{"id":910,"date":"2023-10-22T05:14:59","date_gmt":"2023-10-21T23:44:59","guid":{"rendered":"https:\/\/tnboardsolutions.com\/?p=910"},"modified":"2023-11-10T14:48:28","modified_gmt":"2023-11-10T09:18:28","slug":"samacheer-kalvi-6th-maths-guide-term-2-chapter-2-ex-2-1","status":"publish","type":"post","link":"https:\/\/tnboardsolutions.com\/samacheer-kalvi-6th-maths-guide-term-2-chapter-2-ex-2-1\/","title":{"rendered":"Samacheer Kalvi 6th Maths Guide Term 2 Chapter 2 Measurements Ex 2.1"},"content":{"rendered":"

Students can download Maths Chapter 2 Measurements Ex 2.1 Questions and Answers, Notes, Samacheer Kalvi 6th Maths Guide<\/a>\u00a0Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.<\/p>\n

Tamilnadu Samacheer Kalvi 6th Maths Solutions Term 2 Chapter 2 Measurements Ex 2.1<\/h2>\n

Question 1.
\nFill in the blanks.
\n(i) 250 ml + \\(\\frac{1}{2}\\) ml = _____ l.
\n(ii) 150 kg 200 g + 55 kg 750 g = ____ kg ____ g.
\n(iii) 20 l – 1 l 500 ml = ____ l ___ ml
\n(iv) 450 ml \u00d7 5 = ____ l ____ ml.
\n(v) 50 Kg \u00f7 100 g = ______
\nSolution:
\n(i) \\(\\frac{3}{4}\\) l
\n(ii) 205 kg 950 g
\n(iii) 18 l 500 ml
\n(iv) 2l 250 ml
\n(v) 500<\/p>\n

\"Samacheer<\/p>\n

Question 2.
\nTrue or False.
\n(i) Pugazhenthi ate 100 g of nuts which is equal to 0.1 kg.
\n(ii) Meena bought 250 ml of buttermilk which is equal to 2.5 l.
\n(iii) Karkuzhali’s bag 1 kg 250 g and Poongkodi’s bag 2 kg 750 g. The total weight of their bags 4 kg.
\n(iv) Vanmathi bought 4 books each weighing 500 g. Total weight of 4 books is 2 kg.
\n(v) Gayathri bought 1 kg of birthday cake. She shared 450 g with her friends. The weight of cake remaining is 650 g.
\nSolution:
\n(i) True
\n(ii) False
\n(iii) True
\n(iv) True
\n(v) False<\/p>\n

\"Samacheer<\/p>\n

Question 3.
\nConvert into indicated units:
\n(i) 10 l and 50 ml into ml
\n(ii) 4 km and 300 m into m
\n(iii) 300 mg into g
\nSolution:
\n(i) 10 l and 50 ml
\n= 10 \u00d7 1000 ml + 50 ml
\n= (10000 + 50)ml
\n= 10050 ml<\/p>\n

(ii) 4 km and 300 m
\n= 4 \u00d7 1000 + 300 m
\n= (4000 + 300) m
\n= 4300 m<\/p>\n

(iii) 300 mg
\n= \\(\\frac{300}{1000}\\)g
\n= 0.3 g<\/p>\n

\"Samacheer<\/p>\n

Question 4.
\nConvert into higher units:
\n(i) 13000 mm
\n(km, m, cm)
\nSolution:
\n13000 mm
\n= \\(\\frac{13000}{10}\\) cm
\n= 1300 cm
\n= \\(\\frac{13000}{1000}\\) m = 13000 mm
\n= 13 m
\n= \\(\\frac{13000}{1000000}\\) km = 13000 mm
\n= 0.013 km<\/p>\n

(ii) 8257 ml (kl, l)
\nSolution:
\n8257 ml
\n= \\(\\frac{8257}{1000}\\) l
\n= 8.257 l
\n= 8257 ml
\n= \\(\\frac{8257}{1000000}\\) kl
\n= 0.008257 kl<\/p>\n

\"Samacheer<\/p>\n

Question 5.
\nConvert into lower units:
\n(i) 15 km (m, cm, mm)
\n(ii) 12 kg (g, mg)
\nSolution:
\n(i) 15 km = 15 \u00d7 1000 m = 15000 m
\n15 km = 15 \u00d7 100000 cm
\n= 1500000 cm
\n15 km = 15 \u00d7 1000000 mm
\n= 15000000 mm<\/p>\n

