{"id":2838,"date":"2020-06-03T10:27:57","date_gmt":"2020-06-03T10:27:57","guid":{"rendered":"https:\/\/tnboardsolutions.com\/?p=2838"},"modified":"2021-07-08T03:27:41","modified_gmt":"2021-07-08T08:57:41","slug":"tamil-nadu-11th-maths-model-question-paper-4-english-medium","status":"publish","type":"post","link":"https:\/\/tnboardsolutions.com\/tamil-nadu-11th-maths-model-question-paper-4-english-medium\/","title":{"rendered":"Tamil Nadu 11th Maths Model Question Paper 4 English Medium"},"content":{"rendered":"

Students can Download Tamil Nadu 11th Maths Model Question Paper 4 English Medium Pdf, Tamil Nadu 11th Maths Model Question Papers<\/a> helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.<\/p>\n

TN State Board 11th Maths Model Question Paper 4 English Medium<\/h2>\n

General Instructions:<\/p>\n

    \n
  1. The question paper comprises of four parts<\/span>.<\/li>\n
  2. You are to attempt all the parts. An internal choice of questions is provided wherever applicable.<\/li>\n
  3. All questions of Part I, II, III and IV are to be attempted separately.<\/li>\n
  4. Question numbers 1<\/span> to 20<\/span> in Part I<\/span> are Multiple Choice Questions of one mark<\/span> each.
    \nThese are to be answered by choosing the most suitable answer from the given four alternatives and writing the option code and the corresponding answer<\/li>\n
  5. Question numbers 21<\/span> to 30<\/span> in Part II<\/span> are two-mark<\/span> questions. These are to be answered in about one or two sentences.<\/li>\n
  6. Question numbers 31<\/span> to 40<\/span> in Part III<\/span> are three-mark<\/span> questions. These are to be answered in above three to five short sentences.<\/li>\n
  7. Question numbers 41<\/span> to 47<\/span> in Part IV<\/span> are five-mark<\/span> questions. These are to be answered in detail Draw diagrams wherever necessary.<\/li>\n<\/ol>\n

    Time: 2:30 Hours
    \nMaximum Marks: 90<\/p>\n

    PART – I<\/span><\/p>\n

    I. Choose the correct answer. Answer all the questions: [20 \u00d7 1 = 20]<\/span><\/p>\n

    Question 1.
    \nIf n(A) = 2 and n(B\u222aC) = 3 then n[(A \u00d7 B) \u222a (A \u00d7 C)] is ………………..
    \n(a) 23<\/sup>
    \n(b) 32<\/sup>
    \n(c) 6
    \n(d) 5
    \nAnswer:
    \n(c) 6<\/p>\n

    \"Tamil<\/p>\n

    Question 2.
    \nFor any two sets A and B, A\u2229(A\u222aB) = …………………….
    \n(a) B
    \n(b) \u2205
    \n(c) A
    \n(d) none of these
    \nAnswer:
    \n(c) A<\/p>\n

    Question 3.
    \ncos 1\u00b0 + cos 2\u00b0 + cos 3\u00b0 + cos 4\u00b0 + cos 179\u00b0 = …………………
    \n(a) 0
    \n(b) 1
    \n(c) -1
    \n(d) 89
    \nAnswer:
    \n(a) 0<\/p>\n

    \"Tamil<\/p>\n

    Question 4.
    \nThe value of log9<\/sub> 27 is ……………………
    \n(a) \\(\\frac{2}{3}\\)
    \n(b) \\(\\frac{3}{2}\\)
    \n(c) \\(\\frac{3}{4}\\)
    \n(d) \\(\\frac{4}{3}\\)
    \nAnswer:
    \n(b) \\(\\frac{3}{2}\\)<\/p>\n

    Question 5.
    \nThe value of \\(\\frac{\\sin 3 \\theta+\\sin 5 \\theta+\\sin 7 \\theta+\\sin 9 \\theta}{\\cos 3 \\theta+\\cos 5 \\theta+\\cos 7 \\theta+\\cos 9 \\theta}\\) = ………………..
    \n(a) tan3\u03b8
    \n(b) tan6\u03b8
    \n(c) cot3\u03b8
    \n(d) cot6\u03b8
    \nAnswer:
    \n(b) tan6\u03b8<\/p>\n

