perfectly inelastic collision, the loss in kinetic energy during collision is transformed to another form of energy like sound, thermal, heat, light etc. Let KEi be the total kinetic energy before collision and KEf be the total kinetic energy after collision.
Total kinetic energy before collision,
KEe = \(\frac{1}{2} m_{1} u_{1}^{2}+\frac{1}{2} m_{2} u_{2}^{2}\) …………………… (2)
Total kinetic energy after collision,
KEf = \(\frac{1}{2}\left(m_{1}+m_{2}\right) v^{2}\) …………………….. (3)
Then the loss of kinetic energy is Loss of KE, ∆Q = KEf – KEi
= \(\frac{1}{2}\left(m_{1}+m_{2}\right) v^{2}-\frac{1}{2} m_{1} u_{1}^{2}-\frac{1}{2} m_{2} u_{2}^{2}\) ………………….. (4)
Substituting equation (1) in equation (4), and on simplifying (expand v by using the algebra (a + b)2 = a2 + b2 + 2ab), we get
Loss of KE, ∆Q = \(\frac{1}{2}\) \(\left(\frac{m_{1} m_{2}}{m_{1}+m_{2}}\right)\) (u1 – u2)2

[OR]

(b) Derive an expression for maximum height attained, time of flight, horizontal range for a projectile in oblique projection?
Answer:

Tamil Nadu 11th Physics Model Question Paper 3 English Medium img 17

Maximum height (hmax):
The maximum vertical distance travelled by the projectile during the journey is called maximum height. This is determined as follows:
For the vertical part of the motion
\(v_{y}^{2}=u_{y}^{2}+2 a_{y} s\)
Here, uy= u sin θ, a = -g, s = hmax, and at the maximum height v = 0

Time of flight (Tf):
The total time taken by the projectile from the point of projection till it hits the horizontal plane is called time of flight. This time of flight is the time taken by the projectile to go from point O to B via point A as shown in figure.
We know that sy = uyt + \(\frac{1}{2}\)ayt2
Here, sy = y = 0 (net displacement in y-direction is zero), uy = u sin θ, ay = -g, t = Tf, Then
0 = u sin θ Tf – \(\frac{1}{2} g \mathrm{T}_{f}^{2}\)
Tf = 2u \(\frac{sin θ}{g}\) …………………….. (2)

Horizontal range (R):
The maximum horizontal distance between the point of projection and the point on the horizontal plane where the projectile hits the ground is called horizontal range (R). This is found easily since the horizontal component of initial velocity remains the same. We can write.

Range R = Horizontal component of velocity % time of flight = u cos θ × Tf = \(\frac{u^{2} \sin 2 \theta}{g}\)
The horizontal range directly depends on the initial speed (u) and the sine of angle of projection (θ). It inversely depends on acceleration due to gravity ‘g’.

For a given initial speed u, the maximum possible range is reached when sin 2θ is
maximum, sin 2θ = 1. This implies 2θ = π/2 or θ = π/4
This means that if the particle is projected at 45 degrees with respect to horizontal, it attains maximum range, given by
Rmax = \(\frac { u^{ 2 } }{ g } \).

Tamil Nadu 11th Physics Model Question Paper 3 English Medium

Question 37 (a).
Explain the work-energy theorem in detail and also give three examples?
Answer:

  1. If the work done by the force on the body is positive then its kinetic energy increases.
  2. If the work done by the force on the body is negative then its kinetic energy decreases.
  3. If there is no work done by the force on the body then there is no change in its kinetic energy, which means that the body has moved at constant speed provided its mass remains constant.
  4. When a particle moves with constant speed in a circle, there is no change in the kinetic energy of the particle. So according to work energy principle, the work done by centripetal force is zero.

[OR]

(b) (i) Define molar specific heat capacity?
Answer:
Molar specific heat capacity is defined as heat energy required to increase the temperature of one mole of substance by IK or 1°C

(ii) Derive Mayer’s relation for an ideal gas?

Mayer’s relation: Consider p mole of an ideal gas in a container with volume V, pressure P and temperature T.

When the gas is heated at constant volume the temperature increases by dT. As no work is done by the gas, the heat that flows into the system will increase only the internal energy. Let the change in internal energy be dU.

If CV is the molar specific heat capacity at constant volume, from equation.
CV = \(\frac { 1 }{ \mu } \) \(\frac{dU}{dT}\) …………………… (1)
dU = µCV dT ………………… (2)

Suppose the gas is heated at constant pressure so that the temperature increases by dT. If ‘Q’ is the heat supplied in this process and ‘dV’ the change in volume of the gas.
Q = pCpdT ……………. (3)

If W is the workdone by the gas in this process, then
W = P dV ………………….. (4)

But from the first law of thermodynamics,
Q = dU + W ………………… (5)

Substituting equations (2), (3) and (4) in (5), we get,
For mole of ideal gas, the equation of state is given by
\(\mu \mathrm{C}_{\mathrm{p}} d \mathrm{T}=\mu \mathrm{C}_{\mathrm{v}} d \mathrm{T}+\mathrm{P} d \mathrm{V}\)

Since the pressure is constant, dP = 0
CpdT = CVdT + PdV
∴ Cp = CV + R (or) Cp – CV = R …………………… (6)
This relation is called Mayer’s relation It implies that the molar specific heat capacity of an ideal gas at constant pressure is greater than molar specific heat capacity at constant volume.
The relation shows that specific heat at constant pressure (sp) is always greater than specific heat at constant volume (sv).

Tamil Nadu 11th Physics Model Question Paper 3 English Medium

Question 38 (a).
Derive an expression of pressure exerted by the gas on the walls of the container?
Answer:
Expression for pressure exerted by a gas : Consider a monoatomic gas of N molecules each having a mass m inside a cubical container of side l.
The molecules of the gas are in random motion. They collide with each other and also with the walls of the container. As the collisions are elastic in nature, there is no loss of energy, but a change in momentum occurs.

Tamil Nadu 11th Physics Model Question Paper 3 English Medium img 18

The molecules of the gas exert pressure on the walls of the container due to collision on it. During each collision, the molecules impart certain momentum to the wall. Due to transfer of momentum, the walls experience a continuous force. The force experienced per unit area of the walls of the container determines the pressure exerted by the gas. It is essential to determine the total momentum transferred by the molecules in a short interval of time.

A molecule of mass m moving with a velocity \(\vec { v } \) having components (vx, vy, vz) hits the right side wall. Since we have assumed that the collision is elastic, the particle rebounds with same speed and its x-component is reversed. This is shown in the figure. The components of velocity of the molecule after collision are (-vx, vy, vz).

The x-component of momentum of the molecule before collision = mvx
The x-component of momentum of the molecule after collision = – mvx
The change in momentum of the molecule in x direction
= Final momentum – initial momentum = – mvx – mvx = – 2mvx
According to law of conservation of linear momentum, the change in momentum of the wall = 2 mvx
The number of molecules hitting the right side wall in a small interval of time ∆t.

Tamil Nadu 11th Physics Model Question Paper 3 English Medium img 19

The molecules within the distance of vx∆t from the right side wall and moving towards the right will hit the wall in the time interval ∆t. The number of molecules that will hit the right side wall in a time interval ∆t is equal to the product of volume (Avx∆t) and number density of the molecules (n).

Here A is area of the wall and n is number of molecules per \(\frac{N}{V}\) unit volume. We have assumed that the number density is the same throughout the cube.

Not all the n molecules will move to the right, therefore on an average only half of the n molecules move to the right and the other half moves towards left side.

The number of molecules that hit the right side wall in a time interval ∆t
= \(\frac{n}{2}\) Avx∆t
In the same interval of time ∆t, the total momentum transferred by the molecules
\(\Delta \mathrm{P}=\frac{n}{2} \mathrm{A} v_{x} \Delta t \times 2 m v_{x}=\mathrm{A} v_{x}^{2} m n \Delta t\) ………………….. (2)
From Newton’s second law, the change in momentum in a small interval of time gives rise to force.

The force exerted by the molecules on the wall (in magnitude)
F = \(\frac{∆p}{∆t}\) = nmAv2x ……………………. (3)

Pressure, P = force divided by the area of the wall
P = \(\frac{F}{A}\) = nmAv2x ……………………….. (4)
p = \(nm\bar{v}_{x}^{2}\)

Since all the molecules are moving completely in random manner, they do not have same . speed. So we can replace the term vnmAv2x by the average \(\bar { v } \)2x in equation (4).
P = nm\(\bar { v } \)2x ……………………. (5)

Since the gas is assumed to move in random direction, it has no preferred direction of motion (the effect of gravity on the molecules is neglected). It implies that the molecule has same average speed in all the three direction. So, \(\bar{v}_{x}^{2}\) = \(\bar{v}_{y}^{2}\) = \(\bar{v}_{z}^{2}\). The mean square speed is written as
\(\bar{v}^{2}\) = \(\bar{v}_{x}^{2}\) + \(\bar{v}_{y}^{2}\) + \(\bar{v}_{z}^{2}\) = 3\(\bar{v}_{x}^{2}\)
\(\bar{v}_{x}^{2}\) = \(\frac{1}{3}\) \(\bar{v}^{2}\)
Using this in equation (5), we get
P = \(\frac{1}{3} n m \bar{v}^{2} \quad \text { or } P=\frac{1}{3} \frac{N}{V} m \bar{v}^{2}\) ………………….. (6)

[OR]

(b) Discuss the simple pendulum in detail?
Answer:
Simple pendulum

Tamil Nadu 11th Physics Model Question Paper 3 English Medium img 20

A pendulum is a mechanical system which exhibits periodic motion. It has a bob with mass m suspended by a long string (assumed to be massless and inextensible string) and the other end is fixed on a stand. At equilibrium, the pendulum does not oscillate and hangs vertically downward.

Such a position is known as mean position or equilibrium position. When a pendulum is displaced through a small displacement from its equilibrium position and released, the bob of the pendulum executes to and fro motion. Let l be the length of the pendulum which is taken as the distance between the point of suspension and the centre of gravity of the bob. Two forces act on the bob of the pendulum at any displaced position.

  • The gravitational force acting on the body (\(\vec { F} \) = m\(\vec { g } \)) which acts vertically downwards.
  • The tension in the string T which acts along the string to the point of suspension.

Resolving the gravitational force into its components:

  1. Normal component: The component along the string but in opposition to the direction of tension, Fas = mg cos θ.
  2. Tangential component: The component perpendicular to the string i.e., along tangential direction of arc of swing, Fps = mg sin θ.

Therefore, The normal component of the force is, along the string,
\(\mathrm{T}-\mathrm{W}_{a s}=m \frac{v^{2}}{l}\)

Here v is speed of bob
T -mg cos θ = m \(\frac{v^{2}}{l}\)

From the figure, we can observe that the tangential component Wps of the gravitational force always points towards the equilibrium position i.e., the direction in which it always points opposite to the direction of displacement of the bob from the mean position. Hence, in this case, the tangential force is nothing but the restoring force. Applying Newton’s second law along tangential direction, we have
\(m \frac{d^{2} s}{d t^{2}}+\mathrm{F}_{p s}=0 \Rightarrow m \frac{d^{2} s}{d t^{2}}=-\mathrm{F}_{p s}\)
\(m \frac{d^{2} s}{d t^{2}}=-m g \sin \theta\) …………………. (1)

where, s is the position of bob which is measured along the arc. Expressing arc length in terms of angular displacement i.e.,
s = lθ ………………… (2)
then its acceleration, \(\frac{d^{2} s}{d t^{2}}=l \frac{d^{2} \theta}{d t^{2}}\) …………………. (3)

Substituting equation (3) in equation (1), we get
\(\begin{aligned}
l \frac{d^{2} \theta}{d t^{2}} &=-g \sin \theta \\
\frac{d^{2} \theta}{d t^{2}} &=-\frac{g}{l} \sin \theta
\end{aligned}\) ………………….. (4)

Because of the presence of sin θ in the above differential equation, it is a non-linear differential equation (Here, homogeneous second order). Assume “the small oscillation approximation”, sin θ ~ 0, the above differential equation becomes linear differential equation.
\(\frac{d^{2} \theta}{d t^{2}}=-\frac{g}{l} \theta\) …………………… (5)

This is the well known oscillatory differential equation. Therefore, the angular frequency of this oscillator (natural frequency of this system) is
ω2 = \(\frac{g}{l}\) …………………… (6)
∴ ω = \(\sqrt{g/l}\) in rad s-1 ……………….. (7)

The frequency of oscillation is
f = \(f=\frac{1}{2 \pi} \sqrt{\frac{g}{l}} \text { in } \mathrm{Hz}\) ………………… (8)
and time period of sscillations is
T = 2π\(\sqrt{l/g}\) in second. ……………….. (9)

Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 3 The Age of Empires: Guptas and Vardhanas

Students can download 6th Social Science Term 3 History Chapter 3 The Age of Empires: Guptas and Vardhanas Questions and Answers, Notes, Samacheer Kalvi 6th Social Science Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 6th Social Science History Solutions Term 3 Chapter 3 The Age of Empires: Guptas and Vardhanas

Samacheer Kalvi 6th Social Science The Age of Empires: Guptas and Vardhanas Text Book Back Questions and Answers

I. Choose the correct Answer

Question 1.
………………. was the founder of Gupta dynasty.
(a) Chandragupta I
(b) Sri Gupta
(c) Vishnu Gopa
(d) Vishnugupta
Answer:
(b) Sri Gupta

Question 2.
Prayog Prashasti was composed by ________
(a) Kalidasa
(b) Amarasimha
(c) Harisena
(d) Dhanvantri
Answer:
(c) Harisena

Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 3 The Age of Empires: Guptas and Vardhanas

Question 3.
The monolithic iron pillar of Chandragupta is at ………………
(a) Mehrauli
(b) Bhitari
(c) Gadhva
(d) Mathura
Answer:
(a) Mehrauli

Question 4.
________ was the first Indian to explain the process Of surgery.
(a) Charaka
(b) Sushruta
(c) Dhanvantri
(d) Agnivasa
Answer:
(b) Sushrutal

Question 5.
……………… was the Gauda ruler of Bengal.
(a) Sasanka
(b) Maitraka
(c) Rajavardhana
(d) Pulikesin II
Answer:
(a) Sasanka

II. Match the statement with the reason and tick the appropriate answer

Question 1.
Assertion (A) : Chandragupta I crowned himself as a monarch of a large kingdom after eliminating various small states in Northern India.
Reason (R) : Chandragupta I married Kumaradevi of Lichchavi family.
(a) Both A and R are true and R is the correct explanation of A.
(b) Both A and R are correct but R is not correct explanation of A.
(c) A is correct but R is not correct.
(d) A is not correct but R is correct.
Answer:
(a) Both A and R are true and R is the correct explanation of A

Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 3 The Age of Empires: Guptas and Vardhanas

Question 2.
Statement I : Chandragupta II did not have cordial relationship with the rules of South India.
Statement II : The divine theory of kingship was practised by the Gupta rulers.
(a) Statement I is wrong but statement II is correct.
(b) Statement II is wrong but statement I is correct.
(c) Both the statements are correct.
(d) Both the statements are wrong.
Answer:
(a) Statement I is wrong but statement II is correct.

Question 3.
Which of the following is arranged in chronological order?
(a) Srigupta – Chandragupta I – Samudragupta – Vikramaditya
(b) Chandragupta I – Vikramaditya – Srigupta – Samudragupta
(c) Srigupta – Samudragupta – Vikramaditya – Chandragupta I
(d) Vikramaditya – Srigupta – Samudragupta – Chandragupta I
Answer:
(a) Srigupta – Chandragupta I – Samudragupta -Vikramaditya

Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 3 The Age of Empires: Guptas and Vardhanas

Question 4.
Consider the following statements and find out which of the following statements (s) is/are correct.
(1) Lending money at high rate of interest was practised.
(2) Pottery and mining were the most flourishing industries,
(a) 1. is correct
(b) 2. is correct
(c) Both 1 and 2 are correct
(d) Both 1 and 2 are wrong
Answer:
(a) 1. is correct

Question 5.
Circle the odd one
Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 3 The Age of Empires Guptas and Vardhanas
Answer:
Samudragupta.
Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 3 The Age of Empires Guptas and Vardhanas

Answer:
Harshacharita.

III. Fill in the blanks Answer

  1. ……………., the king of Ceylon, was a contemporary of Samudragupta.
  2. A Buddhist monk from China ……………., visited India during the reign of Chandragupta II.
  3. ……………. invasion led to the downfall of the Gupta Empire.
  4. ……………. was the main revenue to the Government.
  5. The official language of the Guptas was …………….
  6. ……………., the Pallava king was defeated by Samudragupta.
  7. ……………. was the popular king of the Vardhana dynasty.
  8. Harsha shifted his capital from ……………. to Kanauj.

Answer:

  1. Reign of
  2. Fahien
  3. Huns
  4. Land tax
  5. Sanskrit
  6. Vishnugopa
  7. Harsha Vardhana
  8. Thaneswar

IV. State whether True or False

  1. Dhanvantri was a famous scholar in the field of medicine.
  2. The structural temples built during the Gupta period resemble the Indo – Aryan style.
  3. Sati was not in practice in the Gupta Empire.
  4. Harsha belonged to the Hinayana school of thought.
  5. Harsha was noted for his religious intolerance.

Answer:

  1. True
  2. False
  3. False
  4. False
  5. False

V. Match the following

Question 1.
Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 3 The Age of Empires Guptas and Vardhanas
Answer:
b) 2, 4, 1, 3, 5

Question 2.
Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 3 The Age of Empires Guptas and Vardhanas
Answer:
c) 3, 5, 1, 2, 4

VI. Answer in one or two sentences

Question 1.
Who was given the title Kaviraja? Why?
Answer:

  1. The title Kaviraja was given to Samudragupta.
  2. He was a great lover of poetry and music.
  3. In one of the gold coins, he is portrayed playing the harp (Veenai)

Question 2.
What were the subjects taught at Nalanda University?
Answer:

  1. At Nalanda University Buddhism was the main subject of study.
  2. Other subjects like Yoga, Vedic literature, and medicine were also taught.

Question 3.
Explain the Divine Theory of Kingship.
Answer:

  1. The divine theory of Kingship meant that the king is the representative of God on earth.
  2. He is answerable only to God and not to anyone else.

Question 4.
Highlight the achievements of Guptas in metallurgy.
Answer:

  1. Mining and metallurgy were the most flourishing industries during the Gupta period.
  2. The most important evidence of development in metallurgy was the Mehrauli Iron Pillar installed by King Chandragupta in Delhi.
  3. This monolithic iron pillar has lasted through the centuries without rusting.

Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 3 The Age of Empires: Guptas and Vardhanas

Question 5.
Who were the Huns?
Answer:

  1. Huns were the nomadic tribe, who under their great Attila were terrorizing Rome and Constantinople.
  2. They came to India through Central Asia, defeated Skandagupta, and spread across central India.
  3. Their chief Toromana crowned himself asking.
  4. After him, his son Mihirakula ruled and got finally defeated by Yasodharman, ruler of Malwa.

Question 6.
Name the three kinds of tax collected during Harsha’s reign.
Answer:
A Bhaga, Hiranya, and Bali were three kinds of tax collected during Harsha’s reign.

Question 7.
Name the books authored by Harsha.
Answer:
The books authored by Harsha were Ratnavali, Nagananda, and Priyadharshika.

VII. Answer the following briefly

Question 1.
Write a note on Prashasti.
Answer:

  1. Prashasti is a Sanskrit word, meaning communication or in praise of.
  2. Court poets flattered their kings listing out their achievements.
  3. These accounts were later engraved on pillars so that the people could read them.

Question 2.
Give an account of Samudragupta’s military conquests.
Answer:

  1. Samudragupta was a great general and he carried on a vigorous campaign all over the country.
  2. He defeated the Pallava king Vishnugopa.
  3. He conquered nine kingdoms in northern India.
  4. He reduced 12 rulers of southern India to the status of feudatories and to pay tribute.
  5. He received homage from the rulers of East Bengal, Assam, Nepal, the eastern part of Punjab, and various tribes of Rajasthan.

Question 3.
Describe the land classification during the Gupta period.
Answer:
Classification of land during the Gupta period.

  1. Kshetra – Cultivable land
  2. Khila – Wasteland
  3. Aprahata – Jungle (or) Forest land
  4. Vasti – Habitable land
  5. Gapata saraha – Pastoral and

Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 3 The Age of Empires: Guptas and Vardhanas

Question 4.
Write about Sresti and Sarthavaha traders.
Answer:

  1. Sresti: Sresti traders were usually settled at a standard place.
  2. Sarthavaha: Sarthavaha traders caravan traders who carried their goods to different places.

Question 5.
Highlight the contribution of Guptas to architecture.
Answer:

  1. From the earlier tradition of rock – out shrines, the Guptas were the first to construct temples.
  2. These temples, adorned with towers and elaborate carvings, were dedicated to all Hindu deities.
  3. The most notable rock-cut caves are found at Ajanta and Ellora, Bagh, and Udaygiri.
  4. The structural temples built during this period resemble the Dravidian style.

Question 6.
Name the works of Kalidasa.
Answer:

  1. Kalidasa’s famous dramas were Sakunthala, Malavikagnimitra and Vikramaoorvashiyam.
  2. Other significant works were Meghaduta, Raghuvamsa, Kumarasambava and Ritusamhara

Question 7.
Estimate Harshvardhana as a poet and a dramatist.
Answer:

  1. Harsha himself was a poet and dramatist.
  2. Around him gathered the best of poets and artists.
  3. His popular works are Ratnavali, Nagananda and Priyadharshika
  4. is royal court was adorned by Banabhatta, Mayura, Hardatta, and Jayasena.

VIII. HOTs

Question 1.
The gold coins issued by Gupta kings indicate ………………
Answer:
(a) the availability of gold mines in the kingdom
(b) the ability of the people to work with gold
(c) the prosperity of the kingdom
(d) the extravagant nature of kings.
Answer:
(c) the prosperity of the kingdom

Question 2.
The famous ancient paintings at Ajanta were painted on __________
a. walls of caves
b. ceilings of temples
c. Rocks
d. papyrus
Answer:
a. walls of caves

Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 3 The Age of Empires: Guptas and Vardhanas

Question 3.
Gupta period is remembered for ……………….
(a) renaissance in literature and art
(b) expeditions to southern India
(c) invasion of Huns
(d) religious tolerance
Answer:
(a) renaissance in literature and art

Question 4.
What did Indian scientists achieve in astronomy and mathematics during the Gupta period?
Answer:

  1. The invention of zero and the consequent evolution of the decimal system was the legacy of Guptas to the modem world.
  2. Aryabhatta, Varahamihira, and Brahmagupta were the foremost astronomers and mathematicians of the time.
  3. Aryabhatta, in his book ‘ Surya Siddhanta’, explained the true causes of solar and lunar eclipses.
  4. He was the first Indian astronomer to declare that the earth revolves around its own axis.
  5. Dhanvantri was a famous scholar in the field of medicine.
  6. He was a specialist in Ayurveda.
  7. Charaka was a medical scientist.
  8. Susruta was the first Indian to explain the process of surgery.

IX. Student activity (For Students)

  1. Stage any one of the dramas of Kalidasa in the classroom.
  2. Compare and contrast the society of Guptas with that of Mauryas.

X. Life Skills (For Students)

  1. Collect information about the contribution of Aryabhatta, Varahamihira and Brahmagupta to astronomy.
  2. Visit a nearby ISRO centre to know more about satellite launching.

XI. Answer Grid

Question 1.
Who was Toromana?
Answer:
Toromana was the chief of White Huns.

Question 2.
Name the high-ranking officials of the Gupta Empire.
Answer:
Dandanayakas and Maha dandanayakas.

Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 3 The Age of Empires: Guptas and Vardhanas

Question 3.
Name the Gupta kings who performed AsVamedha yagna.
Answer:
Samudragupta and Kumaragupta I

Question 4.
Name the book which explained the causes for the lunar and solar eclipses,
Answer:
Surya Siddhanta

Question 5.
Name the first Gupta king to find a place on coins.
Answer:
Samudragupta

Question 6.
Which was the main source of information to know about the Samudragupta’s reign?
Answer:
Allahabad Pillar

Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 3 The Age of Empires: Guptas and Vardhanas

Question 7.
Harsha was the worshipper in the beginning.
Answer:
Shiva

Question 8.
University reached its fame during the Harsha period.
Answer:
The Nalanda

Samacheer Kalvi 6th Social Science The Post-Mauryan India Additional Important Questions and Answers

I. Choose the Correct Answer:

Question 1.
The successor of Sri Gupta ……………
(a) Kumaragupta I
(b) Skandagupta
(c) Vishnugupta
(d) Ghatotkacha
Answer:
(d) Ghatotkacha

Question 2.
Sri Gupta was succeeded by _______
(a) Chandra Gupta
(b) Samundra Gupta
(c) Ghatotkacha
(d) Skanda Gupta
Answer:
(c) Ghatotkacha

Question 3.
The Huhs chief crowned himself as king.
(a) Yasodharman
(b) Attila
(c) Mihirakula
(d) Toromana
Answer:
(d) Toromana

Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 3 The Age of Empires: Guptas and Vardhanas

Question 4.
Srimeghavarman was the ruler of _______
(a) Singapore
(b) Ceylon
(c) Malaysia
(b) Hansena
Answer:
(b) Ceylon

Question 5.
The place Harsha went to participate in the great Kumbhamela held.
(a) Allahabad
(b) Kasi
(c) Ayodhya
(d) Prayag
Answer:
(d) Prayag

II. Match the statement with the reason and tick the appropriate answer

Question 1.
Assertion (A) : The last of the great Guptas Narasimha Gupta I was paying tribute to Mihirakula.
Reason (R) : He stopped paying tribute to Mihirakula’s hostility towards Buddhism.
(a) Both A and R are true and R is the correct explanation of A.
(b) Both A and R are correct but R is not the correct explanation of A.
(c) A is correct but R is not correct
(d) A is not correct but R is correct
Answer:
(b) Both A and R are correct but R is not the correct explanation of A

Question 2.
Statement I : Criminal law was not more severe than that of the Gupta age.
Statement II : Death punishment was the punishment for violation of the laws and for plotting against the king.
(a) Statement I is wrong but statement II is correct
(b) Statement II is wrong but statement I is correct.
(c) Both the statements are correct.
(d) Both the statements are wrong.
Answer:
d) Both the statements are wrong

III. Fill in the blanks

  1. In the assembly at ……………. Harsha distributed his wealth.
  2. The capital of China ……………. was a great center of art and learning.
  3. ……………. was the wife of Chandragupta I.
  4. The military campaigns of kings were financed through revenue ……………..
  5. The peasants were required to pay various taxes and were reduced to the position of ……………..

Answer:

  1. Prayag
  2. Xian
  3. Kumaradevi
  4. Surpluses
  5. serfs

IV. Match the following

Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 3 The Age of Empires Guptas and Vardhanas
Answer:
b) 4, 5, 2, 1, 3

V. Answer in one or two sentences

Question 1.
Write a note on ‘Lichchhavi’.
Answer:

  1. Lichchhavi was an old gana – Sanga and its territory lay between the Ganges and the Nepal Terai.
  2. Chandragupta, I married Kumaradevi of the famous and powerful lichchhavi family.

Question 2.
How did Chandragupta I crown himself the monarch of a larger kingdom?
Answer:

  1. Chandragupta, I married Kumaradevi of the famous and powerful Lichchhavi family.
  2. With the support of this family, Chandragupta eliminated various small states and| crowned himself the monarch of a larger kingdom.

Question 3.
What did the travel accounts of Fahien provide information about the condi¬tions of the people of Magadha?
Answer:

  1. According to Fahien the people of Magadha were happy and prosperous.
  2. Gaya was desolated. Kapilvasthu had become a jungle, but at Pataliputra people were rich and prosperous.

VII. Answer the following briefly

Question 1.
Name the officials employed by the Gupta rulers.
Answer:

  1. High – ranking officials were called dandanayakas and mahadandnayakas.
  2. The provinces known as deshas or bhuktis were administered by the governors designated as Uparikas. The districts such as vaishyas, were controlled by vishyapatis. At the village level, gramika and gramadhyaksha were the functionaries.
  3. The military designations.
  4. Baladhikrita (Commander of infantry)
  5. Mahabaladhikrita (Commander of the cavalry)
  6. Dutakas (spies)

Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 3 The Age of Empires: Guptas and Vardhanas

Question 2.
Mention the importance of Fahien’s travel accounts.
Answer:

  1. During the reign of Chandragupta II, the Buddhist monk Fahien visited India.
  2. His travel accounts provided us information about the socio-economic, religious and moral conditions of the people of the Gupta age.
  3. According to Fahien, the people of Magadha were happy and prosperous.
  4. Justice was mildly administered and there was no death penalty.
  5. Gaya was desolated, Kapilavasthu had become a jungle, but at Pataliputra, people were rich and prosperous.

VIII. Mind map

Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 3 The Age of Empires Guptas and Vardhanas

Tamil Nadu 11th Maths Model Question Paper 4 English Medium

Students can Download Tamil Nadu 11th Maths Model Question Paper 4 English Medium Pdf, Tamil Nadu 11th Maths Model Question Papers helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

TN State Board 11th Maths Model Question Paper 4 English Medium

General Instructions:

  1. The question paper comprises of four parts.
  2. You are to attempt all the parts. An internal choice of questions is provided wherever applicable.
  3. All questions of Part I, II, III and IV are to be attempted separately.
  4. Question numbers 1 to 20 in Part I are Multiple Choice Questions of one mark each.
    These are to be answered by choosing the most suitable answer from the given four alternatives and writing the option code and the corresponding answer
  5. Question numbers 21 to 30 in Part II are two-mark questions. These are to be answered in about one or two sentences.
  6. Question numbers 31 to 40 in Part III are three-mark questions. These are to be answered in above three to five short sentences.
  7. Question numbers 41 to 47 in Part IV are five-mark questions. These are to be answered in detail Draw diagrams wherever necessary.

Time: 2:30 Hours
Maximum Marks: 90

PART – I

I. Choose the correct answer. Answer all the questions: [20 × 1 = 20]

Question 1.
If n(A) = 2 and n(B∪C) = 3 then n[(A × B) ∪ (A × C)] is ………………..
(a) 23
(b) 32
(c) 6
(d) 5
Answer:
(c) 6

Tamil Nadu 11th Maths Model Question Paper 4 English Medium

Question 2.
For any two sets A and B, A∩(A∪B) = …………………….
(a) B
(b) ∅
(c) A
(d) none of these
Answer:
(c) A

Question 3.
cos 1° + cos 2° + cos 3° + cos 4° + cos 179° = …………………
(a) 0
(b) 1
(c) -1
(d) 89
Answer:
(a) 0

Tamil Nadu 11th Maths Model Question Paper 4 English Medium

Question 4.
The value of log9 27 is ……………………
(a) \(\frac{2}{3}\)
(b) \(\frac{3}{2}\)
(c) \(\frac{3}{4}\)
(d) \(\frac{4}{3}\)
Answer:
(b) \(\frac{3}{2}\)

Question 5.
The value of \(\frac{\sin 3 \theta+\sin 5 \theta+\sin 7 \theta+\sin 9 \theta}{\cos 3 \theta+\cos 5 \theta+\cos 7 \theta+\cos 9 \theta}\) = ………………..
(a) tan3θ
(b) tan6θ
(c) cot3θ
(d) cot6θ
Answer:
(b) tan6θ

Question 6.
In 3 fingers the number of ways 4 rings can be worn in ……………………. ways.
(a) 43 – 1
(b) 34
(c) 68
(d) 64
Answer:
(d) 64

Tamil Nadu 11th Maths Model Question Paper 4 English Medium

Question 7.
Everybody in a room shakes hands with everybody else. The total number of shake hands is 66. The number of persons in the room is ……………….
(a) 11
(b) 12
(c) 10
(d) 6
Answer:
(b) 12

Question 8.
The H.M of two positive number whose AM and G.M. are 16, 8 respectively is ………………..
(a) 10
(b) 6
(c) 5
(d) 4
Answer:
(d) 4

Tamil Nadu 11th Maths Model Question Paper 4 English Medium

Question 9.
The co-efficient of the term independent of x in the expansion of (2x+\(\frac{1}{3x}\))6 is …………………
(a) \(\frac{160}{27}\)
(b) \(\frac{160}{27}\)
(c) \(\frac{80}{3}\)
(d) \(\frac{80}{9}\)
Answer:
(a) \(\frac{160}{27}\)

Question 10.
The value of \(\left|\begin{array}{lll}
a & 0 & 0 \\
0 & b & 0 \\
0 & 0 & c
\end{array}\right|^{2}\) is ………………..
(a) abc
(b) -abc
(c) 0
(d) a2b2c2
Answer:
(d) a2b2c2

Tamil Nadu 11th Maths Model Question Paper 4 English Medium

Question 11.
The value of x for which the matrix A = \(\left[\begin{array}{cc}
e^{x-2} & e^{7+x} \\
e^{2+x} & e^{2 x+3}
\end{array}\right]\) is singular is …………………..
(a) 9
(b) 8
(c) 7
(d) 6
Answer:
(b) 8

Question 12.
If |\(\vec { a } \) + \(\vec { b } \)| = 60, |\(\vec { a } \) – \(\vec { b } \)| = 40 and |\(\vec { b } \)| = 46 then |\(\vec { a } \)| is …………………
(a) 42
(b) 12
(c) 22
(d) 32
Answer:
(c) 22

Tamil Nadu 11th Maths Model Question Paper 4 English Medium

Question 13.
Given \(\vec { a } \) = 2\(\vec { i } \) + \(\vec { j } \) – 8\(\vec { k } \) and \(\vec { b } \) = \(\vec { i } \) + 3\(\vec { j } \) – 4\(\vec { k } \) then |\(\vec { a } \) + \(\vec { b } \)| = ………………….
(a) 13
(b) \(\frac{13}{3}\)
(c) \(\frac{4}{13}\)
(d) \(\frac{3}{13}\)
Answer:
(a) 13

Question 14.
If f(x) = \(\left\{\begin{array}{ccc}
k x & \text { for } & x \leq 2 \\
3 & \text { for } & 2
\end{array}\right.\) is continous at x = 2 then the value of k is ……………………
(a) \(\frac{3}{4}\)
(b) 0
(c) 1
(d) \(\frac{4}{3}\)
Answer:
(c) 1

Tamil Nadu 11th Maths Model Question Paper 4 English Medium

Question 15.
If f: R→R is defined by f(x) = |x – 3| + |x – 4| for x∈R then \(\lim _{x \rightarrow 3^{-}}\) f(x) is equal to ………………..
(a) -2
(b) -1
(c) 0
(d) 1
Answer:
(c) 0

Question 16.
\(\lim _{x \rightarrow \infty}\left(\frac{x^{2}+5 x+3}{x^{2}+x+3}\right)^{x}\) is ………………..
(a) e4
(b) e2
(c) e3
(d) 1
Answer:
(a) e4

Tamil Nadu 11th Maths Model Question Paper 4 English Medium

Question 17.
\(\int \frac{e^{x}\left(x^{2} \tan ^{-1} x+\tan ^{-1} x+1\right)}{x^{2}+1}\) dx is ………………..
(a) e tan-1(x + 1)
(b) tan-1(ex) + c
(c) ex \(\frac{\left(\tan ^{-1} x\right)^{2}}{2}\) + c
(d) extan-1x + c
Answer:
(d) extan-1x + c

Question 18.
∫ \(\frac { secx }{ \sqrt { cos2x } } \) dx = …………………..
(a) tan-1(sin x) + c
(b) 2 sin-1(tan x) + c
(c) tan-1(cos x) + c
(d) sin-1 (tan x) + c
Answer:
(d) sin-1 (tan x) + c

Tamil Nadu 11th Maths Model Question Paper 4 English Medium

Question 19.
\(\int \frac{e^{6 \log x}-e^{5 \log x}}{e^{4 \log x}-e^{3 \log x}}\) dx = ………………..
(a) x + c
(b) \(\frac { x^{ 3 } }{ 3 } \) + c
(c) \(\frac { 3 }{ x^{ 3 } } \) + c
(d) \(\frac { 1 }{ x^{ 2 } } \) + c
Answer:
(b) \(\frac { x^{ 3 } }{ 3 } \) + c

Question 20.
It is given that the events A and B are such that P(A) = \(\frac{1}{4}\), P(A/B) = \(\frac{1}{2}\), P(B/A) = \(\frac{2}{3}\) then P(B) = …………………
(a) \(\frac{1}{6}\)
(b) \(\frac{1}{3}\)
(c) \(\frac{2}{3}\)
(d) \(\frac{1}{2}\)
Answer:
(b) \(\frac{1}{3}\)

PART – II

II. Answer any seven questions. Question No. 30 is compulsory. [7 × 2 = 14]

Question 21.
In the set Z of integers, define mRn if m – n is a multiple of 12. Prove that R is an equivalence relation?
Answer:
As m – m = 0 and 0 = 0 × 12, we have 0 is a multiple of 12; hence mRm proving that R is reflexive.
Let mRn. Then m – n = 12k for some integer k; thus n – m = 12(-k) and hence nRm.
This shows that R is symmetric.
Let mRn and nRp: then m – n = 12k and n – p = 12l for some integers k and l.
So m – p = 12(k + l) and hence mRp. This shows that R is transitive.
Thus R is an equivalence relation.