(ii) 12 kg (g, mg)
\nSolution:
\n12 kg = 12 \u00d7 1000 g
\n= 12000 g
\n12 kg = 12 \u00d7 1000000 mg
\n= 12000000 mg<\/p>\n

Question 6.
\nCompare and put > or < or = in the following:
\n(i) 800 g + 150 g ____ 1 kg
\n(ii) 600 ml + 400 ml ____ 1 l
\n(iii) 6 m 25 cm ____ 600 cm + 25 cm
\n(iv) 88 cm ____ 8 m 8 cm
\n(v) 55 g ____ 550 mg
\nSolution:
\n(i) 800 g + 150g < 3kg
\n(ii) 600 ml + 400 ml = 1 l
\n(iii) 6 m 25 cm = 600 cm + 25 cm
\n(iv) 88 cm < 8 m 8 cm
\n(v) 55 g > 550 mg<\/p>\n

\"Samacheer<\/p>\n

Question 7.
\nGeetha brought 2 l and 250 ml of water in a bottle. Her friend drank 300 ml from it. How much of water is remaining in the bottle?
\nSolution:
\nQuantity of water Geetha brought = 2 l 250 ml
\n= 2 \u00d7 1000 + 250 ml
\n= 2000 + 250 ml
\n= 2,250 ml.
\nQuantity of water her friend drank = 300 ml
\nRemaining water = 2250 – 300 = 1950 ml. = 1 litre 950 ml.
\nRemaining water = 1 litre 950 ml.<\/p>\n

Question 8.
\nThenmozhi\u2019s height is 1.25 m now she grows 5 cm every year. What would be her height after 6 years?
\nSolution:
\nThenmozhi\u2019s present height = 1.25 m
\nRate of growth per year = 5 cm
\nHer growth in 6 years = 5 cm \u00d7 6 = 30 cm.
\nAfter 6 years her height = 1.25 m + 30 cm
\n= 1.25 \u00d7 100 + 30 cm
\n= 125 + 30 cm
\n= 155 cm.
\n\u2234 After 6 years Thenmozhi\u2019s height will be 155 cm.<\/p>\n

\"Samacheer<\/p>\n

Question 9.
\nPriya bought 22\\(\\frac { 1 }{ 2 }\\) kg of onion, Krishna bought 18\\(\\frac { 3 }{ 4 }\\) kg of onion and Sethu bought 9 kg 250 g of onion. What is the total weight of onion did they buy?
\nSolution:
\nPriya\u2019s weight = 22 kg 500 g
\nKrishna\u2019s weight = 18 kg 750 g
\nSethu\u2019s weight = 9 kg 250 g
\nTotal weight = 49 kg 1500 g = 49 kg + 1 kg 500 g = 50 kg + 500 g.
\nTheir total weight = 50 kg 500 g.<\/p>\n

Question 10.
\nMaran walks 1.5 km every day to reach the school while Mahizhan walks 1400 m. Who walks more distance and by how much?
\nSolution:
\nDistance which Maran walks = 1.5 km = 1.5 \u00d7 1000 m = 1500 m
\nThe distance which Mahizhan walks = 1400 m.
\nHere 1500 > 1400
\n\u2234 Difference = 1500 – 1400 = 100 m.
\n\u2234 Maran walks more distance = 100 m.<\/p>\n

\"Samacheer<\/p>\n

Question 11.
\nIn a JRC one day camp, 150 gm of rice and 15 ml oil are needed for a student. If there are 40 students to attend the camp how much rice and oil are needed?
\nSolution:
\nRice needed for one student = 150 g
\nRice needed for 40 students = 150 g \u00d7 40 = 6000 g. = \\(\\frac{6000}{1000}\\) kg = 6 kg.
\nOil needed for one student = 15 ml
\nOil needed for 40 students = 15 ml \u00d7 40 = 600 ml. = \\(\\frac{600}{1000}\\) l = 0.6 l
\n\u2234 For the camp 6 kg of rice and 0.6 l of oil needed.<\/p>\n