    Question 6.
    \nIn 3 fingers the number of ways 4 rings can be worn in ……………………. ways.
    \n(a) 43 – 1
    \n(b) 34
    \n(c) 68
    \n(d) 64
    \nAnswer:
    \n(d) 64<\/p>\n

    \"Tamil<\/p>\n

    Question 7.
    \nEverybody in a room shakes hands with everybody else. The total number of shake hands is 66. The number of persons in the room is ……………….
    \n(a) 11
    \n(b) 12
    \n(c) 10
    \n(d) 6
    \nAnswer:
    \n(b) 12<\/p>\n

    Question 8.
    \nThe H.M of two positive number whose AM and G.M. are 16, 8 respectively is ………………..
    \n(a) 10
    \n(b) 6
    \n(c) 5
    \n(d) 4
    \nAnswer:
    \n(d) 4<\/p>\n

    \"Tamil<\/p>\n

    Question 9.
    \nThe co-efficient of the term independent of x in the expansion of (2x+\\(\\frac{1}{3x}\\))6<\/sup> is …………………
    \n(a) \\(\\frac{160}{27}\\)
    \n(b) \\(\\frac{160}{27}\\)
    \n(c) \\(\\frac{80}{3}\\)
    \n(d) \\(\\frac{80}{9}\\)
    \nAnswer:
    \n(a) \\(\\frac{160}{27}\\)<\/p>\n

    Question 10.
    \nThe value of \\(\\left|\\begin{array}{lll}
    \na & 0 & 0 \\\\
    \n0 & b & 0 \\\\
    \n0 & 0 & c
    \n\\end{array}\\right|^{2}\\) is ………………..
    \n(a) abc
    \n(b) -abc
    \n(c) 0
    \n(d) a2<\/sup>b2<\/sup>c2<\/sup>
    \nAnswer:
    \n(d) a2<\/sup>b2<\/sup>c2<\/sup><\/p>\n

    \"Tamil<\/p>\n

    Question 11.
    \nThe value of x for which the matrix A = \\(\\left[\\begin{array}{cc}
    \ne^{x-2} & e^{7+x} \\\\
    \ne^{2+x} & e^{2 x+3}
    \n\\end{array}\\right]\\) is singular is …………………..
    \n(a) 9
    \n(b) 8
    \n(c) 7
    \n(d) 6
    \nAnswer:
    \n(b) 8<\/p>\n

    Question 12.
    \nIf |\\(\\vec { a } \\) + \\(\\vec { b } \\)| = 60, |\\(\\vec { a } \\) – \\(\\vec { b } \\)| = 40 and |\\(\\vec { b } \\)| = 46 then |\\(\\vec { a } \\)| is …………………
    \n(a) 42
    \n(b) 12
    \n(c) 22
    \n(d) 32
    \nAnswer:
    \n(c) 22<\/p>\n

    \"Tamil<\/p>\n

    Question 13.
    \nGiven \\(\\vec { a } \\) = 2\\(\\vec { i } \\) + \\(\\vec { j } \\) – 8\\(\\vec { k } \\) and \\(\\vec { b } \\) = \\(\\vec { i } \\) + 3\\(\\vec { j } \\) – 4\\(\\vec { k } \\) then |\\(\\vec { a } \\) + \\(\\vec { b } \\)| = ………………….
    \n(a) 13
    \n(b) \\(\\frac{13}{3}\\)
    \n(c) \\(\\frac{4}{13}\\)
    \n(d) \\(\\frac{3}{13}\\)
    \nAnswer:
    \n(a) 13<\/p>\n

    Question 14.
    \nIf f(x) = \\(\\left\\{\\begin{array}{ccc}
    \nk x & \\text { for } & x \\leq 2 \\\\
    \n3 & \\text { for } & 2
    \n\\end{array}\\right.\\)\u00a0is continous at x = 2 then the value of k is ……………………
    \n(a) \\(\\frac{3}{4}\\)
    \n(b) 0
    \n(c) 1
    \n(d) \\(\\frac{4}{3}\\)
    \nAnswer:
    \n(c) 1<\/p>\n