Tamil Nadu 11th Maths Model Question Paper 4 English Medium

Question 22.
Simplify:
\(\frac { 1 }{ 2+\sqrt { 3 } } \) + \(\frac { 3 }{ 4-\sqrt { 5 } } \) + \(\frac { 6 }{ 7-\sqrt { 8 } } \)
Answer:
Tamil Nadu 11th Maths Model Question Paper 4 English Medium img 1

Question 23.
Find the value of sin 22 \(\frac{1}{2}\)°?
Answer:
We know that cos θ = 1 – 2 sin2 \(\frac{θ}{2}\) ⇒ sin \(\frac{θ}{2}\) = ±\(\sqrt { \frac { 1-cos2\theta }{ 2 } } \)
Take θ = 45°, we get sin \(\frac{45°}{2}\) = ±\(\sqrt { \frac { 1-cos45°}{ 2 } } \), (taking positive sign only, since 22\(\frac{1}{2}\)° lies in the first quadrant)
Thus, sin 22\(\frac{1}{2}\)° = \(\sqrt{\frac{1-\frac{1}{\sqrt{2}}}{2}}=\frac{\sqrt{2-\sqrt{2}}}{2}\).

Tamil Nadu 11th Maths Model Question Paper 4 English Medium

Question 24.
The number of bacteria in a certain culture doubles every hour. If there were 30 bacteria present in the culture originally, how many bacteria will be present at the end of 2nd hour, 4th
hour and wth hour?
Answer:
No. of bacteria at the beginning = 30
No. of bacteria after 1 hour = 30 × 2 = 60
No. of bactena after 2 hours = 30 × 22 = 30 × 4 = 120
No. of bacteria after 4 hours = 30 × 24 = 30 × 16 = 480
No. of bacteria after nth hour = 30 × 2n

Tamil Nadu 11th Maths Model Question Paper 4 English Medium

Question 25.
If the sum of the distance of a moving point in a plane from the axis is 1, then find the locus of the point?
Answer:
Let coordinates of a moving point P be (x, y).
Given that the sum of the distances from the axis to the point is always 1.
∴|x| + |y| = 1 ⇒ x + y = 1
⇒- x- y = 1 ⇒ x + y = 1
⇒ x – y = 1
Hence, these equations give us the locus of the point P which is a square.
Tamil Nadu 11th Maths Model Question Paper 4 English Medium

Question 26.
If (a, a + b, a + b + c) is one set of direction ratios of the line joining (1, 0, 0) and (0, 1, 0) then find a set of values of a, b, c?
Answer:
Let A be the point (1, 0, 0) and B be the point (0, 1, 0) (i.e.,) \(\overline { OA } \) = \(\hat { i } \) and \(\overline { OB } \) = \(\hat { j } \).
Then \(\overline { AB } \) = \(\overline { OB } \) – \(\overline { OA } \) = \(\hat { j } \) – \(\hat { i } \) = –\(\hat { i } \) + \(\hat { j } \)
= (-1, 1, 0)
= (a, a + b, a + b + c)
⇒ a = -1, a + b = 1 and a + b + c = 0
⇒ a = -1, ⇒ -1 + b = 1; a + b + c = 0
⇒ b = 2; -1 + 2 + c = 0 ⇒ c + 1 = 0
⇒ c = -1
∴ a = -1, b = 2, c = -1.
Note: if we taken \(\overline { BA } \) then we get a = 1, b = -2 and c = 1.

Tamil Nadu 11th Maths Model Question Paper 4 English Medium

Question 27.
Find \(\frac{dy}{dx}\) for y = (x2 + 4x + 6)5
Answer:
Let u = x2 + 4x + 6
⇒ \(\frac{du}{dx}\) = 2x + 4
Now y = u5 = \(\frac{dy}{du}\) = 5u4
∴ \(\frac{dy}{dx}\) = \(\frac{dy}{du}\) × \(\frac{du}{dx}\) = 5u4 (2x + 4)
= 5(x2 + 4x + 6)4 (2x + 4)
= 5(2x + 4) (x2 + 4x + 6)4

Question 28.
Evaluate ∫\(\sqrt { 25x^{ 2 }-9 } \) dx?
Answer:
Tamil Nadu 11th Maths Model Question Paper 4 English Medium

Question 29.
A bag contains 5 white and 7 black balls. 3 balls are drawn at random. Find the probability that

  1. all are white
  2. one white and 2 black.

Answer:
Number of white balls = 5
Number of black balls = 7
Total number of balls = 12
Selecting 3 from 12 balls can be done in
12C3 = \(\frac{12 \times 11 \times 10}{3 \times 2 \times 1}\) = 220 ways
∴n(S) = 220

1. Let A be the selecting 3 white balls.
∴n(A) = 5C3 = 5C2 = \(\frac{5×3}{2×1}\) = 10
∴P(A) = \(\frac{n(A)}{n(S)}\) = \(\frac{10}{220}\) = \(\frac{1}{22}\)

2. Let B be the event of selecting one white and 2 black balls.
∴n(B) = 5C1 × 7C2 = (5) (\(\frac{7×6}{2×1}\)) = 5(21) = 105
∴P(B) = \(\frac{n(B)}{n(S)}\) = \(\frac{105}{220}\) = \(\frac{21}{44}\).

Tamil Nadu 11th Maths Model Question Paper 4 English Medium

Question 30.
If (k, 2), (2, 4) and (3, 2) are vertices of the triangle of area 4 square units then determine the value of k?
Answer:
Area of ∆ with vertices (k, 2) (2, 4) and (3, 2) = \(\frac{1}{2}\) \(\left|\begin{array}{lll}
k & 2 & 1 \\
2 & 4 & 1 \\
3 & 2 & 1
\end{array}\right|\) = 4 given
⇒ \(\left|\begin{array}{lll}
k & 2 & 1 \\
2 & 4 & 1 \\
3 & 2 & 1
\end{array}\right|\) = 2(4) = 8
(i.e.,) k(4 – 2) – 2(2 – 3) + 1(4 – 12) ± 8
(i.e.,) 2k – 2(-1) + 1(-8) = ± 8
(i.e.,) 2k + 2 – 8 = 8
(i.e.,) 2k = 8 + 8 – 2 = 14
k = 14/2 = 7
∴k = 7
So k = 7 (or) k = -1.

2k + 2 – 8 = -8
⇒2k = – 8 + 8 – 2
2k = – 2
k = -1

PART – III

III. Answer any seven questions. Question No. 40 is compulsory. [7 × 3 = 21]

Question 31.
In the set Z of integers define mRn if m – n is a multiple of 12. Prove that R is an equivalence relation?

Question 32.
Prove that \(\frac{sin4x+sin2x}{cos4x+cos2x}\) = tan 3x?

Tamil Nadu 11th Maths Model Question Paper 4 English Medium

Question 33.
A polygon has 90 diagonals. Find the number of its sides?

Question 34.
If n is an odd positive integer, prove that the coefficients of the middle terms in the expansion of (x + y)n are equal?

Question 35.
Find the equation of the line passing through the point (1, 5) and also divides the co-ordinate axes in the ratio 3 : 10?

Tamil Nadu 11th Maths Model Question Paper 4 English Medium

Question 36.
Prove that \(\left|\begin{array}{ccc}
1 & x & x \\
x & 1 & x \\
x & x & 1
\end{array}\right|^{2}=\left|\begin{array}{ccc}
1-2 x^{2} & -x^{2} & -x^{2} \\
-x^{2} & -1 & x^{2}-2 x \\
-x^{2} & x^{2}-2 x & -1
\end{array}\right|\)

Question 37.
If G is the centroid of a traiangle ABC prove that \(\overline { GA } \) + \(\overline { GB } \) + \(\overline { GC } \) = 0

Tamil Nadu 11th Maths Model Question Paper 4 English Medium

Question 38.
Find \(\frac{dy}{dx}\) for y = \(\sqrt { 1+tan2x } \)?

Question 39.
Evaluate \(\frac { \sqrt { x } }{ 1+\sqrt { x } } \) dx?

Question 40.
Find the relation between a and b if \(\underset { x\rightarrow 3 }{ lim } \) f(x) exists where f(x) = \(\left\{\begin{array}{cc}
a x+b & \text { if } x>3 \\
3 a x-4 b+1 \text { if } x<3
\end{array}\right.\)

PART – IV

IV. Answer all the questions. [7 × 5 = 35]

Question 41 (a).
From the curve y = |x|, draw(i) y = |x-1| + 1

  1. y = |x + 1| + 1
  2. y = |x + 2| – 3

[OR]

(b) Resolve into partial fraction \(\frac { x+4 }{ (x^{ 2 }-4)(x+1) } \)

Tamil Nadu 11th Maths Model Question Paper 4 English Medium

Question 42 (a).
Find the number of positive integers greater than 6000 and less than 7000 which arc divisible by 5, provided that no digit is to be repeated?

[OR]

(b) If nPr = nPr+1 and nCr = nCr-1, find the values of n and r?

Question 43 (a).
In a ∆ABC, prove that b2 sin 2C + c2 sin 2B = 2bc sin A?

[OR]

(b) Differentiate the following s(t) = \(\sqrt[4]{\frac{t^{3}+1}{t^{3}-1}}\)?

Tamil Nadu 11th Maths Model Question Paper 4 English Medium

Question 44 (a).
Find the equation of the lines make an angle 60° with the positive x axis and at a distance 5\(\sqrt{2}\) units measured from the point (4, 7) along the line x – y + 3 = 0

[OR]

(b) If y = A cos4x + B sin 4x, A and B are constants then Show that y2 + 16y = 0

Tamil Nadu 11th Maths Model Question Paper 4 English Medium

Question 45 (a).
Find the sum up to the 17th term of the series \(\frac{1^{3}}{1}+\frac{1^{3}+2^{3}}{1+3}+\frac{1^{3}+2^{3}+3^{3}}{1+3+5}\) + …………..

[OR]

(b) A shopkeeper in a Nuts and Spices shop makes gifi packs of cashew nuts, raisins and almonds?

  1. Pack I contains 100 gm of cashew nuts, 100 gm of raisins and 50 gm of almonds.
  2. Pack-II contains 200 gm of cashew nuts, 100 gm of raisins and 100 gm of almonds.
  3. Pack-III contains 250 gm of cashew nuts, 250 gm of raisins and 150 gm of almonds.
  4. The cost of 50 gm of cashew nuts is ₹50, 50 gm of raisins is ₹10. and 50gm of almonds is ₹60. What is the cost of each gift pack?

Tamil Nadu 11th Maths Model Question Paper 4 English Medium

Question 46 (a).
Find matrix C if A = \(\begin{bmatrix} 3 & 7 \\ 2 & 5 \end{bmatrix}\), B = \(\begin{bmatrix} -3 & 2 \\ 4 & -1 \end{bmatrix}\) and 5C + 28= A?

[OR]

(b) The probability that a new railway bridge will get an award for its design is 0.48, the probability that it will get an award for the efficient use of materials is 0.36, and that it will get both awards is 0.2. What is the probability, that

  1. it will get at least one of the two awards
  2. it will get only one of the awards.

Tamil Nadu 11th Maths Model Question Paper 4 English Medium

Question 47 (a).
\(\underset { \alpha \rightarrow 0 }{ lim } \) \(\frac { sin(\alpha ^{ n }) }{ (sin\alpha )^{ m } } \)

[OR]

(b) Evaluate I = sin-1 (\(\frac { 2x }{ (1+x)^{ 2 } } \)) dx?

Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 2 The Post-Mauryan India

Students can download 6th Social Science Term 3 History Chapter 2 The Post-Mauryan India Questions and Answers, Notes, Samacheer Kalvi 6th Social Science Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 6th Social Science History Solutions Term 3 Chapter 2 The Post-Mauryan India

Samacheer Kalvi 6th Social Science The Post-Mauryan India Text Book Back Questions and Answers

I. Choose the correct answer

Question 1.
The last Mauryan emperor was killed by ……………
(a) Pushyamitra
(b) Agnimitra
(c) Vasudeva
(d) Narayana
Answer:
(a) Pushyamitra

Question 2.
___________ was the founder Of Satavahana dynasty.
(a) Simuka
(b) Satakarani
(c) Kanha
(d) Sivasvati
Answer:
(a) Simuka

Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 2 The Post-Mauryan India

Question 3.
…………… was the greatest of all the Kushana emperors.
(a) Kanishka
b) Kadphises I
(c) Kadphises II
(d) Pan – Chiang
Answer:
(a) Kanishka

Question 4.
The Kantara School of Sanskrit flourished in the
(a) Deccan
(b) North-west India
(c) Punjab
(d) Gangetic valley
Answer:
(a) Deccan

Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 2 The Post-Mauryan India

Question 5.
Sakas ruled over Gandhara region …………… as their capital.
(a) Sirkap
(b) Taxila
(c) Mathura
(d) Purushpura
Answer:
(a) Sirkap

II. Match the statement with the reason and tick the appropriate answer

Question 1.
Assertion (A) : Colonies of Indo – Greeks and Indo – Parthians were established along the north-western part of India.
Reason (R) : The Bactrian and Parthian settlers gradually intermarried and intermixed with the indigenous population.
(a) Both A and R are correct and R is the correct explanation of A.
(b) Both A and R are correct but R is not the correct explanation of A.
(c) A is correct but R is not correct.
(d) A is not correct but R is correct
Answer:
(a) Both A and R are correct and R is the correct explanation of A

Question 2.
Statement I : Indo – Greek rulers introduced die system and produced coins with inscription and symbols, engraving figures on them.
Statement II : Indo – Greek rule was ended by the Kushanas.
(a) Statement I is wrong, but statement II is correct.
(b) Statement II is wrong, but statement I is correct
(c) Both the statements are correct.
(d) Both the statements are wrong.
Answer:
(b) Statement II is wrong, but statement I is correct

Question 3.
Circle the odd one
Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 2 The Post-Mauryan India
Answer:
Kanishka

Question 4.
Answer the following in a word:

Question 1.
Who was the last Sunga ruler?
Answer:
Devabhuti

Question 2.
Who was the most important and famous king of Sakas?
Answer:
Rudradaman

Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 2 The Post-Mauryan India

Question 3.
Who established Kanva dynasty in Magadha?
Answer:
Vasudeva

Question 4.
Who converted Gondophemes into Christianity?
Answer:
St.Thomas

III. Fill in the blanks

  1. …………… was the founder of Indo – Parthian Kingdom.
  2. In the South, Satavahanas became independent after …………… death.
  3. Hala is famous as the author of ……………
  4. …………… was the last ruler of Kanva dynasty.
  5. Kushana’s later capital was ……………

Answer:

  1. Arsaces
  2. Susarman
  3. Sattasai (Saptasati)
  4. Susarman
  5. Peshawar(Purushpura)

IV. State whether True or False Answer

  1. Magadha continued to be a great centre of Buddhist culture True even after the fall of the Mauryan Empire.
  2. We get much information about Kharavela from Hathigumba True inscription.
  3. Simuka waged a successful war against Magadha.
  4. Buddhacharita was written by Asvaghosha.

Answer:

  1. True
  2. True
  3. False
  4. True

V. Match the following

Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 2 The Post-Mauryan India
Answer:
b) 3451 2

VI. Find out the wrong statement from the following

(1) The Kushanas formed a section of the yueh-chi tribes who inhabited north-western China.
(2) Kanishka made Jainism the state religion and built many monasteries.
(3) The Great Stupa of Sanchi and the railings which enclose it belog to the Sunga period.
(4) Pan – Chiang was the Chinese general defeated by Kanishka.
Answer:
2) Kanishka made Jainism the state religion and built many monasteries.

VII. Answer in one or two sentences

Question 1.
What happened to the last Mauryan emperor?
Answer:

  1. The last Mauryan emperor was Brihadratha.
  2. He was assassinated by his own general, Pushyamitra Sunga.

Question 2.
Write a note on Kalidasa’s Malavikagnimitra.
Answer:

  1. Pushyamitra’s son Agnimitra is said to be the hero of Kalidasa’s Malavikagnimitra.
  2. This drama also refers to the victory of Vasumitra, Agnimitra’s son, over the
    Greeks on the banks of the Sindhu river.

Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 2 The Post-Mauryan India

Question 3.
Name the ruler of Kanva dynasty.
Answer:

  1. Vasudeva
  2. Bhumi Mitra
  3. Narayana
  4. Susarman.

Question 4.
Highlight the literary achievements of Satavahanas.
Answer:

  1. The Satavahana king Hala was himself a great scholar of Sanskrit.
  2. The Kantara school of Sanskrit flourished in the Deccan in Second Century B.C.
  3. Hala is famous as the author of Sattasai (Saptasati), 700 stanzas in Prakrit.

Question 5.
Name the places where Satavahana’smounments are situated.
Answer:

  1. Gandhara
  2. Madhura
  3. Amaravati
  4. BodhGaya
  5. Sanchi
  6. Bharhut

Question 6.
Give an account of the achievements of Kadphises
Answer:

  1. Kadphises I was the first famous military and political leader of the Kushanas.
  2. He overthrew the Indo-Greek and Indo-Parthian rulers.
  3. He established himself as a sovereign ruler of Bactria.
  4. He extended his power in Kabul, Gandhara and up to the Indus.

Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 2 The Post-Mauryan India

Question 7.
Name the Buddhist saints and scholars who adorned the court of Kanishka
Answer:

  1. Asvaghosha
  2. Vasumitra
  3. Nagarjuna

VIII. Answer the following

Question 1.
Who invaded India after the decline of the Mauryan empire.
Answer:

  1. The break-up of the Mauryan empire resulted in the invasions of Sakas, Scythians, Parthians, Indo-Greeks or Bactria Greeks, and Kushanas from the north-west.
  2. In the South, Satavahanas became independent after Asoka’s death.
  3. There were Sunga and Kanvas in the north before the emergence of the Gupta dynasty.
  4. Chedis (Kalinga) declared their independence.
  5. Though Magadha ceased to be the premier state of India, it continued to be a great center of Buddhist culture.

Question 2.
Give an account of the conquests of Pushyamitra Sunga.
Answer:

  1. The last Mauryan emperor, Brihadratha, was assassinated by his own general, Pushyamitra Sunga.
  2. He established his Sunga dynasty in Magadha. His capital was Pataliputra.
  3. Pushyamitra successfully repulsed the invasion of Bactria king Menander. He also conquered Vidarbha.
  4. He was a staunch follower of Vedic religion. He performed two Asvamedbayagnas (horse sacrifices) to assert his imperial authority.

Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 2 The Post-Mauryan India

Question 3.
Write a note on GautamiputraSatakarni
Answer:

  1. GautamiputraSatakarni was the greatest ruler of the family.
  2. In the Nasik prashasti, published by his mother GautamiBalasri, Gautamiputra Satakami is described as the destroyer of Sakas, Yavanas (Greeks), and Pahlavis (Parthians).
  3. The extent of the empire is also mentioned in the record.
  4. Their domain included Maharashtra, north Konkan, Berar, Gujarat, Kathiawar, and Malwa.
  5. His ship coins are suggestive of Andhras’ skill in seafaring and their naval power.
  6. The Bogor inscriptions suggest that South India played an important role in the process of early state formation in Southeast Asia.

Question 4.
What do you know of the Gondopharid dynasty?
Answer:

  1. Indo-Parthians came after the Indo-Greeks and the Indo-Scythians who were, in turn, defeated by the Kushanas in the second half of the first century A.D.
  2. Indo-Parthian kingdom or Gondopharid dynasty was founded by Gondophemes.
  3. The domain of Indo-Parthians comprised Kabul and Gandhara.
  4. The name of Gonodophemes is associated with the Christian apostle St. Thomas.
  5. According to Christian tradition, St.Thomas visited the court of Gondophemes and converted him to Christianity.

Question 5.
Who was considered the best known Indo-Greek king? Why?
Answer:

  1. Menander was one of the best known Indo-Greek kings.
  2. He is said to have ruled a large kingdom in the north-west of the country.
  3. His coins were found over an extensive area ranging from Kabul valley and Indus river to western Uttar Pradesh.
  4. MilindaPanha, a Buddhist text, is a discourse between Bactrian king Milinda and the learned Buddhist scholar Nagasena.
  5. This Milinda is identified with Menander.
  6. Menander is believed to have become a Buddhist and promoted Buddhism.

Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 2 The Post-Mauryan India

Question 6.
Who was Sakas?
Answer:

  1. The Indo-Greek rule in India was ended by the Sakas. Sakas as nomads came in huge number and spread all over northern and western India.
  2. The Sakas were against the tribe of Turki nomads.
  3. Sakas were Scythians, nomadic ancient Iranians, and known as Sakas in Sanskrit.
  4. Saka rule was founded by Maos or Mogain in the Gandhara region and his capital was ‘Sirkap’. His name is mentioned in Mora inscription. His coins bear images of Buddha and Siva.
  5. Rudradaman was the most important and famous king of Sakas. His Junagadh/ Gimar inscription was the first inscription in chaste Sanskrit.
  6. In India, the Sakas were assimilated into Indian society. They began to adopt Indian names and practice Indian religious beliefs.
  7. The Sakas appointed kshetras or satraps as provincial governors to administer their territories.

Question 7.
Give an account of the religious policy of Kanishka.
Answer:

  1. Kanishka was an ardent Buddhist.
  2. His empire was a Buddhist empire.
  3. He adopted Buddhism under the influence of Asvaghosha, a celebrated monk from Pataliputra.
  4. He was as equal as the exponent and champion of Mahayanism.
  5. He made Buddhism the state religion.
  6. He built many stupas and monasteries in Mathura, Taxila, and many other parts of his kingdom.
  7. He sent Buddhist missionaries to Tibet, China, and many countries of Central Asia for the propagation of Buddha’s gospel.
  8. He organised the fourth Buddhist Council at Kundalavana near Srinagar to sort out the differences between the various schools of Buddhism. It was only in this council that Buddhism was split into Hinayanism and Mahayanism.

IX. HOTS

Question 1.
The importance of the Gandhara School of Art.
Answer:

  1. The Gandhara School of Indian Art is heavily indebted to Greek influence.
  2. The Greeks were good cave builders.
  3. The Mahay ana Buddhists learnt the art of carving out caves from them.
  4. They became skilled in rock-cut architecture.
  5. This Gandhara art flourished during Kanishka time. The most favourite subject was the carving of Sculptures of Buddha.

Question 2.
Provide an account of trade and commerce during the Post-Mauryan period in South India.
Answer:

  1. Kadphises II maintained a friendly relationship with the emperors of China and Rome.
  2. He encouraged trade and commerce with foreign countries.
  3. His coins contained the inscribed figures of Lord Siva and his imperial titles.
  4. The inscriptions in the coins were in the Kharosthi language.

X. Activity (For Students)

  1. Prepare an album with centres of archaeological monuments of Satavahanas and Kushanas.
  2. Arrange a debate in the classroom on the cultural contribution of Indo-Greeks, Sakas, and Kushanas.

XI. Answer Grid

Question 1.
Who wrote Brihastkatha?
Answer:
Gunadhya

Question 2.
Name the Satavahana ruler who performed two Asvamedha sacrifices.
Answer:
Satakarni

Question 3.
How many years did the Satavahanas rule the Deccan?
Answer:
450 years

Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 2 The Post-Mauryan India

Question 4.
Who laid the foundation of the Saka era?
Answer:
Mao’s (or) Mogain

Question 5.
What was the favourite subject of Gandhara artists?
Answer:
Carving of Sculptures of Buddha

Question 6.
Where did Kanishka organise the fourth Buddhist Council?
Answer:
Kundalavana (near Srinagar)

Samacheer Kalvi 6th Social Science The Post-Mauryan India Additional Important Questions and Answers

I. Choose the Correct Answer:

Question 1.
The Chinese Buddhist monk and traveller who wrote si-yu-ki …………….
(a) Fahien
(b) Hiuen Tsang
(c) Yuch – Chi
(d) Pan – Chiang
Answer:
(b) Hiuen Tsang

Question 2.
Asvahosha wrote
(a) Brihastkatha
(b) Mahabhasya
(c) Buddhacharita
(d) Harshacharita
Answer:
(c) Buddhacharita

Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 2 The Post-Mauryan India

Question 3.
During the Sunga period stone was replaced by railings.
(a) wood
(b) iron
(c) copper
(d) brick
Answer:
(a) wood

Question 4.
MilindaPanha is a Buddhist
(a) Statue
(b) Cave
(c) Text
(d) Monastry
Answer:
(c) Text

Question 5.
……………. gradually gained ascendancy and became the court language.
(a) Sanskrit
(b) Kharasthi
(c) Kannada
(d) Prakrit
Answer:
(a) Sanskrit

II. Match the statement with the reason and tick the appropriate answer

Question 1.
Assertion (A): The Greek rulers of Bactria and Parthia started encroaching into the northwestern borderlands of India.
Reason (R): There was a decline in the Mauryan empire.
(a) Both A and R are correct and R is the correct explanation of A.
(b) Both A and R are correct and R is not the correct explanation of A.
(c) A is correct but R is not correct.
(d) Both the statements are wrong.
Answer:
(a) Both A and R are correct and R is the correct explanation of A

Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 2 The Post-Mauryan India

Question 2.
Statement I: The Mahayana Buddhists learned the art of carving out caves from the Greeks.
Statement II: The Greeks were good cave builders.
(a) Statement I is wrong, but statement II is correct.
(b) Statement II is wrong, but the statement I is correct.
(c) Both the statements are correct.
(d) Both the statements are wrong.
Answer:
(c) Both the statements are correct.

III. Fill in the blanks

  1. Simuka’s successor was his brother …………….
  2. A bronze statue of the standing Buddha was discovered in …………….
  3. The Indo – Greek rule in India was ended by the ……………..
  4. The Saka ruler Mogain’s capital was ……………..
  5. Rudradaman’s ……………. inscription was the first inscription in chaste Sanskrit.

Answer:

  1. Krishna
  2. OC – EO
  3. Sakas
  4. Sirkap
  5. Junagadh / Girnar

IV. True or False

  1. Satakarni was Simuka’s nephew.
  2. A stone seal discovered in Nakhon Pathom was in Thailand.
  3. Mao’s name is mentioned in the Mora inscription.
  4. The Kushanas appointed satraps as provincial governors.
  5. Kushana rulers were Buddhists.

Answer:

  1. True
  2. True
  3. True
  4. False
  5. True

V. Answer in one or two sentences

Question 1.
Write a short note on king Kharavela of Kalinga
Answer:

  1. King Kharavela was a contemporary of the Sungas.
  2. Hathigumba Inscription gave information about Kharavela.

Question 2.
Who laid the foundation of the Satavahana dynasty?
Answer:

  1. The last Kanva ruler Susarman was assassinated by his powerful feudatory chief of Andhra named Simuka.
  2. Simuka laid the foundation of the Satavahana dynasty.

Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 2 The Post-Mauryan India

Question 3.
How did the Sakas assimilate into Indian Society?
Answer:

  1. The Sakas began to adopt Indian names.
  2. They practiced Indian religious beliefs.

Question 4.
Under whom did the satrapies Bactria and Parthia become independent,
Answer:
Satrapies Bactria became independent under the leadership of Diodotus I and Parthia under Arsaces.

VII. Answer the following

Question 1.
Write a note on the Conquests of Kanishka.
Answer:

  1. Kanishka conquered and annexed Kashmir.
  2. He waged a successful war against Magadha.
  3. He also waged a war against a ruler of Parthia to maintain safety and integrity in his vast empire on the western and south-western border.
  4. After the conquest of Kashmir and Gandhara, he turned his attention towards China.
  5. He defeated the Chinese general Pan-Chiang and safeguarded the northern borders of India from Chinese intrusion.
  6. His empire extended from Kashmir down to Benaras, and the Vindhya mountain in the south. It included Kashgar, Yarkand touching the borders of Persia and Parthia.

VIII. Mind map

Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 2 The Post-Mauryan India

Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 1 Society and Culture in Ancient Tamizhagam: The Sangam Age

Students can download 6th Social Science Term 3 History Chapter 1 Society and Culture in Ancient Tamizhagam: The Sangam Age Questions and Answers, Notes, Samacheer Kalvi 6th Social Science Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 6th Social Science History Solutions Term 3 Chapter 1 Society and Culture in Ancient Tamizhagam: The Sangam Age

Samacheer Kalvi 6th Social Science Society and Culture in Ancient Tamizhagam: The Sangam Age Text Book Back Questions and Answers

I. Choose the correct answer

Question 1.
Pattini cult in Tamil Nadu was introduced by …………….
(a) PandyanNeduncheliyan
(b) CheranSenguttuvan
(c) IlangoAdigal
(d) Mudathirumaran
Answer:
(b) CheranSenguttuvan

Question 2.
Which dynasty was not in power during the Sangam Age?
(a) Pandyas
(b) Cholas
(c) Pallavas
(d) Cheras
Answer:
(c) Paliavas

Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 1 Society and Culture in Ancient Tamizhagam: The Sangam Age

Question 3.
The rule of Pandyas was followed by ……………..
(a) Satavahanas
(b) Cholas
(c) Kalabhras
(d) Pallavas
Answer:
(c) Kalabhras

Question 4.
The lowest unit of administration during the Sangam Age was
(a) Mandalam
(b) Nadu
(c) Ur
(d) Pattinam
Answer:
(c) Ur

Question 5.
What was the occupation of the inhabitants of the Kurinji region?
(a) Plundering
(b) Cattle rearing
(c) Hunting and gathering
(d) Agriculture
Answer:
(c) Hunting and gathering

II. Read the statement and tick the appropriate answer

Question 1.
Assertion (A) : The assembly of the poets was known as Sangam.
Reason (R) : Tamil was the language of Sangam literature.
(a) Both A and R are true. R is the correct explanation of A.
(b) Both A and R are true. R is not the correct explanation of A.
(c) A is true but R is false.
(d) Both A and R is not true.
Answer:
(a) Both A and R are true. R is the correct explanation of A

Question 2.
Which of the following statements are not true?
a. Karikala won the battle of Talayalanganam.
b. The Pathitrupathu provides information about Chera Kings.
c. The earliest literature of the Sangam age was written mostly in the form of prose
a. 1 only
b. 1 and 3 only
c. 2 only
Answer:
(b) 1 and 3 only

Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 1 Society and Culture in Ancient Tamizhagam: The Sangam Age

Question 3.
The ascending order of the administrative division in the ancient Tamizhagam was
(a) Ur < Nadu < Kurram < Mandalam
(b) Ur < Kurram < Nadu < Mandalam
(c) Ur < Mandalam < Kurram < Nadu
(d) Nadu < Kurram < Mandalam < Ur
Answer:
(b) Ur < Kurram < Nadu < Mandalam

Question 4.
Match the following dynasties with the Royal Insignia
Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 1 Society and Culture in Ancient Tamizhagam The Sangam Age
Answer:
A) 3 2 1

III. Fill in the blanks

  1. The battle of Venni was won by ………………
  2. The earliest Tamil grammar work of the Sangam period was ………………
  3. ……………… built Kallanai across the river Kaveri.
  4. The chief of the army was known as ……………….
  5. Land revenue was called ………………

Answer:

  1. Karikal Valavan
  2. Tholkappiyam
  3. Karikalan
  4. Thanai thalaivan
  5. Irai

IV. True or False

  1. Caste system developed during the Sangam period.
  2. Kizhar was the village chief.
  3. Puhar was the general term for city.
  4. Coastal region was called Marudham.

Answer:

  1. False
  2. True
  3. False
  4. False

V. Match

Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 1 Society and Culture in Ancient Tamizhagam The Sangam Age

Answer:
1. – d
2. – a
3. – b
4. – c

VI. Answer in one or two sentences

Question 1.
Name any two literary sources to reconstruct the history of ancient Tamizhagam?
Answer:
Tholkappiyam, Ettuthogai, and Patthupattu are some of the literary sources to reconstruct the history of ancient Tamizhagam.

Question 2.
What was Natukkal or Virakkal?
Answer:

  1. The ancient Tamils had great respect for the heroes who died on the battlefield.
  2. The hero stones were created to commemorate heroes who sacrificed their lives in war. These hero stones were known as Natukkal or Virakkal.

Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 1 Society and Culture in Ancient Tamizhagam: The Sangam Age

Question 3.
Name five things mentioned in the Sangam literature.
Answer:

  1. Kurinji.
  2. Mullai.
  3. Marutham.
  4. Neithal.
  5. Palai.

Question 4.
Name any two archaeological sites related to Sangam period.
Answer:
The excavated materials from Adichanallur, Arikamedu, Kodumanal, Puhar, Korkai, Alankulam, Urariyur etc.

Question 5.
Name the seven patrons (KadaiyeluVallalgal).
Answer:
The seven patrons were

  1. Pari
  2. Kari
  3. Ori
  4. Pegan
  5. Ay
  6. Adiyaman
  7. Nalli

Question 6.
Name any three Tamil poetic works of Kalahhra period.
Answer:
Periapuranam, Seevakachinthamani, and Kundalakesi were written during the Kalabhra

VII. Answer the following

Question 1.
Discuss the status of women in the Sangam Society.
Answer:

  1. In the Sangam Society, there were learned and wise women.
  2. Forty women poets had lived
  3. Marriage was a matter of choice.
  4. Chastity (Karpu) was considered the highest virtue.
  5. In their Parents’ property sons and daughters had equal shares.

VIII. HOTS

Question 1.
KarikalValavan is regarded as the greatest Chola king. Justify.
Answer:

  1. KarikalValavan or Karikalan was the most famous of the Chola kings.
  2. He defeated the combined army of the Cheras, Pandyas and the eleven Velir Chieftains who supported them at Venni, a small village in the Thanjavur region.
  3. He converted forests into cultivable lands.
  4. He built Kallanai across the river Kaveri to develop agriculture.
  5. Their port Puhar attracted merchants from various regions of the Indian Ocean.
  6. The Pattinapaalai a poetic work in the pathinenkeezhkanakku gives elaborate information of the trading activity during the rule of Karikalan.

Question 2.
The period ilabhra is not a dark age. Give reasons.
Answer:

  1. Following the Sangam period, the Kalabhras had occupied Tamil Country for about two and half centuries.
  2. There is evidence of their rule in literary texts.
  3. The literary sources for this period include Tamil Navalar Charithai, Yapemkalam and Periapuranam.
  4. Seevakachinthamani and Kundalakesi were also written during this period.
  5. In Tamizhagam, Jainism and Buddhism became prominent during this period
  6. Introduction of Sanskrit and Prakrit languages had resulted in the development of a new script called Vattezhuththu.
  7. Many works under Pathinenkeezhkanakku were composed.
  8. Trade and commerce continued to flourish during this period.
  9. So the Kalabhra period is not a dark age, as it is portrayed.

X. Life skill (For Students)

Collect and paste the pictures of landscape and find out the eco – region to which belongs. Write the important crops grown and occupation of the people there.

XI. Answer Grid

Question 1.
Mention two epics of the Sangam period.
Answer:

  1. Silapathikaram
  2. Manimegalai

Question 2.
Name the two groups of officials who assisted the king.
Answer:

  1. Aimperunguzhu
  2. Enberayam

Question 3.
Name any two women poets of the Sangam period.
Answer:

  1. Awaiyar, Velli
  2. Veethiyar

Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 1 Society and Culture in Ancient Tamizhagam: The Sangam Age

Question 4.
Name any three major ports of Sangam age.
Answer:

  1. Musiri
  2. Tondi
  3. Korkai

Question 5.
What constituted Muthamizh?
Answer:

  1. Iyal
  2. Isai
  3. Naatakam

Question 6.
Silapathikaram was written by ……………
Answer:
Ilango Adigal

Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 1 Society and Culture in Ancient Tamizhagam: The Sangam Age

Question 7.
Talayalanganam is related to whish Pandya king?
Answer:
Nedunchezhiyan

Question 8.
Which ecoregion was called menpulam?
Answer:
Marutham

Question 9.
The lighthouses in the ports are called ……………
Answer:

  1. Kalangari
  2. flangu Sudar

Samacheer Kalvi 6th Social Science Society and Culture in Ancient Tamizhagam: The Sangam Age Additional Important Questions and Answers

I. Choose the Correct Answer:

Question 1.
According to Prof.George L.Hart Tanial is as old as ……………
(a) Chinese
(b) Greek
(c) Latin
(d) English
Answer:
(c) Latin

Question 2.
The epic character from Silappathikaram
(a) Pallavas
(b) Cheras
(c) Pandyas
(d) Cholas
Answer:
(d) Cholas

Question 3.
…………… is the port of Pandvas.
(a) Puhar
(b) Korgai
(c) Muziri
(d) Tondi
Answer:
(b) Korgai

Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 1 Society and Culture in Ancient Tamizhagam: The Sangam Age

Question 4.
Bow and arrow as the symbol of
(a) Kalabhras
(b) Cholas
(c) Cheras
(d) Pandyas
Answer:
(c) Cheras

II. Read the statement and tick the appropriate answer

Question 1.
Assertion (A) : The Kalabhra period is not a dark age.
Reason (R) : It is known about the literary sources, new script and flourishing of trade and commerce.
(a) Both A and R are true. R is not the correct explanation of A.
(b) Both A and R are true. R is the correct explanation of A
(c) A is true but R is false.
(d) Both A and R is not true.
Answer:
(b) Both A and R are true. R is the correct explanation of A.