Question 12.
\nIn a school, 200 litres of lemon juice is prepared. If 250 ml lemon juice is given to each student, how many students get the juice?
\nSolution:
\nTotal lemon juice prepared = 200 l = 200 \u00d7 1000 ml = 2,00,000 ml.
\n\u2234 Quantity of Lemon juice given to one student = 250 ml.
\n\u2234 Number of students can get = \\(\\frac{2,00,000}{250}\\) = 800
\n\u2234 800 students can get the lemon juice.<\/p>\n

\"Samacheer<\/p>\n

Question 13.
\nHow many glasses of the given capacity will fill a 2 litre jug?
\n(i) 100 ml ___
\n(ii) 50 ml ____
\n(iii) 500 ml ____
\n(iv) 1 l ____
\n(v) 250 ml ____
\nSolution:
\n2 litre = 2 \u00d7 1000 ml = 2000 ml.
\n(i) 100 ml
\n\\(\\frac{2000}{100}=20\\)
\n20 glasses of 100 ml.
\n(ii) 50 ml
\n\\(\\frac{2000}{50}=40\\)
\n40 glasses of 50 ml
\n(iii) 500 ml
\n\\(\\frac{2000}{500}=4\\)
\n4 glasses of 500 ml
\n(iv) 1 l
\n\\(\\frac{2 l}{1 l}=2\\)
\n2 glasses of 1 l.
\n(v) 250 ml
\n\\(\\frac{2000}{250}=8\\)
\n8 glasses of 250 ml can fill the jug.<\/p>\n

Objective Type Questions<\/span><\/p>\n

Question 14.
\n9 m 4 cm is equal to ……..
\n(i) 94 cm
\n(ii) 904 cm
\n(iii) 9.4 cm
\n(iv) 0.94 cm
\nSolution:
\n(ii) 904 cm<\/p>\n

\"Samacheer<\/p>\n

Question 15.
\n1006 g is equal to ____
\n(a) 1 kg 6 g
\n(b) 10 kg 6 g
\n(c) 100 kg 6 g
\n(d) 1 kg 600 g
\nSolution:
\n(a) 1 kg 6 g<\/p>\n

Question 16.
\nEvery day 150 l of water is sprayed in the garden. Water sprayed in a week is ……
\n(i) 700 l
\n(ii) 1000 l
\n(iii) 950 l
\n(iv) 1050 l
\nSolution:
\n(iv) 1050 l<\/p>\n

Question 17.
\nWhich is the greatest 0.007 g, 70 mg, 0.07 cg?
\n(a) 0.07 cg
\n(b) 0.007 g
\n(c) 70 mg
\n(d) all are equal
\nSolution:
\n(d) all are equal<\/p>\n

\"Samacheer<\/p>\n

Question 18.
\n7 km – 4200 m is equal to ……….
\n(i) 3 km 800 m
\n(ii) 2 km 800 m
\n(iii) 3 km 200 m
\n(iv) 2 km 200 m
\nSolution:
\n(ii) 2 km 800 m<\/p>\n","protected":false},"excerpt":{"rendered":"

Students can download Maths Chapter 2 Measurements Ex 2.1 Questions and Answers, Notes, Samacheer Kalvi 6th Maths Guide\u00a0Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams. Tamilnadu Samacheer Kalvi 6th Maths Solutions Term 2 Chapter 2 Measurements Ex 2.1 …<\/p>\n","protected":false},"author":3,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[4],"tags":[],"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/tnboardsolutions.com\/wp-json\/wp\/v2\/posts\/910"}],"collection":[{"href":"https:\/\/tnboardsolutions.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/tnboardsolutions.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/tnboardsolutions.com\/wp-json\/wp\/v2\/users\/3"}],"replies":[{"embeddable":true,"href":"https:\/\/tnboardsolutions.com\/wp-json\/wp\/v2\/comments?post=910"}],"version-history":[{"count":1,"href":"https:\/\/tnboardsolutions.com\/wp-json\/wp\/v2\/posts\/910\/revisions"}],"predecessor-version":[{"id":43531,"href":"https:\/\/tnboardsolutions.com\/wp-json\/wp\/v2\/posts\/910\/revisions\/43531"}],"wp:attachment":[{"href":"https:\/\/tnboardsolutions.com\/wp-json\/wp\/v2\/media?parent=910"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/tnboardsolutions.com\/wp-json\/wp\/v2\/categories?post=910"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/tnboardsolutions.com\/wp-json\/wp\/v2\/tags?post=910"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}