    \"Tamil<\/p>\n

    Question 15.
    \nIf f: R\u2192R is defined by f(x) = |x – 3| + |x – 4| for x\u2208R then \\(\\lim _{x \\rightarrow 3^{-}}\\) f(x) is equal to ………………..
    \n(a) -2
    \n(b) -1
    \n(c) 0
    \n(d) 1
    \nAnswer:
    \n(c) 0<\/p>\n

    Question 16.
    \n\\(\\lim _{x \\rightarrow \\infty}\\left(\\frac{x^{2}+5 x+3}{x^{2}+x+3}\\right)^{x}\\) is ………………..
    \n(a) e4<\/sup>
    \n(b) e2<\/sup>
    \n(c) e3<\/sup>
    \n(d) 1
    \nAnswer:
    \n(a) e4<\/sup><\/p>\n

    \"Tamil<\/p>\n

    Question 17.
    \n\\(\\int \\frac{e^{x}\\left(x^{2} \\tan ^{-1} x+\\tan ^{-1} x+1\\right)}{x^{2}+1}\\) dx is ………………..
    \n(a) e tan-1<\/sup>(x + 1)
    \n(b) tan-1<\/sup>(ex<\/sup>) + c
    \n(c) ex<\/sup> \\(\\frac{\\left(\\tan ^{-1} x\\right)^{2}}{2}\\) + c
    \n(d) ex<\/sup>tan-1<\/sup>x + c
    \nAnswer:
    \n(d) ex<\/sup>tan-1<\/sup>x + c<\/p>\n

    Question 18.
    \n\u222b \\(\\frac { secx }{ \\sqrt { cos2x } } \\) dx = …………………..
    \n(a) tan-1<\/sup>(sin x) + c
    \n(b) 2 sin-1<\/sup>(tan x) + c
    \n(c) tan-1<\/sup>(cos x) + c
    \n(d) sin-1<\/sup> (tan x) + c
    \nAnswer:
    \n(d) sin-1<\/sup> (tan x) + c<\/p>\n

    \"Tamil<\/p>\n

    Question 19.
    \n\\(\\int \\frac{e^{6 \\log x}-e^{5 \\log x}}{e^{4 \\log x}-e^{3 \\log x}}\\) dx = ………………..
    \n(a) x + c
    \n(b) \\(\\frac { x^{ 3 } }{ 3 } \\) + c
    \n(c) \\(\\frac { 3 }{ x^{ 3 } } \\) + c
    \n(d) \\(\\frac { 1 }{ x^{ 2 } } \\) + c
    \nAnswer:
    \n(b) \\(\\frac { x^{ 3 } }{ 3 } \\) + c<\/p>\n

    Question 20.
    \nIt is given that the events A and B are such that P(A) = \\(\\frac{1}{4}\\), P(A\/B) = \\(\\frac{1}{2}\\), P(B\/A) = \\(\\frac{2}{3}\\) then P(B) = …………………
    \n(a) \\(\\frac{1}{6}\\)
    \n(b) \\(\\frac{1}{3}\\)
    \n(c) \\(\\frac{2}{3}\\)
    \n(d) \\(\\frac{1}{2}\\)
    \nAnswer:
    \n(b) \\(\\frac{1}{3}\\)<\/p>\n

    PART – II<\/span><\/p>\n

    II. Answer any seven questions. Question No. 30 is compulsory. [7 \u00d7 2 = 14]<\/span><\/p>\n

    Question 21.
    \nIn the set Z of integers, define mRn if m – n is a multiple of 12. Prove that R is an equivalence relation?
    \nAnswer:
    \nAs m – m = 0 and 0 = 0 \u00d7 12, we have 0 is a multiple of 12; hence mRm proving that R is reflexive.
    \nLet mRn. Then m – n = 12k for some integer k; thus n – m = 12(-k) and hence nRm.
    \nThis shows that R is symmetric.
    \nLet mRn and nRp: then m – n = 12k and n – p = 12l for some integers k and l.
    \nSo m – p = 12(k + l) and hence mRp. This shows that R is transitive.
    \nThus R is an equivalence relation.<\/p>\n