Question 2.
Which of the following statements are not true?
(1) Pandyas garlanded Fig (Athi) flower.
(2) The deity of the kurinji people is Indiran.
(3) The author of ‘Natural History’ is Pliny the younger
(a) 1, 2 and 3
(b) 2 and 3
Answer:
(b) 2 and 3

III. Answer the following

Question 1.
What were the ornaments made of?
Answer:

  1. Gold
  2. Silver
  3. Pearls
  4. Precious stones
  5. Conch shells
  6. Beads

Question 2.
What were the main imports?
Answer:

  1. Topaz
  2. Tin
  3. Wine
  4. Glass
  5. Horses

Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 1 Society and Culture in Ancient Tamizhagam: The Sangam Age

Question 3.
What do you know about Indian silk?
Answer:

  1. The silk supplied by Indians, merchants to the Roman Empire was very important. .
  2. The Roman emperor Aurelian declared it to be worth its weight in gold.

Question 4.
What is the Royal Insignia?
Answer:

  1. Sceptre
  2. Drum
  3. White umbrella

VII. Answer the following

Question 1.
Explain the Religious Beliefs and Social Divisions in the Sangam Society. The primary deity of the Tamils was Seyon or Murugan.
Answer:

  1. The other worshipped gods were Sivan, Mayon (Vishnu), Indiran, Varunan and Kotravai.
  2. The Hero stone (natukkal) worship was in practice
  3. Buddhism and Jainism also co-existed.
  4. As it did in northern India caste did not develop in Tamizhagam.
  5. Varuna system came to the Dravidian south comparatively late.

Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 1 Society and Culture in Ancient Tamizhagam: The Sangam Age

Question 2.
What was said by George L Hart about the Tamil language?
Answer:

  1. George L. Hart, Professor of Tamil language at the University of California, has said that Tamil is as old as Latin.
  2. The language arose as an entirely independent tradition with no influence of other languages.

VII. Mind map

Samacheer Kalvi 6th Social Science Guide History Term 3 Chapter 1 Society and Culture in Ancient Tamizhagam The Sangam Age

Tamil Nadu 11th Maths Model Question Paper 3 English Medium

Students can Download Tamil Nadu 11th Maths Model Question Paper 3 English Medium Pdf, Tamil Nadu 11th Maths Model Question Papers helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

TN State Board 11th Maths Model Question Paper 3 English Medium

General Instructions:

  1. The question paper comprises of four parts.
  2. You are to attempt all the parts. An internal choice of questions is provided wherever applicable.
  3. All questions of Part I, II, III and IV are to be attempted separately.
  4. Question numbers 1 to 20 in Part I are Multiple Choice Questions of one mark each.
    These are to be answered by choosing the most suitable answer from the given four alternatives and writing the option code and the corresponding answer
  5. Question numbers 21 to 30 in Part II are two-mark questions. These are to be answered in about one or two sentences.
  6. Question numbers 31 to 40 in Part III are three-mark questions. These are to be answered in above three to five short sentences.
  7. Question numbers 41 to 47 in Part IV are five-mark questions. These are to be answered in detail Draw diagrams wherever necessary.

Time: 2:30 Hours
Maximum Marks: 90

PART – 1

I. Choose the correct answer. Answer all the questions: [20 × 1 = 20]

Question 1.
Let R be the universal relation on a set X with more than one element then R is ………………
(a) Not reflexive
(b) Not symmetric
(c) Transitive
(d) None of the above
Answer:
(c) Transitive

Question 2.
The value of logab logbc logca is …………………..
(a) 2
(b) 1
(c) 3
(d) 4
Answer:
(b) 1

Tamil Nadu 11th Maths Model Question Paper 3 English Medium

Question 3.
If log \(\log _{\sqrt{ }}\) 0.25 = 4 then the value of x is ………………..
(a) 0.5
(b) 2.5
(c) 1.5
(d) 1.25
Answer:
(a) 0.5

Question 4.
The product of r consecutive positive integers is divisible by ………………..
(a) r!
(b) (r-1)!
(c) (r+l)!
(d) rr
Answer:
(a) r!

Tamil Nadu 11th Maths Model Question Paper 3 English Medium

Question 5.
The value of tan75° – cot 75° is ……………….
(a) 1
(b) 2 + \(\sqrt{3}\)
(c) 2 – \(\sqrt{3}\)
(d) 2\(\sqrt{3}\)
Answer:
(d) 2\(\sqrt{3}\)

Question 6.
If (1 +x2)2(1 + x)2 = a0 + a1 x + a2x2 …. + xn+4 and if a0, a1, a2, are in AP, then n is …………………..
(a) 1
(b) 2
(c) 3
(d) 4
Answer:
(c) 3

Tamil Nadu 11th Maths Model Question Paper 3 English Medium

Question 7.
If nC12 = nC5 then nC2 = …………………
(a) 72
(b) 306
(c) 152
(d) 153
Answer:
(d) 153

Question 8.
The line (p + 2q)x + (p- 3q)y =p – q for different values of p and q passes through the point …………………
(a) (\(\frac{3}{5}\), \(\frac{2}{5}\))
(b) (\(\frac{2}{5}\), \(\frac{2}{5}\))
(c) (\(\frac{3}{5}\), \(\frac{3}{5}\))
(d) (\(\frac{2}{5}\), \(\frac{3}{5}\))
Answer:
(d) (\(\frac{2}{5}\), \(\frac{3}{5}\))

Tamil Nadu 11th Maths Model Question Paper 3 English Medium

Question 9.
The number of terms in the expansion of [(a + b)2]18 = ………………..
(a) 19
(b) 18
(c) 36
(d) 37
Answer:
(d) 37

Question 10.
A line passes through the point (2, 2) and is perpendicular to the line 3x + y = 5 then its y intercept is …………………
Answer:
(a) \(\frac{3}{4}\)
(b) \(\frac{4}{3}\)
(c) 5
(d) \(\frac{1}{3}\)

Question 11.
If a and b are the roots of the equation x2 – kx + 16 = 0 satisfy a2 + b2 = 32, then the value of k is ………………..
(a) 10
(b) -8
(c) -8, 8
(d) 6
Answer:
(c) -8, 8

Tamil Nadu 11th Maths Model Question Paper 3 English Medium

Question 12.
If A is a square matrix of order 3 then |kA| = ………………….
(a) k |A|
(b) k2|A|
(c) k3|A|
(d) k|A3|
Answer:
(c) k3|A|

Question 13.
If ABCD is a parallelogram then \(\bar { AB } \) + \(\bar { AD } \) + \(\bar { CD } \) + \(\bar { CD } \) = ………………..
(a) 2(\(\bar { AB } \) + \(\bar { AD } \))
(b) 4\(\bar { AC } \)
(c) 4\(\bar { BD } \)
(d) \(\bar { o } \)
Answer:
(d) \(\bar { o } \)

Tamil Nadu 11th Maths Model Question Paper 3 English Medium

Question 14.
\(\lim _{x \rightarrow 0}\) x cot x = ………………….
(a) 0
(b) 1
(c) -1
(d) ∞
Answer:
(b) 1

Question 15.
If x = \(\frac { 1-t^{ 2 } }{ 1+t^{ 2 } } \) and y = \(\frac { 2t }{ 1+t^{ 2 } } \) then \(\frac{dy}{dx}\) = ………………..
(a) \(\frac{y}{x}\)
(b) \(\frac{-y}{x}\)
(c) –\(\frac{x}{y}\)
(d) \(\frac{x}{y}\)
Answer:
(c) –\(\frac{x}{y}\)

Tamil Nadu 11th Maths Model Question Paper 3 English Medium

Question 16.
If y = \(\frac { (1-x)^{ 2 } }{ x^{ 2 } } \) then \(\frac{dy}{dx}\) is …………………..
(a) \(\frac { 2 }{ x^{ 2 } } \) + \(\frac { 2 }{ x^{ 3 } } \)
(b) –\(\frac { 2 }{ x^{ 2 } } \) + \(\frac { 2 }{ x^{ 3 } } \)
(c) –\(\frac { 2 }{ x^{ 2 } } \) – \(\frac { 2 }{ x^{ 3 } } \)
(d) –\(\frac { 2 }{ x^{ 3 } } \) + \(\frac { 2 }{ x^{ 2 } } \)
Answer:
(d) –\(\frac { 2 }{ x^{ 3 } } \) + \(\frac { 2 }{ x^{ 2 } } \)

Question 17.
If y = \(\frac{sinx+cosx}{sinx-cosx}\) then \(\frac{dy}{dx}\) at x = \(\frac { \pi }{ 2 } \) is ………………….
(a) 1
(b) 0
(c) -2
(d) 2
Answer:
(c) -2

Tamil Nadu 11th Maths Model Question Paper 3 English Medium

Question 18.
\(\int \frac{\sin ^{8} x-\cos ^{8} x}{1-2 \sin ^{2} x \cos ^{2} x}\) dx is ……………………
(a) \(\frac{1}{2}\) sin2x + c
(b) –\(\frac{1}{2}\) sin2x + c
(c) \(\frac{1}{2}\) cos 2x + c
(d) – \(\frac{1}{2}\) cos 2x + c
Answer:
(b) –\(\frac{1}{2}\) sin2x + c

Question 19.
An urn contains 5 red and 5 black balls. A balls is drawn at random, its colour is noted and is returned to the urn. Moreover, 2 additional balls of the colour drawn are put in the urn and then a ball is drawn at random. The probability that the second ball drawn is red will be ………………
(a) \(\frac{5}{12}\)
(b) \(\frac{1}{2}\)
(c) \(\frac{7}{12}\)
(d) \(\frac{1}{4}\)
Answer:
(b) \(\frac{1}{2}\)

Tamil Nadu 11th Maths Model Question Paper 3 English Medium

Question 20.
Let A and B be two events such that P(\(\bar { AUB } \)) = \(\frac{1}{6}\) , Then the events A and B are P(A∩B) = 1/4 and P(\(\bar { A } \)) = 1/4 is ………………
(a) Equally likely but not independent
(b) Independent but not equally likely
(c) Independent and equally likely
(d) Mutually inclusive and dependent
Answer:
(b) Independent but not equally likely

PART – II

II. Answer any seven questions. Question No. 30 is compulsory. [7 × 2 = 14]

Question 21.
Let A and B are two sets such that n(A) = 3 and n(B) = 2. If (x, 1), (y, 2) and (z, 1) are in A × B, find A and B where x, y, z are distinct elements?
Answer:
n(A) = 3 ⇒ set A contains 3 elements
n(B) = 2 ⇒ set B contains 2 elements
we are given (x, 1), (y, 2), (z, 1) are elements in A × B
⇒ A = {x, y, z} and B = {1, 2}

Tamil Nadu 11th Maths Model Question Paper 3 English Medium

Question 22.
Solve |5x — 12| ← 2
Answer:
5x – 12 > -2 (or) 5x – 12 < 2 ⇒ 5x > -2 + 12 (= 10)
⇒ x > \(\frac{10}{5}\) = 2
x > 2
(or)
5x < 2 + 12 (= 14)
⇒ x < \(\frac{14}{5}\)
so 2 < x < \(\frac{14}{5}\)

Question 23.
If 10Pr-1 = 2 × 6 Pr, find r?
Answer:
10Pr-1 = 2 × 6Pr
Tamil Nadu 11th Maths Model Question Paper 3 English Medium img 1
⇒ (11 – r) (10 – r) (9 – r) (8 – r) (7 – r) = 10 × 9 × 4 × 7
= 5 × 2 × 3 × 3 × 2 × 2 × 7
= 7 × 6 × 5 × 4 × 3
⇒ 11 – r = 7
11 – 7 = r
r = 4

Tamil Nadu 11th Maths Model Question Paper 3 English Medium

Question 24.
The number of bacteria in a certain culture doubles every hour. If there were 30 bacteria present in the culture originally, how many bacteria will be present at the end of 2nd hour, 4th hour and nth hour?
Answer:
No. of bacteria at the beginning = 30
No. of bacteria after 1 hour = 30 × 2 = 60
No. of bacteria after 2 hours = 30 × 22 = 30 × 4 = 120
No. of bacteria after 4 hours = 30 × 24 = 30 × 16 = 480
No. of bacteria after nth hour = 30 × 2n

Question 25.
Find |A| if A = \(\left[\begin{array}{ccc}
0 & \sin \alpha & \cos \alpha \\
\sin \alpha & 0 & \sin \beta \\
\cos \alpha & -\sin \beta & 0
\end{array}\right]\)
Answer:
\(\left[\begin{array}{ccc}
0 & \sin \alpha & \cos \alpha \\
\sin \alpha & 0 & \sin \beta \\
\cos \alpha & -\sin \beta & 0
\end{array}\right]\)
= 0M11 – sin αM12 + cos αM13
= 0 – sin α(0 – cos α sin β) + cos α(- sin α sin β – 0) = 0

Tamil Nadu 11th Maths Model Question Paper 3 English Medium

Question 26.
Find the value of λ for which the vectors \(\vec { a } \) = 3\(\hat { i } \) + 2\(\hat { j } \) + 9\(\hat { k } \) and \(\vec { a } \) = \(\hat { i } \) + λ\(\hat { j } \) +3\(\hat { k } \) are parallel?
Answer:
Given \(\vec { a } \) and \(\vec { b } \) are parallel ⇒\(\vec { a } \) = t\(\vec { b } \) (where t is a scalar)
(i.e.,) 3\(\hat { i } \) + 2\(\hat { j } \) + 9\(\hat { k } \) = t\(\hat { i } \) + λ\(\hat { j } \) + 3\(\hat { k } \))
equating \(\hat { i } \) components we get 3 = t
equating \(\hat { j } \) components
(i.e); 2 = tλ
2 = 3λ ⇒λ = 2/3

Tamil Nadu 11th Maths Model Question Paper 3 English Medium

Question 27.
Evaluate \(\underset { x\rightarrow \pi }{ lim } \) \(\frac{sin 3x}{sin 2x}\)
Answer:
Tamil Nadu 11th Maths Model Question Paper 3 English Medium img 2

Question 28.
Find the derivative of sinx2 with respect to x2?
Answer:
Tamil Nadu 11th Maths Model Question Paper 3 English Medium img 3

Question 29.
Let the matrix M = \(\begin{bmatrix} x & y \\ z & 1 \end{bmatrix}\) if x, y and z are chosen at random from the set {1, 2, 3}, and repetition is allowed (i.e., x = y = z), what is the probability that the given matrix M is a singular matrix?
Answer:
If the given matnx M is singular, then = \(\begin{vmatrix} x & y \\ z & 1 \end{vmatrix}\) = 0
That is, x – yz = 0
Hence the possible ways of selecting (x, y, z) are
{(1, 1, 1), (2, 1, 2), (2, 2, 1), (3, 1, 3), (3, 3, 1)} = A (say)
The number of favourable cases n(A) = 5
The total number of cases are n(S) = 33 = 27
The probability of the given matrix is a singular matrix is
P(A) = \(\frac{n(A)}{n(S)}\) = \(\frac{5}{27}\)

Tamil Nadu 11th Maths Model Question Paper 3 English Medium

Question 30.
Evaluate \(\frac { x^{ 2 } }{ 1+x^{ 6 } } \)
Answer:
Tamil Nadu 11th Maths Model Question Paper 3 English Medium img 4

PART – III

III. Answer any seven questions. Question No. 40 is compulsory. [7 × 3 = 21]

Question 31.
If f, g, h are real valued functions defined on R, then prove that (f + g) o h = f o h + g o h. What can you say about fo(g + h)? Justify your answer?

Question 32.
Solve \(\frac{4}{x+1}\) ≤ 3 ≤ \(\frac{6}{x+1}\), x > 0?

Tamil Nadu 11th Maths Model Question Paper 3 English Medium

Question 33.
Prove that cos-1 \(\frac{4}{5}\) + tan-1 \(\frac{3}{5}\) = tan-1 \(\frac{27}{11}\)?

Question 34.
There are 15 candidates for an examination. 7 candidates are appearing for mathematics examination while the remaining 8 are appearing for different subjects. In how many ways
can they be seated in a row so that no two mathematics candidates are together?

Question 35.
Prove that if a, b, c are in H.P. if and only if \(\frac{a}{c}\) = \(\frac{a-b}{b-c}\)?

Tamil Nadu 11th Maths Model Question Paper 3 English Medium

Question 36.
If (-4, 7) is one vertex of a rhombus and if the equation of one diagonal is 5x – y + 7 = 0, then find the equation of another diagonal?

Question 37.
Verify the existence of \(\underset { x\rightarrow 1 }{ lim } \) f(x), where f(x) = \(\left\{\begin{aligned}
\frac{|x-1|}{x-1}, & \text { for } x \neq 1 \\
0, & \text { for } x=1
\end{aligned}\right.\)

Question 38.
If y = sin-1 x then find y?

Tamil Nadu 11th Maths Model Question Paper 3 English Medium

Question 39.
Evaluate cot2 x + tan2 x?

Question 40.
Show that
\(\left|\begin{array}{ccc}
2 b c-a^{2} & c^{2} & b^{2} \\
c^{2} & 2 c a-b^{2} & a^{2} \\
b^{2} & a^{2} & 2 a b-c^{2}
\end{array}\right|=\left|\begin{array}{ccc}
a & b & c \\
b & c & a \\
c & a & b
\end{array}\right|^{2}\)

PART – IV

IV. Answer all the questions. [7 × 5 = 35]

Question 41 (a).
The total cost of airfare on a given route is comprised of the base cost C and the fuel surcharge S in rupee. Both C and S are functions of the mileage m; C(m) = 0.4m + 50 and S(m) = 0.03m. Determine a function for the total cost of a ticket in terms of the mileage and find the airfare for flying ¡600 miles?

[OR]

(b) Evaluate \(\sqrt { x^{ 2 }+x+1 } \)?

Tamil Nadu 11th Maths Model Question Paper 3 English Medium

Question 42 (a).
Determine the region in the plane determined by the inequalities y ≥ 2x and -2x + 3y ≤ 6?