    \"Tamil<\/p>\n

    Question 22.
    \nSimplify:
    \n\\(\\frac { 1 }{ 2+\\sqrt { 3 } } \\) + \\(\\frac { 3 }{ 4-\\sqrt { 5 } } \\) + \\(\\frac { 6 }{ 7-\\sqrt { 8 } } \\)
    \nAnswer:
    \n\"Tamil<\/p>\n

    Question 23.
    \nFind the value of sin 22 \\(\\frac{1}{2}\\)\u00b0?
    \nAnswer:
    \nWe know that cos \u03b8 = 1 – 2 sin2<\/sup> \\(\\frac{\u03b8}{2}\\) \u21d2 sin \\(\\frac{\u03b8}{2}\\) = \u00b1\\(\\sqrt { \\frac { 1-cos2\\theta }{ 2 } } \\)
    \nTake \u03b8 = 45\u00b0, we get sin \\(\\frac{45\u00b0}{2}\\) = \u00b1\\(\\sqrt { \\frac { 1-cos45\u00b0}{ 2 } } \\), (taking positive sign only, since 22\\(\\frac{1}{2}\\)\u00b0 lies in the first quadrant)
    \nThus, sin 22\\(\\frac{1}{2}\\)\u00b0 = \\(\\sqrt{\\frac{1-\\frac{1}{\\sqrt{2}}}{2}}=\\frac{\\sqrt{2-\\sqrt{2}}}{2}\\).<\/p>\n

    \"Tamil<\/p>\n

    Question 24.
    \nThe number of bacteria in a certain culture doubles every hour. If there were 30 bacteria present in the culture originally, how many bacteria will be present at the end of 2nd hour, 4th
    \nhour and wth hour?
    \nAnswer:
    \nNo. of bacteria at the beginning = 30
    \nNo. of bacteria after 1 hour = 30 \u00d7 2 = 60
    \nNo. of bactena after 2 hours = 30 \u00d7 22<\/sup> = 30 \u00d7 4 = 120
    \nNo. of bacteria after 4 hours = 30 \u00d7 24<\/sup> = 30 \u00d7 16 = 480
    \nNo. of bacteria after nth<\/sup> hour = 30 \u00d7 2n<\/sup><\/p>\n

    \"Tamil<\/p>\n

    Question 25.
    \nIf the sum of the distance of a moving point in a plane from the axis is 1, then find the locus of the point?
    \nAnswer:
    \nLet coordinates of a moving point P be (x, y).
    \nGiven that the sum of the distances from the axis to the point is always 1.
    \n\u2234|x| + |y| = 1 \u21d2 x + y = 1
    \n\u21d2- x- y = 1 \u21d2 x + y = 1
    \n\u21d2 x – y = 1
    \nHence, these equations give us the locus of the point P which is a square.
    \n\"Tamil<\/p>\n

    Question 26.
    \nIf (a, a + b, a + b + c) is one set of direction ratios of the line joining (1, 0, 0) and (0, 1, 0) then find a set of values of a, b, c?
    \nAnswer:
    \nLet A be the point (1, 0, 0) and B be the point (0, 1, 0) (i.e.,) \\(\\overline { OA } \\) = \\(\\hat { i } \\) and \\(\\overline { OB } \\) = \\(\\hat { j } \\).
    \nThen \\(\\overline { AB } \\) = \\(\\overline { OB } \\) – \\(\\overline { OA } \\) = \\(\\hat { j } \\) – \\(\\hat { i } \\) = –\\(\\hat { i } \\) + \\(\\hat { j } \\)
    \n= (-1, 1, 0)
    \n= (a, a + b, a + b + c)
    \n\u21d2 a = -1, a + b = 1 and a + b + c = 0
    \n\u21d2 a = -1, \u21d2 -1 + b = 1; a + b + c = 0
    \n\u21d2 b = 2; -1 + 2 + c = 0 \u21d2 c + 1 = 0
    \n\u21d2 c = -1
    \n\u2234 a = -1, b = 2, c = -1.
    \nNote: if we taken \\(\\overline { BA } \\) then we get a = 1, b = -2 and c = 1.<\/p>\n