[OR]

(b) If y(cos-1 x)2, prove that (1-x2) \(\frac { d^{ 2 }y }{ dx^{ 2 } } \) – x \(\frac{dy}{dx}\) – 2 = 0. Hence find y2 when x = 0?

Question 43(a).
Prove that nCr + nCr-1 = n+1Cr

[OR]

(b) If the binomial coefficients of three consecutive terms in the expansion of (a + x)n are in the ratio 1 : 7 : 42, then find n?

Tamil Nadu 11th Maths Model Question Paper 3 English Medium

Question 44 (a).
(a) Prove that

  1. sin A + sin( 120° + A) + sin (240° + A) = O
  2. cos A+ cos (120° + A) + cos (120° – A) = O

[OR]

(b) A box contains two white balls, three black balls and four red balls. In how many ways can three balls be drawn from the box, if at least one black ball is to be included in the draw?

Question 45 (a).
Show that \(\left|\begin{array}{ccc}
a^{2}+x^{2} & a b & a c \\
a b & b^{2}+x^{2} & b c \\
a c & b c & c^{2}+x^{2}
\end{array}\right|\) is divisible by x4?

[OR]

(b) \(\left[\begin{array}{ccc}
0 & p & 3 \\
2 & q^{2} & -1 \\
r & 1 & 0
\end{array}\right]\) is skew-symmetric, find the values of p, q and r?

Tamil Nadu 11th Maths Model Question Paper 3 English Medium

Question 46 (a).
In a shopping mall there is a hail of cuboid shape with dimension 800 × 800 × 720 units, which needs to be added the facility of an escalator in the path as shown by the dotted line in the figure. Find

  1. The minimum total length of the escalator
  2. The heights at which the escalator changes its direction
  3. The slopes of the escalator at the turning points.

Tamil Nadu 11th Maths Model Question Paper 3 English Medium img 5-1

[OR]

(b) Evaluate \(\lim _{x \rightarrow a} \frac{\sqrt{x-b}-\sqrt{a-b}}{x^{2}-a^{2}}(a>b)\)

Tamil Nadu 11th Maths Model Question Paper 3 English Medium

Question 47 (a).
Evaluate ∫\(\frac { 3x+5 }{ x^{ 2 }+4x+7 } \) dx

[OR]

(b) A factory has two Machines – I and II. Machine-I produces 60% of items and Machine-II produces 40% of the items of the total output. Further 2% of the items produced by Machine-I are defective whereas 4% produced by Machine-II are defective. If an itci is drawn at random what is the probability that it is defective?

Samacheer Kalvi 6th Social Science Guide Economics Term 2 Chapter 1 Economics-An Introduction

Students can download 6th Social Science Term 2 Economics Chapter 1 Economics-An Introduction Questions and Answers, Notes, Samacheer Kalvi 6th Social Science Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 6th Social Science Economics Solutions Term 2 Chapter 1 Economics-An Introduction

Samacheer Kalvi 6th Social Science Economics-An Introduction Text Book Back Questions and Answers

I. Fill in the blanks

  1. The producers of food grains are ……………..
  2. Collection of honey is a …………….. occupation.
  3. The conversion of raw materials into finished goods is called ……………..
  4. According to Gandhiji the villages are …………….. of the nation.
  5. The percentage of population in the cities of Tamil Nadu is ……………..

Answer:

  1. Farmers
  2. Primary
  3. Secondary activities
  4. backbone
  5. 47%

II. Match the following

Samacheer Kalvi 6th Social Science Guide Economics Term 2 Chapter 1 Economics-An Introduction
Answer:
1. – c
2. – d
3. – a
4. – b
5. – d

III. Match and find the odd pair

Samacheer Kalvi 6th Social Science Guide Economics Term 2 Chapter 1 Economics-An Introduction
Answer:
1. – d
2. – c
3. – b
4. – a

IV. Choose the correct answer

  1. Agriculture is a (primary / Secondary) occupation.
  2. Economic activities are divided on the basis of (ownership / use)
  3. Sugar Industries are (Primary / Secondary) activity.
  4. Agro based industry (Cotton / Furniture)
  5. Dairy farming is a (Public sector/Co-operative sector)

Answer:

  1. Primary
  2. use
  3. Secondary
  4. Cotton
  5. Co-operative sector

V. Answer the following questions

Question 1.
Sandhai – Define
Answer:
In villages once in a week or month, all things are sold in a particular place at a specific time to meet the needs of the people. That is called Sandai.

Question 2.
What is called the barter system?
Answer:
A system of exchanging goods for other goods is called a barter system. Example: Exchange a bag or rice for enough clothes.

Question 3.
What is trade?
Answer:
Trade involves the transfer of goods or services from one person to another often in exchange of money.

Samacheer Kalvi 6th Social Science Guide Economics Term 2 Chapter 1 Economics-An Introduction

Question 4.
What is Savings?
Answer:
The amount from the income which is left for future needs after consumption is called sayings.

Question 5.
What was the necessity for the invention of money?
Answer:

  1. When traders exchange commodities there arises a difference in the value of the commodity.
  2. To solve this problem people invented money.

Question 6.
What was the reason for the development of settlements near water bodies?
Answer:

  1. Rivers act as the main source for the cultivation of crops.
  2. So early man settled permanently near the rivers.

Samacheer Kalvi 6th Social Science Guide Economics Term 2 Chapter 1 Economics-An Introduction

Question 7.
What are called secondary occupation?
Answer:
The raw materials obtained from the primary activities are converted into finished products is called a secondary occupation.

Question 8.
Name the city-centered industries.
Answer:
Cement, iron, and Aluminium industries, seafood processing are some of the city centered industries.

VI. Answer the following in detail

Question 1.
List out the important primary occupations of your district.
Answer:

  1. Agriculture
  2. Cattle rearing
  3. Collection of fruits, nuts, honey, and medicinal herbs.

Samacheer Kalvi 6th Social Science Guide Economics Term 2 Chapter 1 Economics-An Introduction

Question 2.
Mention the manufacturing industries found in your district.
Answer:

  1. Cotton textiles
  2. Spinning and weaving
  3. Food processing industries
  4. Beedi production
  5. Wind power generations

Question 3.
How are the industries classified on the basis of raw materials?
Answer:
On the basis of raw materials industries are classified as

  1. Agro-Based Industries – Cotton textiles, Sugar mills, and Food processing.
  2. Forest-Based Industries – Paper mills, Furniture making, Building materials.
  3. Mineral Based Industries – Cement, Iron, Aluminium Industries.
  4. Marine Based Industries – Seafood processing.

Question 4.
Write down the occupations in the service sector.
Answer:
The service sector serves the people to fulfill their daily needs like:

  1. Transport – Roadways, Railways, Waterways, Airways.
  2. Communication – Post, Telephone, Information Technology.
  3. Trade – Procurement of goods, selling.
  4. Banking – Money Transaction, Banking Services.

Samacheer Kalvi 6th Social Science Guide Economics Term 2 Chapter 1 Economics-An Introduction

Question 5.
What do you know about the features of cities?
Answer:

  1. A city is a large human settlement.
  2. The high density of population.
  3. Four-way roads, flyovers, skyscrapers, parks.
  4. Educational institution, hospital, Government offices.
  5. Private and public industries and technological institutions.
  6. Employment opportunities permanent monthly income, basic requirements are

VII. Fill in the tabular column given below

Samacheer Kalvi 6th Social Science Guide Economics Term 2 Chapter 1 Economics-An Introduction

Activity:
Write the lyrics of Bharathiyar’s Samacheer Kalvi 6th Social Science Guide Economics Term 2 Chapter 1 Economics-An Introduction Analyze the lyrics and write down the commodities which were exchanged in yesteryears with the help of the teacher.
Samacheer Kalvi 6th Social Science Guide Economics Term 2 Chapter 1 Economics-An Introduction
(1) Wheat
(2) Betel
(3) Tusk

VIII. Stick picture

Samacheer Kalvi 6th Social Science Guide Economics Term 2 Chapter 1 Economics-An Introduction

Samacheer Kalvi 6th Social Science Economics-An Introduction Additional Important Questions and Answers

I. Fill in the blanks Answer

  1. The permanent settlements near the rivers were called ……………
  2. More than …………… percentage of the world’s population live in cities.
  3. The …………… sector serves the people to fulfill their daily needs.
  4. One who uses the products is called ……………
  5. …………… are the real shadow of cities.

Answer:

  1. Villages
  2. 50
  3. Service
  4. Consumer
  5. Villages

II. Choose the correct answer

Question 1.
Tertiary activities are also called as sector ……………
(a) Private
(b) Service
(c) Public
Answer:
(b) Service

Question 2.
Secondary and tertiary activities are …………… centred activities.
(a) City
(b) Town
(c) Village
Answer:
(a) City

Question 3.
…………… is the main occupation in villages.
(a) Mining
(b) Fishing
(c) Farming
Answer:
(c) Farming

III. Answer the following questions

Question 1.
Sandhai – Define
Answer:
In villages, once in a week or month, things are sold in a particular place at a specific time to meet the needs of the people. That is called Sandhai.

Question 2.
What is called the barter system?
Answer:

  1. A system of exchanging goods for other goods is called a barter system.
  2. Example: Exchange a bag or rice for enough clothes.

Samacheer Kalvi 6th Social Science Guide Economics Term 2 Chapter 1 Economics-An Introduction

Question 3.
What are consumer goods?
Answer:
The finished goods which are brought from the market to fulfill the daily needs of the consumers are called consumer goods.

Question 4.
Who are cultivators?
Answer:
Persons who are involved in farming and grazing are called cultivators or farmers.

Question 5.
How are industries classified?
Answer:
Industries are classified on the basis of the:

  1. Availability of raw materials
  2. Capital
  3. Ownership

Question 6.
Name the sectors that are helpful in the economic development of our country.
Answer:
Agriculture and Industries are helpful in the economic development of our country.

IV. Mind map

Samacheer Kalvi 6th Social Science Guide Economics Term 2 Chapter 1 Economics-An Introduction

Tamil Nadu 11th Maths Model Question Paper 2 English Medium

Students can Download Tamil Nadu 11th Maths Model Question Paper 2 English Medium Pdf, Tamil Nadu 11th Maths Model Question Papers helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

TN State Board 11th Maths Model Question Paper 2 English Medium

General Instructions:

  1. The question paper comprises of four parts.
  2. You are to attempt all the parts. An internal choice of questions is provided wherever applicable.
  3. All questions of Part I, II, III and IV are to be attempted separately.
  4. Question numbers 1 to 20 in Part I are Multiple Choice Questions of one mark each.
    These are to be answered by choosing the most suitable answer from the given four alternatives and writing the option code and the corresponding answer
  5. Question numbers 21 to 30 in Part II are two-mark questions. These are to be answered in about one or two sentences.
  6. Question numbers 31 to 40 in Part III are three-mark questions. These are to be answered in above three to five short sentences.
  7. Question numbers 41 to 47 in Part IV are five-mark questions. These are to be answered in detail Draw diagrams wherever necessary.

Time: 2:30 Hours
Maximum Marks: 90

PART – 1

I. Choose the correct answer. Answer all the questions: [20 × 1 = 20]

Question 1.
Let R be the set of all real numbers. Consider the following subsets of the plane R × R:
S= {(x, y) : y = x + 1 and 0 < x < 2} and T = {(x, y): x – y is an integer}
Then which of the following is true?
(a) T is an equivalence relation but S is not an equivalence relation.
(b) Neither S nor T is an equivalence relation
(c) Both S and T are equivalence relation
(d) S is an equivalence relation but T is not an equivalence relation.
Answer:
(a) T is an equivalence relation but S is not an equivalence relation.

Tamil Nadu 11th Maths Model Question Paper 2 English Medium

Question 2.
If the set A has m elements the set B has n elements and the number of elements in A × B is …………………
(a) m + n
(b) mn
(c) \(\frac{m}{n}\)
(d) m2
Answer:
(b) mn

Question 3.
If \(\frac{ax}{(x+2)(2x-3)}\) = \(\frac{2}{x+2}\) + \(\frac{3}{2x-3}\) then a = ……………….
(a) 8
(b) 7
(c) 5
(d) 4
Answer:
(b) 7

Tamil Nadu 11th Maths Model Question Paper 2 English Medium

Question 4.
The number of solutions of x2 + |x – 1| = 1 is ………………….
(a) 1
(b) 0
(c) 2
(d) 3
Answer:
(c) 2

Question 5.
If a, 8, b are in A.P. a, 4, b are in G.P. and a, x, b are in H.P then x = ………………..
(a) 2
(b) 1
(c) 4
(d) 16
Answer:
(a) 2

Tamil Nadu 11th Maths Model Question Paper 2 English Medium

Question 6.
If 10 lines are drawn in a plane such that no two of them are parallel and no three are concurrent, then the total number of points of intersection are ……………….
(a) 45
(b) 40
(c) 10!
(d) 210
Answer:
(a) 45

Question 7.
The value of e2logx = …………………..
(a) 2x
(b) x2
(c) \(\sqrt{x}\)
(d) \(\frac{x}{2}\)
Answer:
(b) x2

Tamil Nadu 11th Maths Model Question Paper 2 English Medium

Question 8.
The nth term of the sequence 1, 2, 4, 7, 11 …. is …………………
(a) n3 + 3n2 + 2n
(b) n3 – 3n2 + 3n
(c) n\(\frac{(n+1)(n+2)}{3}\)
(d) \(\frac { n^{ 2 }-n+2 }{ 2 } \)
Answer:
(d) \(\frac { n^{ 2 }-n+2 }{ 2 } \)

Question 9.
The last term in the expansion (2+\(\sqrt{3}\))8 is ………………
(a) 81
(b) 27
(c) 9
(d) 3
Answer:
(a) 81

Tamil Nadu 11th Maths Model Question Paper 2 English Medium

Question 10.
A line perpendicular to the line 5x -y = 0 forms a triangle with the coordinate axes. If the area of the triangle is 5sq.units, then its equation is …………………..
(a) x + 5y ± 5\(\sqrt{2}\) = 0
(b) x – 5y ± 5\(\sqrt{2}\) = 0
(c) 5x + y ± 5\(\sqrt{2}\) = 0
(d) 5x – y ± 5\(\sqrt{2}\) = 0
Answer:
(a) x + 5y ± 5\(\sqrt{2}\) = 0

Question 11.
A factor of the determinant \(\left|\begin{array}{ccc}
x & -6 & -1 \\
2 & -3 x & x-3 \\
-3 & 2 x & x+2
\end{array}\right|\) is ……………….
(a) x + 3
(b) 2x – 1
(c) x – 2
(d) x – 3
Answer:
(a) x + 3

Tamil Nadu 11th Maths Model Question Paper 2 English Medium

Question 12.
If λ\(\vec { a } \) + 2λ\(\vec { j } \) + 2λ\(\vec { k } \) is a unit vector then the value of λ is ………………
(a) \(\frac{1}{3}\)
(b) \(\frac{1}{4}\)
(c) \(\frac{1}{9}\)
(d) \(\frac{1}{2}\)
Answer:
(a) \(\frac{1}{3}\)

Question 13.
One of the diagonals of parallelogram ABCD with \(\vec { a } \) and \(\vec { b } \) are adjacent sides is \(\vec { a } \) + \(\vec { b } \). The other diagonal BD is ………………….
(a) \(\vec { a } \) – \(\vec { b } \)
(b) \(\vec { a } \) – \(\vec { b } \)
(c) \(\vec { a } \) + \(\vec { b } \)
(d) \(\frac{\vec{a}+\vec{b}}{2}\)
Answer:
(b) \(\vec { a } \) – \(\vec { b } \)

Tamil Nadu 11th Maths Model Question Paper 2 English Medium

Question 14.
If (1, 2, 4) and (2, -3λ, -3) are the initial and terminal points of the vector \(\vec { i } \) + 5\(\vec { j } \) – 7\(\vec { k } \) then the value of λ …………………..
(a) \(\frac{7}{3}\)
(b) –\(\frac{7}{3}\)
(c) \(\frac{5}{3}\)
(d) \(\frac{-5}{3}\)
Answer:
(b) –\(\frac{7}{3}\)

Question 15.
If y = mx + c and f(0) =f'(0) = 1 then f(2) = …………………..
(a) 1
(b) 2
(c) 3
(d) 4
Answer:
(c) 3

Tamil Nadu 11th Maths Model Question Paper 2 English Medium

Question 16.
The derivative of (x + \(\frac{1}{x}\))2 w.r.to. x is ………………..
(a) 2x – \(\frac { 2 }{ x^{ 3 } } \)
(b) 2x + \(\frac { 2 }{ x^{ 3 } } \)
(c) 2(x + \(\frac{1}{x}\))
(d) 0
Answer:
(a) 2x – \(\frac { 2 }{ x^{ 3 } } \)

Question 17.
If f(x) is \(\left\{\begin{array}{cc}
a x^{2}-b, & -1<x<1 \\
\frac{1}{|x|}, & \text { elsewhere }
\end{array}\right.\) is differentiable at x = 1, then …………………
(a) a = \(\frac{1}{2}\), b = \(\frac{-3}{2}\)
(b) a = \(\frac{-1}{2}\), b = \(\frac{3}{2}\)
(c) a = \(\frac{-1}{2}\), b = \(\frac{-3}{2}\)
(d) a = \(\frac{1}{2}\), b = \(\frac{3}{2}\)
Answer:
(c) a = \(\frac{-1}{2}\), b = \(\frac{-3}{2}\)

Tamil Nadu 11th Maths Model Question Paper 2 English Medium

Question 18.
∫\(\frac { \sqrt { tanx } }{ sin2x } \) dx is ………………
(a) \(\sqrt{tanx}\) + c
(b) 2\(\sqrt{tanx}\) + c
(c) \(\frac{1}{2}\) \(\sqrt{tanx}\) + c
(d) \(\frac{1}{4}\) \(\sqrt{tanx}\) + c
Answer:
(a) \(\sqrt{tanx}\) + c

Question 19.
An urn contains 5 red and 5 black balls. A balls is drawn at random, its colour is noted and is returned to the urn. Moreover, 2 additional balls of the colour drawn are put in the urn and then a ball is drawn at random. The probability that the second ball drawn is red will be ………………….
(a) \(\frac{5}{12}\)
(b) \(\frac{1}{2}\)
(c) \(\frac{7}{12}\)
(d) \(\frac{1}{4}\)
Answer:
(b) \(\frac{1}{2}\)

Tamil Nadu 11th Maths Model Question Paper 2 English Medium

Question 20.
It is given that the events A and B are such that P(A) = \(\frac{1}{4}\), P(A/B) = \(\frac{1}{2}\), and P(B/A) = \(\frac{2}{3}\) then
P(B) = ………………….
(a) \(\frac{1}{6}\)
(b) \(\frac{1}{3}\)
(c) \(\frac{2}{3}\)
(d) \(\frac{1}{2}\)
Answer:
(b) \(\frac{1}{3}\)