    \"Tamil<\/p>\n

    Question 27.
    \nFind \\(\\frac{dy}{dx}\\) for y = (x2<\/sup> + 4x + 6)5<\/sup>
    \nAnswer:
    \nLet u = x2<\/sup> + 4x + 6
    \n\u21d2 \\(\\frac{du}{dx}\\) = 2x + 4
    \nNow y = u5<\/sup> = \\(\\frac{dy}{du}\\) = 5u4<\/sup>
    \n\u2234 \\(\\frac{dy}{dx}\\) = \\(\\frac{dy}{du}\\) \u00d7 \\(\\frac{du}{dx}\\) = 5u4<\/sup> (2x + 4)
    \n= 5(x2<\/sup> + 4x + 6)4<\/sup> (2x + 4)
    \n= 5(2x + 4) (x2<\/sup> + 4x + 6)4<\/sup><\/p>\n

    Question 28.
    \nEvaluate \u222b\\(\\sqrt { 25x^{ 2 }-9 } \\) dx?
    \nAnswer:
    \n\"Tamil<\/p>\n

    Question 29.
    \nA bag contains 5 white and 7 black balls. 3 balls are drawn at random. Find the probability that<\/p>\n

      \n
    1. all are white<\/li>\n
    2. one white and 2 black.<\/li>\n<\/ol>\n

      Answer:
      \nNumber of white balls = 5
      \nNumber of black balls = 7
      \nTotal number of balls = 12
      \nSelecting 3 from 12 balls can be done in
      \n12<\/sup>C3<\/sub> = \\(\\frac{12 \\times 11 \\times 10}{3 \\times 2 \\times 1}\\) = 220 ways
      \n\u2234n(S) = 220<\/p>\n

      1. Let A be the selecting 3 white balls.
      \n\u2234n(A) = 5<\/sup>C3<\/sub> = 5<\/sup>C2<\/sub> = \\(\\frac{5\u00d73}{2\u00d71}\\) = 10
      \n\u2234P(A) = \\(\\frac{n(A)}{n(S)}\\) = \\(\\frac{10}{220}\\) = \\(\\frac{1}{22}\\)<\/p>\n

      2. Let B be the event of selecting one white and 2 black balls.
      \n\u2234n(B) = 5<\/sup>C1<\/sub> \u00d7 7<\/sup>C2<\/sub> = (5) (\\(\\frac{7\u00d76}{2\u00d71}\\)) = 5(21) = 105
      \n\u2234P(B) = \\(\\frac{n(B)}{n(S)}\\) = \\(\\frac{105}{220}\\) = \\(\\frac{21}{44}\\).<\/p>\n

      \"Tamil<\/p>\n

      Question 30.
      \nIf (k, 2), (2, 4) and (3, 2) are vertices of the triangle of area 4 square units then determine the value of k?
      \nAnswer:
      \nArea of \u2206 with vertices (k, 2) (2, 4) and (3, 2) = \\(\\frac{1}{2}\\) \\(\\left|\\begin{array}{lll}
      \nk & 2 & 1 \\\\
      \n2 & 4 & 1 \\\\
      \n3 & 2 & 1
      \n\\end{array}\\right|\\) = 4 given
      \n\u21d2 \\(\\left|\\begin{array}{lll}
      \nk & 2 & 1 \\\\
      \n2 & 4 & 1 \\\\
      \n3 & 2 & 1
      \n\\end{array}\\right|\\) = 2(4) = 8
      \n(i.e.,) k(4 – 2) – 2(2 – 3) + 1(4 – 12) \u00b1 8
      \n(i.e.,) 2k – 2(-1) + 1(-8) = \u00b1 8
      \n(i.e.,) 2k + 2 – 8 = 8
      \n(i.e.,) 2k = 8 + 8 – 2 = 14
      \nk = 14\/2 = 7
      \n\u2234k = 7
      \nSo k = 7 (or) k = -1.<\/p>\n