PART – II

II. Answer any seven questions. Question No. 30 is compulsory. [7 × 2 = 14]

Question 21.
If n(P(A)) = 1024, n(A∪B) = 15 and n(P(B)) = 32 then find n(A∩B)
Answer:
n(P(A)) = 1024 = 210 ⇒ n(A) = 10
n(A∪B) = 15
n(P(B)) = 32 = 25 ⇒ n(B) = 5
We know n(A∪B) = n(A) + n(B) – n(A∩B)
(i.e) 15 = 10 + 5 – n(A∩B)
⇒ n(A∩B) = 15 – 15 = 0

Tamil Nadu 11th Maths Model Question Paper 2 English Medium

Question 22.
Simplify (343)2/3
Answer:
(343)2/3 = (73)2/3 = 73×2/3 = 72 = 49

Question 23.
Show that cos36° cos 72° cos 108° cos 144° = \(\frac{1}{16}\)
Answer:
LHS = cos36° cos(90° – 18°) cos(90° – 18°) cos(90° + 18°) cos(180° – 36°)
= sin2 18° cos2 36°
= (\(\frac { \sqrt { 5-1 } }{ 4 } \))2 (\(\frac { \sqrt { 5+1 } }{ 4 } \))2 = \(\frac{1}{16}\) = RHS

Tamil Nadu 11th Maths Model Question Paper 2 English Medium

Question 24.
Find the number of ways of selecting 9 balls from 6 red balls, 5 white balls and 5 blue balls if each selection consists of 3 balls of each colour?
Answer:
There are 6 red balls, 5 white balls and 5 blue balls.
We have to select 3 balls of each colour.
∴Number of ways of selection = 6C3 × 5C3 × 5C3
= \(\frac { 6! }{ 3!3! } \) × \(\frac { 5! }{ 3!2! } \) × \(\frac { 5! }{ 3!2! } \)
= 20 × 10 × 10 = 2000

Question 25.
Find |A| if A = \(\left[\begin{array}{ccc}
0 & \sin \alpha & \cos \alpha \\
\sin \alpha & 0 & \sin \beta \\
\cos \alpha & -\sin \beta & 0
\end{array}\right]\)
Answer:
\(\left[\begin{array}{ccc}
0 & \sin \alpha & \cos \alpha \\
\sin \alpha & 0 & \sin \beta \\
\cos \alpha & -\sin \beta & 0
\end{array}\right]\)
= 0M11 – sin αM12 + cos αM13
= 0 – sin α(0 – cos α sin β) + cos α (-sin α sin β – 0) = 0

Tamil Nadu 11th Maths Model Question Paper 2 English Medium

Question 26.
For any vector prove that \(\vec { r } \) = [\(\vec { r } \).\(\vec { i } \)) + (\(\vec { r } \).\(\vec { j } \))j + [\(\vec { r } \).\(\vec { k } \)}k
Answer:
Let \(\vec { r } \) = x\(\hat { i } \) + y\(\hat { j } \) + z\(\hat { k } \)
Tamil Nadu 11th Maths Model Question Paper 2 English Medium img 1 - Copy

Tamil Nadu 11th Maths Model Question Paper 2 English Medium

Question 27.
Calculate \(\lim _{x \rightarrow-2}\) (x3 – 3x + 6) (-x2 + 15)
Answer:
Tamil Nadu 11th Maths Model Question Paper 2 English Medium

Question 28.
Evaluate y = ex sin x
Answer:
Tamil Nadu 11th Maths Model Question Paper 2 English Medium

Question 29.
Integrate the following with respect to x
\(\frac{4}{3+4x}\) + (10x + 3)9 – 3 cosec(2x + 3) cot (2x + 3)
Answer:
Tamil Nadu 11th Maths Model Question Paper 2 English Medium

Tamil Nadu 11th Maths Model Question Paper 2 English Medium

Question 30.
P(A) = 0.6, P (B) = 0.5 and P(A∩B) = 0.2 find P(A/B)
Answer:
Given that P(A) = 0.6, P(B) = 0.5, and P(A∩B) = 0.2
P(A/B) = \(\frac { p(A∩B) }{ p(B) } \) = \(\frac{0.2}{0.5}\) = \(\frac{2}{5}\)

PART – III

III. Answer any seven questions. Question No. 40 is compulsory. [7 × 3 = 21]

Question 31.
A quadratic polynomial has one of its zeros 1 + \(\sqrt{5}\) and it satisfies p(1) = 2. Find the quadratic polynomial?

Question 32.
Prove that

  1. tan-1 (\(\frac{1}{7}\)) + tan-1(\(\frac{1}{13}\)) = tan-1(\(\frac{2}{9}\))
  2. cos-1\(\frac{4}{5}\) + tan-1\(\frac{3}{5}\) = tan-1\(\frac{27}{11}\)

Tamil Nadu 11th Maths Model Question Paper 2 English Medium

Question 33.
The product of three increasing numbers in GP is 5832. If we add 6 to the second number and 9 to the third number, then resulting numbers form an AP. Find the numbers in GP?

Question 34.
Find the equation of the line passing through the point (5, 2) and perpendiular to the line joining the points (2, 3) and (3, -1)?

Tamil Nadu 11th Maths Model Question Paper 2 English Medium

Question 35.
Find the area of the triangle whose vertices are (0,0), (1,2) and (4,3)?

Question 36.
If \(\vec { a } \), \(\vec { b } \), \(\vec { c } \) are three vectors such that \(\vec { a } \) + 2\(\vec { b } \) + \(\vec { c } \) = 0 and |\(\vec { a } \)| = 3, |\(\vec { b } \)| = 4, |\(\vec { c } \)| = 7 fimd the angle between \(\vec { a } \) and \(\vec { b } \)

Question 37.
Evaluate: \({ \underset { x\rightarrow 0 }{ lim } }\) \(\frac { 3^{ x }-1 }{ \sqrt { 1+x-1 } } \)

Tamil Nadu 11th Maths Model Question Paper 2 English Medium

Question 38.
Find \(\frac{dy}{dx}\) for y = tan-1 \((\frac { cosx+sinx }{ cosx-sinx } )\)

Question 39.
Evaluate: ∫x5 ex2

Question 40.
How many automobile license plates can be made, if each plate contains two different letters followed by three different digits?

PART – IV

IV. Answer all the questions. [7 × 5 = 35]

Question 41.
(a) If f : R – {-1, 1} → R is defined by f(x) = \(\frac { x }{ x^{ 2 }-1 } \), verify whether f is one-to-one or not?

[OR]

(b) Solve: log2 x + log4 x + log8 x = 11

Tamil Nadu 11th Maths Model Question Paper 2 English Medium

Question 42.
(a) Prove that \(\frac{\sin x+\sin 3 x+\sin 5 x+\sin 7 x}{\cos x+\cos 3 x+\cos 5 x+\cos 7 x}\) = tan 4x

[OR]

(b) If x + y + z = xyz, then prove that \(\frac { 2x }{ 1-x^{ 2 } } \) + \(\frac { 2y }{ 1-y^{ 2 } } \) + \(\frac { 2z }{ 1-z^{ 2 } } \) = \(\frac { 2x }{ 1-x^{ 2 } } \) \(\frac { 2y }{ 1-y^{ 2 } } \) \(\frac { 2z }{ 1-z^{ 2 } } \)

Question 43.
(a) If the letters of the word GARDEN are permuted in all possible ways and the strings thus formed are arranged in the dictionary order, then and the ranks of the words

  1. GARDEN
  2. DANGER

[OR]

(b) \(\underset { x\rightarrow a }{ lim } \) \(\frac{\sqrt{x-b}-\sqrt{a-b}}{x^{2}-a^{2}}\) (a>b)

Tamil Nadu 11th Maths Model Question Paper 2 English Medium

Question 44.
(a) If the binomial coefficients of three consecutive terms in the expansion of (a + x)n are in the ratio 1 : 7 : 42 then find n?

[OR]

(b) Evalute \(\sqrt { x^{ 2 }+y^{ 2 } } \) = tan-1(\(\frac{y}{x}\))

Question 45.
Let \(\vec { a } \), \(\vec { b } \), \(\vec { c } \) be three vectors such that |\(\vec { a } \)| = 3, |\(\vec { b } \)| = 4, |\(\vec { c } \)| = 5 and each one of them being perpendicular to the sum of the other two, find |\(\vec { a } \) + \(\vec { b } \) + \(\vec { c } \)|.

[OR]

(b) Evaluate ∫sec3 2xdx

Tamil Nadu 11th Maths Model Question Paper 2 English Medium

Question 46.
(a) Find all the equations of the straight lines in the family of the lines y = mx – 3, for which m and the x-coordinate of the point of intersection of the lines with x – y = 6 are integers?

[OR]

(b) There are two identical boxes containing respectively 5 white and 3 red balls, 4 white and 6 red balls. A box is chosen at random and a ball is drawn from it

  1. Find the probability that the ball is white
  2. If the ball is white, what is the probability that it from the first box?

Tamil Nadu 11th Maths Model Question Paper 2 English Medium

Question 47 (a).
If Ai Bi, Ci are the cofactors of ai, bi, ci, respectively, i = 1 to 3 in

[OR]

(b) Express the matrix \(\left(\begin{array}{ccc}
3 & 3 & -1 \\
-2 & -2 & 1 \\
-4 & -5 & 2
\end{array}\right)\) as the sum of symmetric martix and a skew-symmetric martix?

Tamil Nadu 11th Maths Model Question Paper 1 English Medium

Students can Download Tamil Nadu 11th Maths Model Question Paper 1 English Medium Pdf, Tamil Nadu 11th Maths Model Question Papers helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

TN State Board 11th Maths Model Question Paper 1 English Medium

General Instructions:

  1. The question paper comprises of four parts.
  2. You are to attempt all the parts. An internal choice of questions is provided wherever applicable.
  3. All questions of Part I, II, III and IV are to be attempted separately.
  4. Question numbers 1 to 20 in Part I are Multiple Choice Questions of one mark each.
    These are to be answered by choosing the most suitable answer from the given four alternatives and writing the option code and the corresponding answer
  5. Question numbers 21 to 30 in Part II are two-mark questions. These are to be answered in about one or two sentences.
  6. Question numbers 31 to 40 in Part III are three-mark questions. These are to be answered in above three to five short sentences.
  7. Question numbers 41 to 47 in Part IV are five-mark questions. These are to be answered in detail Draw diagrams wherever necessary.

Time: 2:30 Hours
Maximum Marks: 90

PART – 1

I. Choose the correct answer. Answer all the questions: [20 × 1 = 20]

Question 1.
For non empty sets A and B if A ⊂ B then (A × B) n (B × A) is equal to ………………….
(a) A ∩ B
(b) A × A
(c) B × B
(d) none of these
Answer:
(b) A × A

Tamil Nadu 12th Computer Science Model Question Paper 1 English Medium

Question 2.
The solution set of the inequality |x – 1| ≥ |x – 3| is ………………..
(a) [0, 2]
(b) [2, ∞)
(c) (0, 2)
(d) (-∞, 2)
Answer:
(b) [2, ∞)

Question 3.
The numer of solutions of x2 + |x – 1| = 1 is …………………
(a) 1
(b) 0
(c) 2
(d) 3
Answer:
(c) 2

Tamil Nadu 12th Computer Science Model Question Paper 1 English Medium

Question 4.
Which of the following is not true?
(a) sin θ = – \(\frac{3}{4}\)
(b) cos θ = -1
(c) tan θ = 25
(d) sec θ = \(\frac{1}{4}\)
Answer:
(d) sec θ = \(\frac{1}{4}\)

Question 5.
Let fk(x) = \(\frac{1}{k}\) [sink x + cos2 x] where x ∈ R and k ≥ 1. Then f4(x) – f6(x) = …………………
(a) \(\frac{1}{4}\)
(b) \(\frac{1}{12}\)
(c) \(\frac{1}{6}\)
(d) \(\frac{1}{3}\)
Answer:
(b) \(\frac{1}{12}\)

Tamil Nadu 12th Computer Science Model Question Paper 1 English Medium

Question 6.
If A and B are coefficients of xn in the expansion of (1 + x)2n and (1 + x)2n-1 respectively then \(\frac{A}{B}\) =
(a) \(\frac{1}{2}\)
(b) \(\frac{1}{n}\)
(c) 1
(d) 2
Answer:
(d) 2

Question 7.
The value of 15C8 + 15C9 – 15C6 – 15C7 is …………………
(a) 0
(b) 1
(c) 2
(d) 3
Answer:
(a) 0

Tamil Nadu 12th Computer Science Model Question Paper 1 English Medium

Question 8.
The slope of the line which makes an angle 45° with the line 3x -y = – 5 are …………………
(a) 1, -1
(b) \(\frac{1}{2}\), -2
(c) 1, \(\frac{1}{2}\)
(d) 2, \(\frac{-1}{2}\)
Answer:
(b) \(\frac{1}{2}\), -2

Question 9.
The sum of the binomial co-efficients is ………………….
(a) 2n
(b) 2n
(c) n2
(d) 1
Answer:
(b) 2n

Tamil Nadu 12th Computer Science Model Question Paper 1 English Medium

Question 10.
If the square of the matrix \(\begin{pmatrix} \alpha & \beta \\ \gamma & -\alpha \end{pmatrix}\) satisfy the relation
(a) 1 + α2 + βγ = 0
(b) 1 – α2 – βγ = 0
(c) 1 – α2 + βγ = 0
(d) 1 + α2 – βγ = 0
Answer:
(b) 1 – α2 – βγ = 0

Question 11.
The value of x for which the matrix A = \(\begin{bmatrix} e^{ x-2 } & e^{ 7+x } \\ e^{ 2+x } & e^{ 2x+3 } \end{bmatrix}\) is singular is ………………….
(a) 9
(b) 8
(c) 7
(d) 6
Answer:
(b) 8

Tamil Nadu 12th Computer Science Model Question Paper 1 English Medium

Question 12.
If A = \(\begin{pmatrix} \lambda & 1 \\ -1 & -\lambda \end{pmatrix}\) then for what value of λ, A2 = 0?
(a) 0
(b) ±1
(c) -1
(d) 1
Answer:
(b) ±1

Question 13.
limx→1 \(\frac { xe^{ x }-sinx }{ x } \) is ……………….
(a) 1
(b) 2
(c) 3
(d) 0
Answer:
(d) 0

Question 14.
If the points whose position vectors 10\({ \vec { i } }\) + 3\({ \vec { j } }\) + 12\({ \vec { i } }\) – 5\({ \vec { j } }\) and a\({ \vec { i } }\) + 11\({ \vec { j } }\) are collinear then the value of a is ……………….
(a) 3
(b) 5
(c) 6
(d) 8
Answer:
(d) 8

Question 15.
If y = mx + c and f(0) = f'(0) = 1 then f(2) = ………………..
(a) 1
(b) 2
(c) 3
(d) 4
Answer:
(c) 3

Tamil Nadu 12th Computer Science Model Question Paper 1 English Medium

Question 16.
limx→1 \(\frac { e^{ x }-e }{ x-1 } \) = ……………….
(a) 1
(b) e
(c) ∞
(d) 0
Answer:
(b) e

Question 17.
∫23x+5 dx is ………………..
(a) \(\frac { 3(2^{ 3x+5 }) }{ log2 } \) + c
(b) \(\frac { 2^{ 3x+5 } }{ 2log(3x+5) } \) + c
(c) \(\frac { 2^{ 3x+5 } }{ 2log3 } \) + c
(d) \(\frac { 2^{ 3x+5 } }{ 3log2 } \) + c
Answer:
(d) \(\frac { 2^{ 3x+5 } }{ 3log2 } \) + c

Question 18.
∫x2 cos xdx is ………………..
(a) x2sinx + 2xcosx – 2 sinx + c
(b) x2 – 2xcosx – 2sinx + c
(c) -x2 + 2xcosx + 2sinx + c
(d) -x2 – 2xcosx + 2 sinx + c
Answer:
(a) x2sinx + 2xcosx – 2 sinx + c

Tamil Nadu 12th Computer Science Model Question Paper 1 English Medium

Question 19.
∫\(\frac { x }{ 1+x^{ 2 } } \) dx = ………………
(a) tan-1 x + c
(b) log (1 + x2) + c
(c) log x + c
(d) \(\frac{1}{2}\) log (1 + x2) + c
Answer:
(d) \(\frac{1}{2}\) log (1 + x2) + c

Question 20.
Ten coins are tossed. The probability of getting atleast 8 heads is …………….
(a) \(\frac{7}{64}\)
(b) \(\frac{7}{32}\)
(c) \(\frac{7}{128}\)
(d) \(\frac{7}{16}\)
Answer:
(c) \(\frac{7}{128}\)

PART – II

II. Answer any seven questions. Question No. 30 is compulsory. [7 × 2 = 14]

Question 21.
To secure an A grade one must obtain an average of 90 marks or more in 5 subjects each of maximum 100 marks. If A scored 84, 87, 95, 91 in first four subjects, what is the minimum mark be scored in the fifth subject to get an A grade in the course?
Answer:
Required marks = 5 × 90 = 450
Total marks obtained in 4 subjects = 84 + 87 + 95 + 91 = 357
So required marks in the fifth subject = 450 – 357 = 93.

Tamil Nadu 12th Computer Science Model Question Paper 1 English Medium

Question 22.
Prove that (1 + tan1°) (1 + tan2°) (1 + tan 3°) …. (1 + tan 44°) is a multiple of 4?
Answer:
45°= 1 + 44 (or) 2 + 43 (or) 3 + 42 (or) 22 + 23
So we have 22 possible pairs
sa the product is (2) (22) = 44
which is ÷ by 4

Question 23.
Find the distinct permutations of the letters of the word MISSISSIPPI?
Answer:
MISSISSIPPI
Number of letters = 11
Here M-1 time, I-4timcs, S-4times, P-2timcs
So total number of arrangement is of this word = \(\frac { 11! }{ 4!4!2! } \)
\(\frac { 11\times 10\times 9\times 8\times 7\times 6\times 5\times 4! }{ 4\times 3\times 2\times 1\times 2\times 1\times 4! } \) = 34650

Tamil Nadu 12th Computer Science Model Question Paper 1 English Medium

Question 24.
Compare |A| using Sarrus rule if A = \(\left[\begin{array}{ccc}
3 & 4 & 1 \\
0 & -1 & 2 \\
5 & -2 & 6
\end{array}\right]\)
Answer:
Tamil Nadu 11th Maths Model Question Paper 1 English Medium img 1
|A| = [3(-1) (6) + 4(2)(5) + 1(0)(-2)] -[5(-1)(1) + (-2)(2)3 + 6(0)(4)] = [-18 + 40 + 0] – [-5 – 12 + 0] = 22 + 17 = 39.

Question 25.
If |\({ \vec { a } }\)|, |\({ \vec { b } }\)| = 6, |\({ \vec { c } }\)| =7 and \({ \vec { a } }\) + \({ \vec { b } }\) + \({ \vec { c } }\) = 0 find \({ \vec { a } }\).\({ \vec { b } }\) + \({ \vec { b } }.\) \({ \vec { c } }\) + \({ \vec { c } }\).\({ \vec { a } }\)
Answer:
Given \(\bar { a } \)+\(\bar { b } \)+\(\bar { c } \) = 0
⇒ (\(\bar { a } \)+\(\bar { b } \)+\(\bar { c } \))2 = 0
(i.e;) |\(\bar { a } \)|2 + |\(\bar { b } \)|2 + |\(\bar { c } \)|2 + 2 [\(\bar { a } \).\(\bar { b } \)+\(\bar { b } \).\(\bar { c } \)+\(\bar { c } \).\(\bar { a } \)) = 0
⇒ 52+62+72+2(\(\bar { a } \).\(\bar { b } \)+\(\bar { b } \).\(\bar { c } \)+\(\bar { c } \).\(\bar { a } \)) = 0
⇒2(\(\bar { a } \).\(\bar { b } \)+\(\bar { b } \).\(\bar { c } \)+\(\bar { c } \).\(\bar { a } \)) = – 25 – 36 – 49 = -110
⇒\(\bar { a } \).\(\bar { b } \)+\(\bar { b } \).\(\bar { c } \)+\(\bar { c } \).\(\bar { a } \) = \(\frac{-110}{2}\) = -55

Tamil Nadu 12th Computer Science Model Question Paper 1 English Medium

Question 26.
Find \(\lim _{ t\rightarrow 0 }{ \frac { \sqrt { t^{ 2 }+9-3 } }{ t^{ 2 } } } \)
Answer:
We can’t apply the quotient Iieorem it.:iiediatcly. Use the algebra technique of rationalising the numerator.
Tamil Nadu 11th Maths Model Question Paper 1 English Medium

Question 27.
Evaluate y = e-x.log x?
Answer:
y = e-x log x = uv(say)
Here u = e-x and v = log x
⇒ u’ = -e-x and v’ = uv’ + vu’
Now y = uv ⇒y’ = uv’ + vu’
(i.e). \(\frac{dy}{dx}\) = e-x(\(\frac{1}{x}\)) + log x(- e-x)
= e-x(\(\frac{1}{x}\) – log x)

Tamil Nadu 12th Computer Science Model Question Paper 1 English Medium

Question 28.
Evaluate ∫\(\frac { 1 }{ \sqrt { 1+(4x)^{ 2 } } } \) dx
Answer:
Let I = ∫\(\frac { 1 }{ \sqrt { 1+4x^{ 2 } } } \)dx = ∫\(\frac { 1 }{ \sqrt { 1+(2x^{ 2 }) } } \) dx
Putting 2x = t ⇒ 2 dx = dt ⇒ dx = \(\frac{1}{2}\) dt
Thus, I = \(\frac{1}{2}\)∫\({ \frac { 1 }{ \sqrt { 1^{ 2 }+t^{ 2 } } } }\) dt
I = \(\frac{1}{2}\) log |t+\(\sqrt { t^{ 2 }+1 } \) + c = \(\frac{1}{2}\) log |2x + \(\sqrt { (2x)^{ 2 }+1 } \)| + c
I = \(\frac{1}{2}\) log |2x+\(\sqrt { 4^{ 2 }+1 } \)| + c.

Question 29.
Nine coins are tossed once. Find the probablity to get atleast 2 heads?
Answer:
Let S be the sample and A be the event of getting at least two heads.
Therefore, the event \(\bar { A } \) denotes, getting at most one head.
n(S) = 29 = 521, n(\(\bar { A } \)) = 9C0 + 9C1 = 1 + 9 = 10
P(\(\bar { A } \)) = \(\frac{10}{512}\) = \(\frac{5}{256}\)
P(A) = 1- P(\(\bar { A } \)) = 1 – \(\frac{5}{256}\) = \(\frac{251}{256}\)

Tamil Nadu 11th Maths Model Question Paper 1 English Medium img 3

Tamil Nadu 12th Computer Science Model Question Paper 1 English Medium

Question 30.
If P(A) denotes the power set of A, then find n(P(P(ϕ))))?
Answer:
Since P(∅) contains 1 element, P(P(∅)) contains 21 elements and hence P(P(P(∅))) contains 22 elements. That is, 4 elements.

PART – III

III. Answer any seven questions. Question No. 40 is compulsory. [7 × 3 = 21]

Question 31.
A simple cipher takes a number and codes it, using the function f(x) = 3x – 4. Find the inverse of this function, determine whether the inverse is also a function and verify the symmetrical property about the line y = x (by drawing the lines)?

Question 32.
Show that 4 sin A sin (60° + A). sin(60° – A) = sin 3A?

Tamil Nadu 12th Computer Science Model Question Paper 1 English Medium

Question 33.
How many strings of length 6 can be formed using letters of the word FLOWER if (i) either starts with F or ends with R?

Question 34.
Find the distance of the line 4x – y = 0 from the point P(4, 1) measured along the line making an angle 135° with the positive x- axis?

Tamil Nadu 12th Computer Science Model Question Paper 1 English Medium

Question 35.
Using factor theorem prove that \(\left|\begin{array}{lll}
x+1 & 3 & 5 \\
2 & x+2 & 5 \\
2 & 3 & x+4
\end{array}\right|\) = (x – 1)2 + ( x+ 9)

Question 36.
Find the unit vectors perpendicular to each of the vectors \({ \vec { a } }\) + \({ \vec { b } }\) and \({ \vec { a } }\) – \({ \vec { b } }\). Where \({ \vec { a } }\) = \({ \vec { i } }\) + \({ \vec { j } }\) + \({ \vec { k } }\) and b = \({ \vec { i } }\) + 2\({ \vec { j } }\) + 3\({ \vec { k } }\)?

Tamil Nadu 12th Computer Science Model Question Paper 1 English Medium

Question 37.
If y = tan-1 \(\left(\frac{1+x}{1-x}\right)\), find y’?

Question 38.
Evaluate ∫\(\frac { x }{ \sqrt { 1+x^{ 2 } } } \) dx?

Question 39.
If A and B are two events such that P(A∪B) = 0.7, P(A∩B) = 0.2 and P(B) = 0.5 then show that A and B are independent?

Tamil Nadu 12th Computer Science Model Question Paper 1 English Medium

Question 40.
Resolve into partial fractions \(\frac { 2x^{ 2 }+5x-11 }{ x^{ 2 }+2x-3 } \)

PART – IV

IV. Answer all the questIons [7 × 5 = 35]

Question 41.
(a) A photocopy store charges Rs. 1.50 per copy for the first 10 copies and Rs. 1.00 per copy after the 10th copy. Let x be the number of copies, and let y be the total cost of photocopying.
(a) Draw graph of the cost as x goes from 0 to 50 copies?
(b) Find the cost of making 40 copies

[OR]

(b) If the difference of the roots of the equation 2x2 – (a + 1)x + a – 1 = 0 is equal to their product then prove that a =2?

Tamil Nadu 12th Computer Science Model Question Paper 1 English Medium

Question 42.
(a) Prove that tan 70° – tan 20° – 2 tan 40° = 4 tan 10°?

[OR]

(b) In a ∆ABC, if a = 2\(\sqrt{3}\), b = 2\(\sqrt{2}\) and C = 75° find the other side and the angles?

Question 43.
(a) Use induction to prove that n3 – 7n + 3, is divisible by 3, for all natural numbers n?

[OR]

(b) Evaluate y = (x2 + 1) \(\sqrt [ 3 ]{ x^{ 2 }+2 } \)?

Tamil Nadu 12th Computer Science Model Question Paper 1 English Medium

Question 44.
(a) Show that f(x) f(y) = f(x + y), where f(x) = \(\left[\begin{array}{ccc}
\cos x & -\sin x & 0 \\
\sin x & \cos x & 0 \\
0 & 0 & 1
\end{array}\right]\)

[OR]

(b) The chances of X, Y and Z becoming managers of a certain company are 4 : 2 : 3. The probabilities that bonus scheme will be introduced if X, Y and Z become managers are 0.3, 0.5 and 0.4 respectively. 1f the bonus scheme has been introduced, what is the probability that Z was appointed as the manager?

Tamil Nadu 12th Computer Science Model Question Paper 1 English Medium

Question 45.
(a) If the equation λx2 – 10xy + 12y2 + 5x – 16y – 3 = O represents a pair of straight lines, find

  1. The value of λ and the separate equations of the lines
  2. Angle between the lines

[OR]

(b) Show that

  1. \(\lim _{n \rightarrow \infty} \frac{1+2+3+\ldots+n}{3 n^{2}+7 n+2}=\frac{1}{6}\)
  2. \(\lim _{n \rightarrow \infty} \frac{1^{2}+2^{2}+\ldots+(3 n)^{2}}{(1+2+\ldots+5 n)(2 n+3)}=\frac{9}{25}\)
  3. \(\lim _{n \rightarrow \infty} \frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\ldots .+\frac{1}{n(n+1)}=1\)

Tamil Nadu 12th Computer Science Model Question Paper 1 English Medium

Question 46.
(a) A man repays an amount of ₹3250 by paying ₹20 in the first month and then increases the payment by ₹15 per month. How long will it take him to clear the amount?

[OR]

(b) Find the area of the triangle whose vertices are A (3, -1, 2), B (1, -1, -3) and C (4, -3, 1)?

Tamil Nadu 12th Computer Science Model Question Paper 1 English Medium

Question 47.
(a) Evaluate (x + 1) \(\sqrt { 2x+3 } \)?
[OR]

(b) Evaluate ∫cosec2x dx?

Samacheer Kalvi 6th Social Science Guide Civics Term 2 Chapter 2 The Constitution of India

Students can download 6th Social Science Term 2 Civics Chapter 2 The Constitution of India Questions and Answers, Notes, Samacheer Kalvi 6th Social Science Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 6th Social Science Civics Solutions Term 2 Chapter 2 The Constitution of India

Samacheer Kalvi 6th Social Science The Constitution of India Text Book Back Questions and Answers

I. Choose the correct Answer

Question 1.
The Constitution Day is celebrated on ……………..
(a) January 26
(b) August 15
(c) November 26
(d) December 9
Answer:
(c) November 26

Question 2.
The Constituent Assembly accepted the Constitution of India in the year
(a) 1946
(b) 1950
(c) 1947
(d) 1949
Answer:
(d) 1950

Samacheer Kalvi 6th Social Science Guide Civics Term 2 Chapter 2 The Constitution of India

Question 3.
There are …………….. amendments made in the Constitution of India till 2016.
(a) 101
(b) 100
(c) 78
(d) 46
Answer:
(a) 101

Question 4.
Which of the following is not a fundamental right?
(a) Right to freedom
(b) Right to equality
(c) Right to vote
(d) Right to education
Answer:
(c) Right to vote

Question 5.
An Indian citizen has the right to vote at ……………..
(a) 14 years
(b) 18 years
(c) 16 years
(d) 21 years
Answer:
(b) 18 years

II. Fill in the blanks

  1. …………….. was selected as the chairman of the Constituent Assembly.
  2. The farther of the Constitution of India is ……………..
  3. …………….. protects our fundamental rights.
  4. The Constitution of India came into existence on ……………..

Answer:

  1. Mr. Rajendra Prasad
  2. Dr. B. R. Ambedkar
  3. Law of the country
  4. 26th January 1950

III. Match the following

Samacheer Kalvi 6th Social Science Guide Civics Term 2 Chapter 2 The Constitution of India
Answer:
b) c d a b

IV. Answer the question given under the caption (Constituent Assembly)

Question 1.
In which year was the Constituent Assembly formed?
Answer:
Constituent Assembly was formed in the year 1946.

Question 2.
How many members were in the Drafting Committee?
Answer:
There are eight members in the Drafting Committee.

Samacheer Kalvi 6th Social Science Guide Civics Term 2 Chapter 2 The Constitution of India

Question 3.
How many women were part of the Constituent Assembly?
Answer:
There were fifteen women participants in the constituent Assembly.

Question 4.
When was the Constitution of India completed?
Answer:
The Constitution of India was completed on 26th November 1949.

V. Answer the following questions

Question 1.
Why was January 26 adopted as Republic day?
Answer:

  1. When the Congress met at Lahore in 1929, the members of the Congress unofficially declared the same day as the Day of Pooma Swaraj or the Day of complete self-governance.
  2. The next year, 26th January 1930 was celebrated as Independence Day. That day has been observed as our Republic Day.

Question 2.
What is the Constitution of India?
Answer:

  1. The constitution of India is the ultimate law.
  2. We have to abide by it.
  3. It explains the fundamental concepts of structure, methods, powers, and duties of Government bodies.
  4. It also lists the fundamental rights and duties of the citizens.
  5. Directive Principles are also mentioned in the constitution.
  6. So it is holistic in nature.

Question 3.
List out the special features of the Constitution of India.
Answer:

  1. The preface of the constitution is the Preamble.
  2. According to it, India is a Sovereign, Socialist, Secular democratic republic.
  3. The constitution has granted people the right to rule. Sovereignty refers to the ultimate power of the country.
  4. The term secular refers to the freedom of worship.
  5. The Constitution provides a Parliamentary form of Government, both at the center

Samacheer Kalvi 6th Social Science Guide Civics Term 2 Chapter 2 The Constitution of India

Question 4.
What are the fundamental rights?
Answer:
Fundamental rights are the basic human rights of all citizens. They are

  • Right to Equality
  • Right to Freedom
  • Right against exploitation
  • Right to freedom of Religion
  • Cultural and Educational Rights
  • Right to Constitutional Remedies.

Question 5.
List out the fundamental duties that you would like to fulfill.
Answer:

  1. Respecting the National flag and National Anthem.
  2. Respect and protect the Constitution.
  3. Readiness to serve our country if the need arises.
  4. Treating everyone as brothers and sister
  5. Avoid violence.
  6. Protect government property etc.

Question 6.
What is Preamble?
Answer:

  1. The Preamble of our constitution stresses justice, liberty, equality, and fraternity.
  2. The preface of the constitution is the preamble. According to it, India is a sovereign, socialists, secular democratic republic.

Samacheer Kalvi 6th Social Science Guide Civics Term 2 Chapter 2 The Constitution of India

Question 7.
What do you understand by Liberty, Equality, and Fraternity?
Answer:

  1. The preamble of the Indian constitution clearly says that
  2. To achieve Justice-social, economic and political
  3. Liberty of thought, expression, belief, faith, and worship.
  4. Equality of status and opportunity.
  5. Fraternity assuring the dignity of the individual and the unity and integrity of the nation.

Question 8.
Define: Sovereign
Answer:

  1. The Constitution of India has granted the people the right to vote.
  2. The members of the Parliament and the Legislative Assembly are elected by the people.
  3. The right to decide is only in the hands of the representatives.
  4. Sovereignty refers to the ultimate power of the country.
  5. Sovereignty refers to India as an independent country.
  6. India is not subject to any external power of influence.

VI. Projects and Activities

Question 1.
Let the students work individually or in a group to prepare rules for their class. From them discuss and form a list of rules and regulations for their class.
Answer:

  1. Listen to the teacher
  2. Respect each other
  3. Respect other people’s property
  4. Listen to others
  5. Take care of our equipment

Question 2.
List your duties at
(a) School
(b) Home and
(c) Society
Answer:
(a) At School:

  1. Participate in learning opportunities
  2. Attend school regularly on time

(b) at Home:

  1. Honour your father and mother
  2. Simple hygiene – brush teeth, wash and dry hands, and brush hair.

c) At Society:

  1. Teach the illiterate to read and write.
  2. Take an active role in literacy campaigns

Question 3.
Discuss these topics:

  1. Equality
  2. Child labour
  3. Right to Education

Answer:

  1. Equality means equal rights for all the people and the abolition of all special rights and privileges.
  2. Child labour refers to the employment of children in any work that deprives the children of their childhood.
  3. The right to education is a fundamental human right. Every individual irrespective of race, gender, social origin, religion, or age are entitled to free elementary education.

Samacheer Kalvi 6th Social Science Guide Civics Term 2 Chapter 2 The Constitution of India

Question 4.
Kailash Satyarti (India) and Malala Yusufsai (Pakistan) have been awarded the Nobel Prize for Peace (2014) Find out the reason why?
Answer:
“For their struggle against the suppression of children and young people and for the right of all children to education.

VII. Life Skill

Question 1.
Which of the fundamental rights do you like the most? Why?
Answer:
Fundamental rights and duties are guaranteed by the constitution. Look at the picture and share your opinions. Right against Exploitation. Traffic in Human beings and all forms of forced labour are prohibited.

Question 2.
Fundamental rights and duties are guaranteed by the constitution. Look at the picture and share your opinions. (For Students)
Answer:
Samacheer Kalvi 6th Social Science Guide Civics Term 2 Chapter 2 The Constitution of India

Samacheer Kalvi 6th Social Science The Constitution of India Additional Important Questions and Answers

I. Fill in the blanks Answer

  1. The Constitutions of nearly …………….. countries have been adopted by our Constitution.
  2. …………….. refers to the ultimate power of the country.
  3. …………….. is collectively responsible to the legislature.
  4. The chief architect of the Drafting Committee was
  5. The Constitution of India provides a …………….. form of government both at the centre and the state.

Answer:

  1. 60
  2. Sovereignty
  3. Executive
  4. Dr. B. R. Ambedkar
  5. Parliamentary

II. Answer the following questions

Question 1.
What is the Universal Adult Franchise?
Answer:
Universal Adult Franchise is every Indian citizen’s right to vote when they attain 18 years of age.

Question 2.
What are the Directive Principles?
Answer:
Directive Principles are certain guidelines to be followed while the government frame law.

Samacheer Kalvi 6th Social Science Guide Civics Term 2 Chapter 2 The Constitution of India

Question 3.
What is Democracy?
Answer:
Democracy is a type of government in which representatives are elected by the people of that country.

Question 4.
What is Secular?
Answer:
Secular is a state which does not discriminate against anyone on a religious ground.

III. Mind map

Samacheer Kalvi 6th Social Science Guide Civics Term 2 Chapter 2 The Constitution of India