      2k + 2 – 8 = -8
      \n\u21d22k = – 8 + 8 – 2
      \n2k = – 2
      \nk = -1<\/p>\n

      PART – III<\/span><\/p>\n

      III. Answer any seven questions. Question No. 40 is compulsory. [7 \u00d7 3 = 21]<\/span><\/p>\n

      Question 31.
      \nIn the set Z of integers define mRn if m – n is a multiple of 12. Prove that R is an equivalence relation?<\/p>\n

      Question 32.
      \nProve that \\(\\frac{sin4x+sin2x}{cos4x+cos2x}\\) = tan 3x?<\/p>\n

      \"Tamil<\/p>\n

      Question 33.
      \nA polygon has 90 diagonals. Find the number of its sides?<\/p>\n

      Question 34.
      \nIf n is an odd positive integer, prove that the coefficients of the middle terms in the expansion of (x + y)n<\/sup> are equal?<\/p>\n

      Question 35.
      \nFind the equation of the line passing through the point (1, 5) and also divides the co-ordinate axes in the ratio 3 : 10?<\/p>\n

      \"Tamil<\/p>\n

      Question 36.
      \nProve that \\(\\left|\\begin{array}{ccc}
      \n1 & x & x \\\\
      \nx & 1 & x \\\\
      \nx & x & 1
      \n\\end{array}\\right|^{2}=\\left|\\begin{array}{ccc}
      \n1-2 x^{2} & -x^{2} & -x^{2} \\\\
      \n-x^{2} & -1 & x^{2}-2 x \\\\
      \n-x^{2} & x^{2}-2 x & -1
      \n\\end{array}\\right|\\)<\/p>\n

      Question 37.
      \nIf G is the centroid of a traiangle ABC prove that \\(\\overline { GA } \\) + \\(\\overline { GB } \\) + \\(\\overline { GC } \\) = 0<\/p>\n

      \"Tamil<\/p>\n

      Question 38.
      \nFind \\(\\frac{dy}{dx}\\) for y = \\(\\sqrt { 1+tan2x } \\)?<\/p>\n

      Question 39.
      \nEvaluate \\(\\frac { \\sqrt { x } }{ 1+\\sqrt { x } } \\) dx?<\/p>\n

      Question 40.
      \nFind the relation between a and b if \\(\\underset { x\\rightarrow 3 }{ lim } \\) f(x) exists where f(x) = \\(\\left\\{\\begin{array}{cc}
      \na x+b & \\text { if } x>3 \\\\
      \n3 a x-4 b+1 \\text { if } x<3
      \n\\end{array}\\right.\\)<\/p>\n

      PART – IV<\/span><\/p>\n

      IV. Answer all the questions. [7 \u00d7 5 = 35]<\/span><\/p>\n

      Question 41 (a).
      \nFrom the curve y = |x|, draw(i) y = |x-1| + 1<\/p>\n

        \n
      1. y = |x + 1| + 1<\/li>\n
      2. y = |x + 2| – 3<\/li>\n<\/ol>\n

        [OR]<\/p>\n

        (b) Resolve into partial fraction \\(\\frac { x+4 }{ (x^{ 2 }-4)(x+1) } \\)<\/p>\n

        \"Tamil<\/p>\n

        Question 42 (a).
        \nFind the number of positive integers greater than 6000 and less than 7000 which arc divisible by 5, provided that no digit is to be repeated?<\/p>\n

        [OR]<\/p>\n

        (b) If n<\/sup>Pr<\/sub> = n<\/sup>Pr+1<\/sub> and n<\/sup>Cr<\/sub> = n<\/sup>Cr-1<\/sub>, find the values of n and r?<\/p>\n

        Question 43 (a).
        \nIn a \u2206ABC, prove that b2<\/sup> sin 2C + c2<\/sup> sin 2B = 2bc sin A?<\/p>\n

        [OR]<\/p>\n

        (b) Differentiate the following s(t) = \\(\\sqrt[4]{\\frac{t^{3}+1}{t^{3}-1}}\\)?<\/p>\n

        \"Tamil<\/p>\n

        Question 44 (a).
        \nFind the equation of the lines make an angle 60\u00b0 with the positive x axis and at a distance 5\\(\\sqrt{2}\\) units measured from the point (4, 7) along the line x – y + 3 = 0<\/p>\n

        [OR]<\/p>\n

        (b) If y = A cos4x + B sin 4x, A and B are constants then Show that y2<\/sub> + 16y = 0<\/p>\n

        \"Tamil<\/p>\n

        Question 45 (a).
        \nFind the sum up to the 17th<\/sup> term of the series \\(\\frac{1^{3}}{1}+\\frac{1^{3}+2^{3}}{1+3}+\\frac{1^{3}+2^{3}+3^{3}}{1+3+5}\\) + …………..<\/p>\n

        [OR]<\/p>\n

        (b) A shopkeeper in a Nuts and Spices shop makes gifi packs of cashew nuts, raisins and almonds?<\/p>\n

          \n
        1. Pack I contains 100 gm of cashew nuts, 100 gm of raisins and 50 gm of almonds.<\/li>\n
        2. Pack-II contains 200 gm of cashew nuts, 100 gm of raisins and 100 gm of almonds.<\/li>\n
        3. Pack-III contains 250 gm of cashew nuts, 250 gm of raisins and 150 gm of almonds.<\/li>\n
        4. The cost of 50 gm of cashew nuts is \u20b950, 50 gm of raisins is \u20b910. and 50gm of almonds is \u20b960. What is the cost of each gift pack?<\/li>\n<\/ol>\n

          \"Tamil<\/p>\n

          Question 46 (a).
          \nFind matrix C if A = \\(\\begin{bmatrix} 3 & 7 \\\\ 2 & 5 \\end{bmatrix}\\), B = \\(\\begin{bmatrix} -3 & 2 \\\\ 4 & -1 \\end{bmatrix}\\) and 5C + 28= A?<\/p>\n

          [OR]<\/p>\n

          (b) The probability that a new railway bridge will get an award for its design is 0.48, the probability that it will get an award for the efficient use of materials is 0.36, and that it will get both awards is 0.2. What is the probability, that<\/p>\n

            \n
          1. it will get at least one of the two awards<\/li>\n
          2. it will get only one of the awards.<\/li>\n<\/ol>\n

            \"Tamil<\/p>\n

            Question 47 (a).
            \n\\(\\underset { \\alpha \\rightarrow 0 }{ lim } \\) \\(\\frac { sin(\\alpha ^{ n }) }{ (sin\\alpha )^{ m } } \\)<\/p>\n

            [OR]<\/p>\n

            (b) Evaluate I = sin-1<\/sup> (\\(\\frac { 2x }{ (1+x)^{ 2 } } \\)) dx?<\/p>\n","protected":false},"excerpt":{"rendered":"

            Students can Download Tamil Nadu 11th Maths Model Question Paper 4 English Medium Pdf, Tamil Nadu 11th Maths Model Question Papers helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams. TN State Board 11th Maths Model Question Paper 4 English …<\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[6],"tags":[],"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/tnboardsolutions.com\/wp-json\/wp\/v2\/posts\/2838"}],"collection":[{"href":"https:\/\/tnboardsolutions.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/tnboardsolutions.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/tnboardsolutions.com\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/tnboardsolutions.com\/wp-json\/wp\/v2\/comments?post=2838"}],"version-history":[{"count":0,"href":"https:\/\/tnboardsolutions.com\/wp-json\/wp\/v2\/posts\/2838\/revisions"}],"wp:attachment":[{"href":"https:\/\/tnboardsolutions.com\/wp-json\/wp\/v2\/media?parent=2838"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/tnboardsolutions.com\/wp-json\/wp\/v2\/categories?post=2838"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/tnboardsolutions.com\/wp-json\/wp\/v2\/tags?post=2838"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}